similar to: selecting characters from a line of text

Is there a simple way in R to remove all characters from a string other than those in a specified set? For example, I want to keep only the digits 0-9 in a string. In general, I have found the string handling abilities of R a bit limited. (Of course it's great for stats in general). Is there a good reference on this? Or should R programmers dump their output to a text file and use something

Hi all, I have a numeric vector with 1 decimal place, and I'd like to extract the last 3 characters, including the decimal point. The vector ranges from 0 to 20. x <- round(runif(100)*20, digits=1) Some of numbers have 3 characters, and some have 4. I've read up on the substr() function but that extracts characters based on exact positions. How can I extract just the last 3

Hi, i have a vector filled with names: [1] Alvaro Adela ... [25] Beatriz Berta ... ... [100000] ... I would like to drop last character in every name. I use the next program: for (i in 1:100000) { ? ? ? ? ? ? ? ? ? ? ? ? ? largo <- nchar(names[i]-1) ? ? ? ? ? ? ? ? ? ? ? ? ? names[i] <- substring (names[i],1,largo] ? ? ? ? ? ? ? ? ? ? ? ? ?} Is another and faster way of do it? Thanks,

Hi I have this problem where I need to find if there is any numbers in a string, this is no problem if theres only one number per string. I would then simply use the regexpr() funtion togheter with the substring function to extract the number. But regexpr only picks one number per string either from the beginning or the end, but not multiple. Can this be done? And how for example My string <-

Dear R users, The best in this new year 2011. I am dealing with a character vector (xx) whose nchar are not the same. Ex. nchar(xx) [1] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 [38] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 3 3 3 3 3 4 4 4 4 4 4 4 4 [75] 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 ....... 9 I need xx to be nchar = 9 My

Hello, I am running into issues using *_path() and *_url() helpers the Facebooker Publisher framework. I encounter the following error when using these helpers while *inside of a partial*: undefined method `default_url_options'' for ActionView::Base:Class I''ve seen a few other people speak about this issue, yet I haven''t seen any resolution on the mailing list yet.

Dear R wizards: sorry to bug everyone twice in one day. I would like to annotate my graph by putting text strings into rectangle boxes with a little cartoon-like bubble with a lid pointing to a specific location. I can draw some sort of bubble-with-lid using the R primitives. (has anyone done something like this already?) the problem where I am stuck is that the width of the rectangle must

Hello together, i have a question for "substring". I know i can filter a number like this one: bill$No<-substring(bill$Customer,2,4) in this case i get the 2nd, 3rd and 4th number of my Customer ID. But how can i do this, if i want the 2nd, 3rd and 4th number of a column. Like this one. I have: Mercedes_02352 Audi_03555 and now i want to filter this data.frame to 235 355 can you

Hi all, Does anybody know the easiest way to import excel data into R? I copied and pasted the excel data into a txt file, and tried read.table, but R reported that Error in read.table("data_support.txt", sep = " ", header = T) : more columns than column names Thanks! Ling

Hi, (First, apology for my earlier incorrectly addressed "subscribe" post.) Can somebody tell me what exactly is going on below. Basically, I am running into some kind of "string truncation" problem when I try to get a substring starting past the 8192nd character (see sample session below). There doesn't appear to be any problem creating the string, and nchar()

[R 1.7.1 on Windows XP Pro] Since R allows missing values for character variables, why are NA's not propagated by character manipulation functions? For example: > temp <- c("a", NA) > temp [1] "a" NA > is.na(temp) [1] FALSE TRUE > paste(temp[1], temp[2]) [1] "a NA" > substr(temp, 1, 1) [1] "a" "N" >

Hello all, Frustrated and i know you can help I need to drop the last numeral of each of my values in my data set. So for the following i have tried the ?substring but since i have to specify the length, but because my data are of varying lengths it doenst work so well Data<-c("1131", "1132", "1731" ,"1732" ,"1821" ,"1822",

Dear R Experts, I have a vector of dates in character format like this: date "2000-01-01" "2000-01-23" "2001-03-12" ... ... ... "2009-12-31" I would like to delete the last part of the character string (i.e. the "day" part), so the vector looks like this: date "2000-01" "2000-01" "2001-03" ... ... ...

Hi, I am trying to create the assignment function: "substring<-" <- function(text, first, last=100000, sub) { if(is.character(first)) { if(!missing(last)) stop('wrong # arguments') return(sedit(text, first, sub)) } lf <- length(first) if(length(text)==1 && lf > 1) { if(missing(last)) last <- nchar(text) last <- rep(last,

Dear all, I just want to determine if the characters in a character string are the same or not. For example, temp <- c("aa", "aA", "ab") How do I determine the first one have the two same ?a?, and the second and third have the different characters? Thanks in advance. Lisa -- View this message in context:

Dear R users, I have a dataframe with one character field, and I would like to create two new fields (columns) in my dataset, by spliting the existing character field into two using an existing substring. ... something that in SAS I could solve e.g. combining substr(which I am aware exist in R) and "index" for determining the position of the pattern within the string. e.g. if my

Hello R users, I have a little problem with a for loop. Below there is an simple example of my problem. I want to delet the commas in the character string. Fore this reason I create a for loop to unpick the string and rebuild him without the commas. The problem is, that "paste" does not work in the loop as I expected. text <- "aaa,bbb,ccc,ddd" characterseq <-

Is there a wine option to send the log output to a file? I'm doing the following: wineconsole --debugmsg +all program_name parm1 parm2 parm3 > /mylog.txt mylog.txt is not receiving a copy of the millions, nay billions!, of messages output. I'm using Redhat 7.3 and the 10/07/2002 RPMs. - Bill

Have created sample sinatra cucumber app as suggested on wiki. Tried both env.rb configurations from there and aslaks git repo. With this combination of gems I get the following error doing basic cuc tests When I visit ''/foo'' # features/step_definitions/general.rb:1 PATH_INFO must start with / (Rack::Lint::LintError)

Can anyone help me with this error I am having. I am using puppet on Debian Etch, version 0.20.1-1 from apt works OK, but due to one or two problems we want to use the version from testing, 0.23.2-10, but the puppetd just fails upon startup spitting this out: Starting puppet configuration management tool/usr/lib/ruby/1.8/timeout.rb:54:in `open'': execution expired (Timeout::Error)