Displaying 20 results from an estimated 3000 matches similar to: "Rearranging Capture History Data in R"
2008 Jun 13
2
Quartile regression question
I have data that looks like
lake,loglength,logweight
1,2.369215857,1.929418926
1,2.426511261,2.230448921
1,2.434568904,2.298853076
1,2.437750563,2.298853076
1,2.442479769,2.230448921
1,2.445604203,2.356025857
...
102,2.722633923,3.310268367
102,2.781755375,3.502153893
102,2.836324116,3.683407299
102,2.802773725,3.583312152
102,2.790285164,3.546419267
102,2.806179974,3.599118565
2010 Aug 23
2
Quantile Regression and Goodness of Fit
All -
Does anyone know if there is a method to calculate a goodness-of-fit
statistic for quantile regressions with package quantreg?
Specifically, I'm wondering if anyone has implemented the
goodness-of-fit process developed by Koenker and Machado (1999) for R?
Though I have used package quantreg in the past, I may have overlooked
this function, if it is included.
Citation:
Koenker, R. and
2008 Aug 22
2
Newbie programming help
All - 
Not sure if this is a real programming question, but here goes:
I have data that looks like
Lake	Length	Weight
1	158	45
1	179	70
1	200	125
1	202	150
1	206	145
1	209	165
1	210	140
1	215	175
1	216	152
1	220	150
1	221	165
...
where lake goes from 1 - 84 and the number of rows for each lake is variable (but > ~20).  
I'm trying to do two things: 1) build a simple linear model of the
2008 Aug 19
1
Histogram binning
I am trying to produce frequencies in defined intervals however I can't seem
to figure out how to get R to bin my data the way I want it to.
 
I have several thousand lengths of fish that I want to be binned as follows:
 
Ex.
 
Length      Bin
 
209         200
219         210
431         430
727         720
 
That is, bins with any length equal to or greater than the lower
2008 Jun 10
3
newbie nls question
I'm tyring to fit a relatively simple nls model to some data, but keep coming up against the same error (code follows):
Oto=nls(Otolith ~ Linf*(1-exp(-k(AGE-to))), 
    data = ages, 
    start = list(Linf=1000, k=0.1, to=0.1), 
    trace = TRUE) 
The error message I keep getting is "Error in eval(expr, envir, enclos) : could not find function "k"".  I've used this
2008 Dec 18
2
Contextstack overlow
All - 
I have a number of rows that I am assigning length classes to via
l.class<-with(wae,
  ifelse((Length>=120)&(Length<130),"125",
  ifelse((Length>=130)&(Length<140),"135",
  ifelse((Length>=140)&(Length<150),"145",
  ifelse((Length>=150)&(Length<160),"155",
 
2008 Jun 12
2
Predicting from an nls model
I keep running up against the same error when I try to plot a line from a nls model.  The data is fisheries length/weight data.  Code follows:
require(graphics)
pow = nls(Weight~alpha*Length^beta, data=wae,
      start=list(alpha=0.0000001, beta=3.0), trace=TRUE)                             
predict(pow)                                                                        
plot(Weight~Length,
2008 Jul 03
1
lm() question
I have data that looks like
YC      Age	Num
82	11	2
83	10	0
84	9	8
85	8	21
86	7	49
87	6	18
88	5	79
89	4	28
90	3	273
91	2	175
with a program 
mod1=lm(log(Num+1)~YC, data=box44) 
plot(log(Num+1)~YC, data=box44, pch=19, xlab="Year Class",
    ylab="Loge Number at age", ylim=c(0,6), xlim=c(91,82))
abline(lm(log(Num+1)~YC), col="blue", lwd=2)
summary(mod1)
I need to
2008 Sep 02
2
nls.control()
All - 
I have data:
TL	age
388	4
418	4
438	4
428	5
539	10
432	4
444	7
421	4
438	4
419	4
463	6
423	4
...
[truncated]
and I'm trying to fit a simple Von Bertalanffy growth curve with program:
#Creates a Von Bertalanffy growth model
VonB=nls(TL~Linf*(1-exp(-k*(age-t0))), data=box5.4,
    start=list(Linf=1000, k=0.1, t0=0.1), trace=TRUE)
#Scatterplot of the data
plot(TL~age, data=box5.4,
2008 Oct 24
4
gfortran optimization problems
Colleagues,
I have a routine in package labdsv that calls a FORTRAN subroutine. 
Recently, I was informed that it sometimes gives different results on a 
PC and Mac, and that the PC version is clearly wrong.  I tested it on 
linux (because I don't have a PC), and I get the same (incorrect) 
behavior as the PC.
Simply by inserting debug WRITE statements in the FORTRAN I would get 
different,
2008 Aug 29
1
lm() and dffits
All -
My question is a bit involved, so bear with me.
I have some data that looks like:
Lake	LL	LW
81	2.176091259	1.342422681
81	2.176091259	1.414973348
81	2.176091259	1.447158031
81	2.181843588	1.414973348
81	2.181843588	1.447158031
81	2.184691431	1.462397998
81	2.187520721	1.447158031
81	2.187520721	1.477121255
81	2.187520721	1.505149978
...
[truncated]
I'm trying to:
1) fit a simple
2010 Mar 26
1
Trouble loading package
I am trying to load a package called Rmark, but when I run 
library(Rmark)
I get the following:
> library(RMark)
Error in !character.only : invalid argument type
Error in library(RMark) : .First.lib failed for 'RMark'
When I try to load Rmark from the packages menu, I get:
> local({pkg <- select.list(sort(.packages(all.available = TRUE)))
+ if(nchar(pkg)) library(pkg,
2003 Feb 07
2
Data manipulation
I am interested in building a model with a subset of data from a column.
The first 6 lines of my data look like this:
    QUAD YEAR SITE TREAT HERB TILL PLANT SEED Kweed 
1     A4 2002    s     1    N    N     N    N 55.00   
2    A10 2002    s     1    N    N     N    N 60.00   
3     B2 2002    s     1    N    N     N    N 35.00  
4     C2 2002    s     1    N    N     N    N 23.00   
5     C9
2008 Jul 03
1
lines() warning message
I have data that looks like
Year,Recruit,Spawner,Mtempcv
1958,4532,775,0.24125
1959,22996,2310,0.16319
1960,628,2990,0.46056
1961,879,1400,0.33028
1962,14747,1130,0.22618
1963,13205,790,0.20596
1964,31793,1195,0.19229
1965,10621,981,0.20363
1966,22271,870,0.3452
1967,8736,1104,0.27511
1968,8761,883,0.10884
1969,18885,1421,0.17799
1970,10098,1198,0.2106
1971,3394,760,0.22098
1972,1697,1354,0.39461
2005 Jun 13
3
To many NA's from mean(..., na.rm=T) when a column is all NA's
Dear R-help folks,
I am seeing unexpected behaviour from the function mean
with option na.rm =TRUE (which is removing a whole column of a data frame
or matrix.
example:
testcase <- data.frame( x = 1:3, y = rep(NA,3))
mean(testcase[,1], na.rm=TRUE)
[1] 2
mean(testcase[,2], na.rm = TRUE)
[1] NaN
  OK, so far that seems sensible.  Now I'd like to compute both means at
once:
 
2008 Aug 01
1
Confidence intervals with nls()
I have data that looks like
O.lengthO.age
176	1
179	1
182	1
...
493	5
494	5
514	5
606	5
462	6
491	6
537	6
553	6
432	7
522	7
625	8
661	8
687	10
704	10
615	12
(truncated)
with a simple VonB growth model from within nls():
plot(O.length~O.age, data=OS)
Oto = nls(O.length~Linf*(1-exp(-k*(O.age-t0))), data=OS,
      start=list(Linf=1000, k=0.1, t0=0.1), trace=TRUE)
      mod <- seq(0, 12)        
2005 Jul 19
1
deriv - accessing numeric output listed under gradient attribute
Hi,
I am interested in using the numeric output from the "gradient" attribute of 
deriv's output in subsequent analyses.
But, I have so far been unable to determine how to do so.
I will use the example from the deriv help to illustrate.
> ## function with defaulted arguments:
>    (fx <- deriv(y ~ b0 + b1 * 2^(-x/th), c("b0", "b1", "th"),
    
2005 Nov 30
8
Solving Systems of Non-linear equations
I am trying to write a function that will solve a simple system of 
nonlinear equations for the parameters that describe the beta 
distribution (a,b) given the mean and variance.
mean = a/(a+b)
variance = (a*b)/(((a+b)^2) * (a+b+1))
Any help as to where to start would be welcome.
-- 
Scott Story
Graduate Student
MSU Ecology Department
319 Lewis Hall
Bozeman, Mt 59717
406.994.2670
sstory at
2006 Sep 08
4
Any Rails Developers in Montana?
Any Rails Developers in Montana? Especially Helena or Bozeman?
I don''t expect there''s enough of us to form a user group, but it might
be nice to talk shop ''offline'' every once and a while.
Eric
(in Helena)
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1999 Oct 25
1
Linking to html help from outside R
Dear R-help-ers
   (Currently running Version 0.65.1 Release (October 07, 1999) on Solaris
     2.6)
  My problem has to do with updates of the R language.  When I install a
new version, I would like to just change one directive, or a soft link to
the current doc/html/ directory, to update a bookmark I have pointing to 
the current R doumentation directory.  I've tried building a soft link: