similar to: evaluating variables in the context of a data frame

I ran into an interesting issue with `evalq` (and also `eval(quote(...))`): ???? f <- function() { ?????? list( ???????? sys.parent(1), ???????? evalq(sys.parent(1)), ???????? evalq((function() sys.parent(2))()),? # add an anon fun layer ???????? evalq((function() sys.parent(1))()) ?????? ) ???? } ???? res <- f() ???? str(res) ???? ## List of 4 ???? ##? $ : int 0???????? # sys.parent(1)

I'm still going over old emails and trying to get my head around evaluation so I'm persistent if nothing else. A while back , an expert sent me below as an exercise in understanding and I only got around to it tonight. I understand some of the output but not all of it and I put "Why not Zero ?" next to the ones that I don't understand based on my reading of the various

On Fri, Mar 13, 2009 at 6:09 PM, Bill Wendling <isanbard at gmail.com> wrote: > On Fri, Mar 13, 2009 at 4:41 PM, Zack Weinberg <zackw at panix.com> wrote: >> I'm trying to persuade llvm (svn trunk) to build in a mode where it >> *runs on* amd64 but *generates code* for alpha, exclusively. ... >>  - The "natural" way to do that (by which I mean

https://bugs.freedesktop.org/show_bug.cgi?id=32855 Summary: Incorrect image stretching with Render in RepeatPad mode, NV50 Product: xorg Version: git Platform: x86-64 (AMD64) OS/Version: Linux (All) Status: NEW Severity: normal Priority: medium Component: Driver/nouveau

https://bugs.freedesktop.org/show_bug.cgi?id=91705 Bug ID: 91705 Summary: [NVE7] GPU crash (read fault) on boot w/ DMI+HDMI outputs Product: xorg Version: unspecified Hardware: x86-64 (AMD64) OS: Linux (All) Status: NEW Severity: normal Priority: medium Component:

On Jul 15, 2015, at 12:51 PM, William Dunlap wrote: > I think rapply() was changed to act like lapply() in this respect. > When I looked at the source of the difference, it was that typeof() returned 'language' in 3.2.1, while it returned 'list' in the earlier version of R. The first check in rapply's code in both version was: if (typeof(object) != "list")

David, If you are referring to the solution that would be: rapply(list(test), eval, envir = fenv) I thought I explained in the question that the above code does not work. It does not throw an error, but the behavior is no different (at least in the output or result). Using the above code still results in the x object not being stored in fenv on 3.1.2. Dayne On Wed, Jul 15, 2015 at 4:40 PM,

In 3.1.2 eval does not store the result of the bquote-generated call in the given environment. Interestingly, in 3.2.1 eval does store the result of the bquote-generated call in the given environment. In other words if I run the given example with eval rather than evalq, on 3.1.2 "x" is never stored in "fenv," but it is when I run the same code on 3.2.1. However, the given

On 01/04/2015 1:35 PM, Gabriel Becker wrote: > Joris, > > > The second argument to evalq is envir, so that line says, roughly, "call > environment() to generate me a new environment within the environment > defined by data". I think that's not quite right. environment() returns the current environment, it doesn't create a new one. It is evalq() that created

The help page of eval says: The 'evalq' form is equivalent to 'eval(quote(expr), ...)'. But the following is not equivalent. Can anyone give me some explaination? Thanks very much. > f1 <- function(x,digits=5) lapply(x, f2) > f2 <- function(x) eval(quote(print(x+1,digits=digits)),list(x=x),parent.frame(2)) > f1(list(x1=1)) [1] 2 $x1 [1] 2 > > f1 <-

On 01/04/2015 2:33 PM, Joris Meys wrote: > Thank you for the insights. I understood as much from the code, but I > can't really see how this can cause a problem when using with() or > within() within a package or a function. The environments behave like > I would expect, as does the evaluation of the arguments. The second > argument is supposed to be an expression, so I

Hello, I upgraded from 3.1.2 to 3.2.1 and am receiving errors on code that worked as I intended previously. Briefly, I am using bquote to generate expressions to modify data.table objects within a function, so I need the changes to actually be stored in the given environment. Previously, I used code like the following: test <- list(bquote(x <- 10)) fenv <- environment() rapply(test,

Hi, In order to avoid deep copies by passing large arguments to functions or returning values, I'm trying to do the assignment of variables in a given environment. The problem is when I try to assign a structure: a list for example. If I have: ind <- c("a","b") my idea is doing something like l <- alist() l[ind] <- as.list(c(20,40)) in a given

I'm trying to persuade llvm (svn trunk) to build in a mode where it *runs on* amd64 but *generates code* for alpha, exclusively. (Well, technically, generate code for my experimental architecture simulator that happens to be based on alpha.) I have been unable to find any combination of configure switches that makes this happen. I should probably underline that I am _not_ trying to

This is an expanded version of the question I tried to ask last night - I thought I had it this morning, but it's still not working and I just do not understand what is going wrong. What I am trying to do is write a wrapper for lattice xyplot() that passes a whole bunch of its secondary arguments, so that I can produce similarly formatted graphs for several different data sets. This is what

Dear mailing list, I have found some strange behaviour which I think relates to parent frames and eval. Can anyone explain what's going on here? First example: > test.parent.funcs_ function() { outer.var_ 5 subfunc1_ function() substitute( outer.var, envir=parent.frame()) print( subfunc1()) subfunc2b_ function() eval( quote( outer.var), envir=parent.frame()) print(

Dear list members, I'm a bit confused about the evaluation of expressions using with() or within() versus subset() and transform(). I always teach my students to use with() and within() because of the warning mentioned in the helppages of subset() and transform(). Both functions use nonstandard evaluation and are to be used only interactively. I've never seen that warning on the help

Hi, When using evalq to evaluate expressions within a say data.frame context I often wish there was a 'subset' argument, much like in lm() or any ather advanced regression model. I would be grateful for a tip how to do this. Here is an illustration of what I want: n <- 100 data <- data.frame(x=rnorm(n), y=rnorm(y), z=rnorm(z)) # this works evalq({ i <- 0<x;

On Mon, Jan 26, 2015 at 12:24 PM, Hadley Wickham <h.wickham at gmail.com> wrote: > If it was any other environment than the global, you could use substitute: > > e <- new.env() > delayedAssign("foo", stop("Hey!"), assign.env = e) > substitute(foo, e) > > delayedAssign("foo", stop("Hey!")) > substitute(foo) Hmm... interesting

As you may not be surprised to hear, no sooner did I post the previous message than I realized I had a really dumb mistake. I've now gotten a bit farther but am still stuck. New code: graph <- function (x, data, groups, xlab) { pg <- function(x, y, group.number, ...) fnord body(pg) <- substitute({ panel.xyplot(x, y, ..., group.number=group.number) panel.text(2,