similar to: search path question

If I have 100 objekts in a folder and I prefer not to load them manually I wonder how I do this in R if using a for-loop. I was thinking initially to do something like this: infiles <- dir(pattern=".RData") for(i in length(infiles)) { load(infiles[i]) paste("kalle", i, sep="") <- saveLoadReference } But the line

Eric's approach seems reasonable to me, and I agree that it's probably not the use of a "for" loop that makes the original version slow. As Eric mentioned, there are lots of unnecessary things happening in the loop. For example, list.files() was called twice inside the loop, which is unnecessary, and will definitely slow the loop down (though probably not by much). Call it

Dear R-help As a novice to R I was seeking some advice with respect to using R to help solve a problem I have. I have a large number of infiles that need analysed. This can be done, I believe, using 2 separate R packages (popgen and ape) with the output from 'popgen' being used as input for 'ape'. What I would like to know is whether it is possible within R to write some

Am Freitag, 24. November 2006 03:00 schrieb Reid Spencer: > If you're making your own front end, you probably won't need it :) Well, I wanted to play around with it, so see, how my older programs perform with it. So far I managed to get some programs running by folowing scheme: for src in $infiles; do llvm-gcc -o $src.bc -c $src ; opt -f -o $src.bc.opt $src.bc ; llc -f $src.bc.opt

Hi all R users, I want to create a matrix having n columns and 2^n rows, and all its entries are only 0 or 1. In each row, column i is 0 means dimension i is chosen, 0 means not. The matrix will contains all the possible combination of those n dimensions. Here is an example, if n = 3, the matrix will look like: 0 0 0 0 0 1 0 1 0 1 0 0 0 1 1 1 0 1 1 1 1 I know I can use n "for" loops

Inspired by the functions that Barry Rawlingson and Dave Forrest posted for searching Rwiki and R-help archive, I've made up a function that does the search on Prof. Baron's site (Thanks to Prof. Baron's help on setting up the query string!): RSiteSearch <- function(string, restrict="Rhelp", format="long", sortby="score",

First, my site will be down December 27-28 because of a network upgrade at Penn. It will also be down at least one day before that, while I upgrade the operating system. (And another day some time in January because of a planned power outage.) Second, I have replaced the search engine in my R site: http://finzi.psych.upenn.edu/ I am now using Namazu instead of HtDig. The direct link to the

something like "sprintf" in C? so I can do: print(sprintf("the correct result is %3.4f\n", myresult)); ------- Also, I am desperately looking for a "clear console screen" function in R... thanks a lot! [[alternative HTML version deleted]]

Hi All: I have written an R search plug-in based on Prof Jonathan Baron's R search site. This Firefox/Netscape plug-in lets you search R sites and R discussion group archives directly from your Mozilla (Seamonkey) or Firefox or Netscape browser. Here is the link to the installer for the plug-in: http://arinbasu.bravehost.com/installer.html If you want the source files or have other comments

Hi R community, First of all, I want to thank everybody to share their time solving R questions, You are great. Ok, for my questions, I've been looking for a solutions by myself, in forums but I'm just a little bit desesperate so I hope somebody can help me. I have built a code to read files from a directory. These files are named by a year (2004.csv, 2005.csv,...). When the code reads

Hi Stephen, I am not sure that the "for loop" is the source of slowness. You seem to be doing a lot of unnecessary work each time through the loop. e.g. no need to check if it's the last file, just move that section outside of the loop. It will be executed when the loop finishes. As it is you are calling list.files() each time through the loop which could be slow. In any case

Hi, This question seems to be old, however I am asking it from a different point of view. R introduces itself as a 'statistical' language and environment. There are many discussions about comparing R to MATLAB or mathematica (or other similar software). It seems to me that these other software have a broader range of applications. For example, in Mathematica one can solve a partial

Dear colleagues, I am looking for a package to analyze rank-order data in the form of regression. My outcome (dependent) variable is a rank ordering in the sense that the respondents to a  questionnaire were asked a single question: to assign the values 1 to 4 to four different objects (e.g. to rank four cars as best , second best etc). Their first preference was number 1, their second was 

hello, i have a couple of .R files distributed about my file system. i commonly source() these from other files, but i have to include the full file path. this is not always convenient if you move files around. is there a way of setting the search path for source()? thanks a lot! cheers, andrew. -- Andrew B. Collier Space Physics Group Hermanus Magnetic Observatory Honorary Research Fellow

Is there a function in R for doing Greenhouse-Geiser correction in ANOVA models? Is it already available in the aov function? How do we use it? Best, Darren [[alternative HTML version deleted]]

Hello. Some months age an e-mail was posted in which a comparison between Glimmix and glm was discussed. I have not been able to find that e-mail on the R archive. Does anyone recall the date of the above e-mail? Thank you very much. ******************************************* Antonio Paredes USDA- Center for Veterinary Biologics Biometrics Unit 510 South 17th Street, Suite 104 Ames, IA 50010

Dear All, I have a following for-loop code which is basically intended to read in many excel files (each file has many columns and rows) in a directory and extract the some rows and columns out of each file and then combine them together into a dataframe. I use for loop which can do the work but quite slow. How to make it faster using lapply function ? Thanks in advance! temp.df<-c() #

Hi all I have a question regarding differences in the way gregpexr works in R 2.3.0 and R 2.4.0. In R 2.3.0, this is what happens: > gregexpr(" [a-z] [a-z] ", " a b c d e f ", perl=T) [[1]] [1] 1 3 5 7 9 attr(,"match.length") [1] 5 5 5 5 5 ... while in R 2.4.0, this is what happens: > gregexpr(" [a-z] [a-z] ", " a b c d e f ", perl=T)

Hi all I don't have idea how to write this script, please help I have thousand records in this format. eg: file No.3 is File No: 003 Customer: Ann Email address: xxx at info Country: England Created by: 20071102 file No. 4 is: File No: 004 Customer: James Email address: xxx at gov Country: Australia Created by: 20071105 I need to write a

Hello- It has been several years since anyone has asked, so i am asking again- has anyone created a routine to estimate confidence intervals for predictions from nls models (ala Bates and Watts 1988)? Thanks - Alice Shelly [[alternative HTML version deleted]]