similar to: optional fields in function declarations; Solved

Hi. I'm still facing troubles on my way. This time concerning ssl encryption. only dovecot-auth starts... imap and pop3 go down with this log dovecot: Mar 23 18:34:19 Info: Dovecot v1.0.rc27 starting up dovecot: Mar 23 18:34:20 Error: Temporary failure in creating login processes, slowing down for now dovecot: Mar 23 18:34:20 Error: imap-login: Can't load certificate file

I have to compare four different grape varieties proteome in two different years. I don't know what test would be more suitable for my data. I think that an anova two way can be usefull also if someone suggested me to perform a manova. In addiction, I can perform each test on a single protein a time, but I can't loose my whole life carrying out anova (I have more than 1000 protein to

I have to perform ANOVA's on many different data organized in a dataframe. I can run an ANOVA for each sample, but I've got hundreds of data and I would like to avoid manually carrying out each test. in addition, I would like to have the results organized in a simple way, for example in a table, wich could be easy to export. thank you for assistance simone

Hi. I'm still facing troubles on my way. This time concerning ssl encryption. only dovecot-auth starts... imap and pop3 go down with this log dovecot: Mar 23 18:34:19 Info: Dovecot v1.0.rc27 starting up dovecot: Mar 23 18:34:20 Error: Temporary failure in creating login processes, slowing down for now dovecot: Mar 23 18:34:20 Error: imap-login: Can't load certificate file

With version 8 of acrobat reader, it is now possible to have 3D in PDf documents. Does it exist already an R package who manage to produce 3D plots which can be saved as interactive 3D graphs in a PDF file? Best Regards Bruno Cavestro ------------------------------------------------------ Leggi GRATIS le tue mail con il telefonino i-mode? di Wind http://i-mode.wind.it/

Hi, I've noticed that if I disconnect or reconnect a phone from the net, Asterisk take long time to realize that (even more then 10 minutes). Is there a way to reduce this time, working on the configuration files? Thank you. silvia ------------------------------------------------------ Passa a Infostrada. ADSL e Telefono senza limiti e senza canone Telecom http://click.libero.it/infostrada

Thanks Adaikalavan, however the problem remains. Considering AIC() as applied to the linear model in AIC() help documentation: > data(swiss) > lm1 <- lm(Fertility ~ . , data = swiss) > AIC(lm1) [1] 326.0716 Clearly this includes the estimation of the residual standard error as an estimated parameter, as this gives the correct score: > -2*logLik(lm1) + 2*(length(coef(lm1))+1)

Dear all, I am having trouble trying to install R-1.8.1 on a Sun Solaris 8 (Generic_108528-23 version) machine. The configuration was successful but make check fails. I traced the the problem to the plot() function. > 1 + 1 [1] 2 > capabilities() jpeg png tcltk X11 GNOME libz http/ftp sockets TRUE FALSE TRUE TRUE FALSE TRUE TRUE TRUE

I have been struggling with this problem for a while and I hope someone could help me. Or if someone could point me to a section in the manual I would be grateful. x <- "my" plot(1:10, main=expression(paste( x, Delta, "values" ))) Q : How do I get the title to say "my (triangle symbol) values" ? The following trial-and-error produced mainly errors :

Hello everybody I'm very new at using R so probably this is a very stupid question. I have a matrix of "p" columns and I have to calculate for each of them the "two sample t-statistic" and p-value and to save the results into two different vectors. I have divided my matrix into two submatrices: submatrix A containing the first "n1" rows (p columns) and submatrix B

I really appreciate all the helpful answers from Richard Müller, Marc Schwartz, Adaikalavan Ramasamy, Vito Ricci. I tried Marc's simple suggestion which was to copy only the data area and paste to a new excel sheet, and that solved my problem. I'll try other suggestions while I'm learning more about R. Unedited answers are provided below followed by my question. Thanks again. Kyong

Hello, I need to extract sequences from an ordered vector. For example, if a<-c(1,2,3,6,10,11,13) I need to get the followings 4 vectors (1,2,3),(6),(10,11),(13) Thank You -Bruno ------------------------------------------------------ Leggi GRATIS le tue mail con il telefonino i-mode? di Wind http://i-mode.wind.it/

Hello my problem is the following: I have a matrix A and a vector B which contains as many rows as A. I need to build a matrix C which contains B[i]-times the row A[i,] and this for each line of A. if for example A is [1] [2] [1] 8 9.4 [2] 4.2 1.1 and B is (3,1). Then C will be: [1] [2] [1] 8 9.4 [2] 8 9.4 [3] 8 9.4 [4] 4.2 1.1 I have some

[In future, please press reply all as there might be others in the mailing list who can help you] Without a (short) reproducible example, it would be difficult to say. BTW, I think you have mistyped the error/warning message. Does it actually say "cannot compute _correct_ p-value" or "cannot compute _exact_ p-value". See example below. > wilcox.test( 1:3, 1:10 )

Dear Partecipants to the list, I am searching a R function, which can calculate the inverse of one real value function. Does it exists a R code in order to make it? Many thanks for any kind of help and for Your availability. Enrico Foscolo ------------------------------------------------------ Passa a Infostrada. ADSL e Telefono senza limiti e senza canone Telecom

Could some kindly tell me if I am supposed to be getting the same test statistic value with var.equal=TRUE and var.equal=FALSE in t.test ? set.seed(1066) x1 <- rnorm(50) x2 <- rnorm(50) t.test(x1, x2, var.equal=FALSE)$statistic # 0.5989774 t.test(x1, x2, var.equal=TRUE)$statistic # 0.5989774 ??? Here are my own calculations that shows that perhaps the result when var.equal=TRUE is

You are using a method that needs to estimate the covariance matrix of all the variables. If you have 80 variables, there are (80+1)*80/2 = 3240 variances and covariances to estimate. How many data points do you think you need to do that? Some people assume the covariance matrix is diagonal (i.e., assuming all the variables are uncorrelated). Even then you still have 80 variances to estimate.

I have functions using get.hist.quote() from library tseries. It seems that something changed (yahoo) and function get broken. try with a simple get.hist.quote('IBM') and let me kow if for someone it is still working. I get this error: Error in if (!quiet && dat[n] != start) cat(format(dat[n], "time series starts %Y-%m-%d\n")) : missing value where

Take a look at the manual page for "layout". The final example does pretty much what you're asking about (with a scatterplot and histograms, but the idea should be the same). Hope this helps, Matthew Wiener Applied Computer Science & Mathematics Dept. Merck Research Labs Rahway, NJ 07090 732-594-5303 -----Original Message----- From: Adaikalavan Ramasamy [mailto:ramasamy at

I worked this out over the weekend. I appreciate that using temporary variables would be simpler but I think this makes for quite readable code: # in RProfile.site inplace <- function (f, arg=1) eval.parent(call("<-",substitute(f)[[arg+1]], f),2) # examples in code inplace(foo[bar,baz] *2) # or inplace(paste(foo[bar,baz], 1:10)) # or inplace(sub("blah",