similar to: how to reduce in a grid ?

Hello! # I have 3 vectors of values: values1<-rnorm(10) values2<-rnorm(10) values3<-rnorm(10) # In real life, all 3 vectors have a length of 25 # I create all possible combinations of 4 based on 10 elements: mycombos<-expand.grid(1:10,1:10,1:10,1:10) dim(mycombos) # Removing rows that contain pairs of identical values in any 2 of these columns: mycombos<-mycombos[!(mycombos$Var1

Hi, I have one question on expand.grid() function. When I write following syntax :expand.grid(c("u", "l"), c("u", "l"), c("u", "l")) I get following as desired : Var1 Var2 Var3 1 u u u 2 l u u 3 u l u 4 l l u 5 u u l 6 l u l 7 u l l 8 l l l However

Dear all, I am using expand.grid for calculating all the possible values between four pairs. I would like to ask you if it is possible to filter the result out, so to keep all unique pairs. In my algorithm the input c(1,2) produces the same results as the c(2,1) so for example in the following code below > expand.grid(c(1,2,3),c(1,2,3))   Var1 Var2 1    1    1 2    2    1 3    3    1 4   

I have a Lattice plot in which I want to adjust the number of tick marks used, and I want to have the drawn grid reflect that change. Here is what I'm doing: bwplot(var1 ~ var2, data=df, scales=list(tick.number=10), panel=function(...) { panel.grid(h=0,v=-1,...); panel.stripplot(col="gray40", pch="|", cex=2, ...); panel.bwplot(...); })

Hello! I have a list of variable length. One example is: X=vector("list",3) X[[1]]=1:2 X[[2]]=1:2 X[[3]]=1:2 How could I run expand.grid on the elements of X so that the results would be the same as expand.grid(1:2,1:2,1:2)? Thank you! Dimitri -- Dimitri Liakhovitski gfk.com <http://marketfusionanalytics.com/> [[alternative HTML version deleted]]

Hello All: The function expand.grid() does nearly exactly what I want for permutation tests I wish to carry out, and it does so quickly when the number is kept small as in the example below: expand.grid(rep(list(c(-1, 1)), 3)) Var1 Var2 Var3 1 -1 -1 -1 2 1 -1 -1 3 -1 1 -1 4 1 1 -1 5 -1 -1 1 6 1 -1 1 7 -1 1 1 8 1 1 1 Understandably,

Hi, I am using R 1.9.1 on on i686 PC with SuSE Linux 9.0. I have a data.frame, e.g.: > myData <- data.frame( var1 = c( 1:4 ), var2 = c (5:8 ) ) If I add a new column by > myData$var3 <- myData[ , "var1" ] + myData[ , "var2" ] everything is fine, but if I omit the commas: > myData$var4 <- myData[ "var1" ] + myData[ "var2" ] the name

Dear List, I have Multi-level Data i= Indivitual Level g= Group Level var1= First Variable of interest var2= Second Variable of interest and I want to count the frequency of "var1" and "var2" on the group level. I found a way, but there must be a much simpler way. data.ml <- data.frame(i=c(1:8),g=as.factor(c(1,1,1,2,2,3,3,3)),var1=c(3,3,3,4,4,4,4 ,4),

Hi all, I have been trying to solve this problem and have had no luck so far. I have numeric vectors VAR1, VAR2, and VAR3 which I am trying to cbind. I also have a character vector "VAR1,VAR2,VAR3". How do I manipulate this character vector such that I can input a transformed version of the character vector into cbind and have it recognize that I'm trying to refer to my numeric

Buenos días. Hoy ando un poco (o bastante) espeso y no doy con la tecla de una cosa que seguro que es muy simple.. Pongo un ejemplo. var1 <- c(rep(0,3),rep(1,2)) var2 <- c(rep(1,2),0,0,1) var3 <- c(rep(1,2),rep(0,3)) var4 <- c(rep(1,2),rep(0,3)) datos <- data.frame(fila=1:5,var1, var2, var3, var4) datos datos fila var1 var2 var3 var4 1 1 0 1 1 1 2 2 0

I would like to know how to turn a variable into a string. I have tried as.symbol and as.name but it doesnt work for what I'd like to do Essentially, I'd like to feed the function below with two variables. This works fine in the bit working out number of elements in each variable. In the print(sprintf("OK with %s and %s\n", var1, var2)) line I would like var1 and var2 to be

Estimados Estoy entrenando hacer funciones que respondan a comandos, en esta caso en la salida gráfica se observa que dice : Exposure=var3 y outcome=var 1 quisiéramos que se reflejan los nombres de la base de datos : var1=estado, var2=cake, var3=chocolate Espero haberme explicado adecuadamente Adjunto tabla con datos #################################### #Comando que llama

I have a data frame whose first colum contains the names of the variables and whose second colum contains the values to assign to them: : kkk <- data.frame(vars=c("var1", "var2", "var3"), vals=c(10, 20, 30), stringsAsFactors=F) If I do : assign(kkk$vars[1], kkk$vals[1]) it works : var1 [1] 10 However, if I try with mapply

Can someone please give me a clue how to 're'write this so I dont need to use loops. a<-ts(matrix(c(1,1,1,10,10,10,20,20,20),nrow=3),names=c('var1','var2','var3')) b<-ts(matrix(c(2,2,2,11,11,11,21,21,21),nrow=3),names=c('var1','var2','var3'))

Hello, I would like to know if this behaviour in R is as expected. I have a data frame 'dat' with column var1 being character (and not factor). Then I create a new column 'var2' by: > dat[,"var2"] <- dat$var1; Column var2 is now a factor. But if I do: > dat$var2 <- dat$var1; Then column var2 is character (and not factor). I don't want to have

Buenas noches Javier y José, Estoy en contra de usar attach(), asi que propongo la siguiente alternativa con with(): # paquete require(epicalc) # los argumentos en ... pasan de epicalc:::cc # ver ?cc para mas informacion foo <- function(var1, var2, var3, ...){ or1 <- cc(var1, var2, ...) or2 <- cc(var1, var3, ...) list(or1 = or1, or2 = or2) } # datos x <-

Suppose I have a dataframe as follows: dat <- data.frame(id = c(1,1,2,2,2), var1 = c(10,10,20,20,25), var2 = c('foo', 'foo', 'foo', 'foobar', 'foo')) Now, if I were to subset by id, such as: > subset(dat, id==1) id var1 var2 1 1 10 foo 2 1 10 foo I can see that the elements in var1 are exactly the same and the elements in var2 are exactly

Dear all, I have a data set in which the same unit appears 2 or 3 or 4 times. I need to aggregate this data to maintain only one unit by row. But I need to do that based on a comparison between the values of such units. I can't find a function to help me on that. I appreciate any help. Below I provide an example of what I want: This is my data: Units Var1 Var2 Var3 1 B 2

Hi, I think this is a very simple question, and it must just be missing something. I am looking for find out how to assign a constant integer value to the variable in llvm ir. The following returns 12, and %var2 = 12. ; ModuleID = 't.c' target datalayout =

R users, I don't know if I can make myself clear but I'll give it a try. I have a data.frame like this x <- "var1,var2,var3,var4 a,b,b,a b,b,c,b c,a,a,a a,b,c,c b,a,c,a c,c,b,b a,c,a,b b,c,a,c c,a,b,c" DF <- read.table(textConnection(x), header=T, sep=",") DF and I would like to sum all the combinations/occurences by a factor (letter in this case) between