similar to: normal distribution from chisqrd

hie how do you compute the logrank test using R what commands do you use my data looks something like just an example treatmentgrp strata censoringTime survivalTime censoring act.surv.time [1,] 2 2 42.89005 1847.3358 1 42.89005 [2,] 1 1 74.40379 440.3467 1 74.40379 [3,] 2 2

how do l programme the logrank test. l am trying to compare 2 survival curves --------------------------------- [[alternative HTML version deleted]]

hie is it possible to get the code for the logrank test l just need the chisquared value. thanks --------------------------------- [[alternative HTML version deleted]]

hie 1...i'm trying to carryout a relibility testusing cronbach's alpha what fuctin do i use. 2.. this is more of a statistical question.if the alpha value for all the variables is negative what does it mean. and if the alpha value is negative for all tyha variables but is greater than 0.7 for some sections of the variables what does that mean thanks in advance

hie l would like to create about ten strata l have tried using sample(c(1,2),1,replace=TRUE) but all l get is a vector of 1 and 2 if i change it to sample(c(1,10),1,replace=TRUE) it gives me a vector of 1 and 10 how do l go about it --------------------------------- [[alternative HTML version deleted]]

Hi All, I have a vector of length 48, something like: 0 0 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 I would like to print (reformat) this vector as: 001100000000001111111111111111111111111111111111 by simply removing the spaces between them. I have been trying with many option but not able to do this task. I would greatly appreciate your

hie i'm tryimg to generate two survival data using the following code (I know its ugly ) but it seems to repeat two of the variables can any one tell me whats the porblem. n=20 n1=n/2 n2=n/4 a11=1 ;a12=1.4 ;a21=16 ;a22=a12 * a21 t1<-array(1,c(n1)) t2<-array(2,c(n1)) treatgrp=matrix(c(t1,t2))

On 5/2/07, r-help-request@stat.math.ethz.ch < r-help-request@stat.math.ethz.ch> wrote: > > Send R-help mailing list submissions to > r-help@stat.math.ethz.ch > > To subscribe or unsubscribe via the World Wide Web, visit > https://stat.ethz.ch/mailman/listinfo/r-help > or, via email, send a message with subject or body 'help' to >

Hello, I've got a script set up to back up some of our server's (CentOS 4.3) directories to a mounted Samba drive. One of the directories contains the mail and during the file copy some open mail files are backed up. However, these files are unable to be deleted from the mounted drive giving an error "Text file busy." There's no process id so the CentOS server doesn't

Dear the following is the asterisk's dbase(Mysql5). if the extension =17171000 asterisk run appdata=222222, but I prefer to run appdata=3333333. let me know how I can run the appdata=33333 best Mani mysql> select * from ext; +----+---------+--------+----------+------+---------------------------------------+ | id | context | exten | priority | app | appdata

Hello, I am attempting to extend the standard manifest generated by puppetd --genmanifest. Interestingly, it seems like my file configurations are not being honored in terms of permissions and ownership. Instead, the default permissions and owners are being set. Is there some way to override the defaults from within a manifest? Also, I attempted to use the special parameters in the

Hello - I running Samba as a PDC on FC6 with roaming profiles. I need to setup a custom Windows logon/welcome message... to tell users want they can expect using this domain. Is it also possible to place different PDF files on the users desktop when he or she logs on, but only referencing one source file, so I don't have a copy for each user? What is the best approach? Thank You. Ralf

hie when i use plot.survfit to plot more than one graph why I only see the last graph how do i see the other graphs.for example n=20 n1=n/2 n2=n/4 a11=4;a12=4 ;a21=4 ;a22=4 t1<-array(1,c(n1)) t2<-array(2,c(n1)) treatgrp=matrix(c(t1,t2))

hie all i am trying to carry out a categorical data analysis but my problem is that when in i use the chi squared test some of my expected values are less than 5. is there a test that can handle this situation. the data is not a 2*2 table. its more from the social sciences where you have from strongly agree to strongly disagree. i know i can collapse vthe tables but there is a loss of

hi there! I have a couple phones connected to a sipura ata and if I go into *- IVR, I press options on the regular phones and it all works fine and dandy. then I connect an xten softphone, a new extension in my dialplan, I dial the ivr, * asks me to dial something to go through it, I press keys on xten, but nothing happens, * just times out through as if I did not press anything! is there some

I have been trying to learn the various "apply" functions but am still learning their appropriate use. I appreciate any help the R community can offer me. Sorry for the length of this post. Background: I have data on my hard drive organized in the following manner: The data pertains to many different "samples" of data. (e.g. sample 001, sample, 002, sample 003, etc.) Each

hie Im trying to calculate the power of the logrank test for different values of rho .I was just wandering whether the following programme would do it. any suggestions are welcome s=50 number=1 count1=0;count2=0;count3=0;count4=0;count5=0;count6=0;count7=0;count7=0; count8=0;count9=0 while(s!=0){ n=20 n1=n/2

hie how do I specify the number of decuimal places for my calulations thanks __________________________________________________ [[alternative HTML version deleted]]

hie carried out a comparison of survival curves using the log rank test in R with the values of rho ranging from -2 to 2 in increments of 0.5 the question is at rho=-1.5 the power of the test seems to fluctuate or differ from the trend shown by the other values of rho is the statistical reason for this difference.ie if the power is increasing as i move from 0 to -2 at rho=-1.5 the power either

hie l would like to create a 6th column "actual surv time" from the following data the condition being if censoringTime>survivaltime then actual survtime =survival time else actual survtime =censoring time the code l used to create the data is s=2 while(s!=0){ n=20 m<-matrix(nrow=n,ncol=4)