similar to: A coding question involving variable assignments in ifelse()

Displaying 20 results from an estimated 900 matches similar to: "A coding question involving variable assignments in ifelse()"

2007 Sep 26
5
sprucing up the R homepage
I've been a R-user for quite some time. The graphic on the home page looks a bit in need of polish so I applied some antialiased transformations that Peter Dalgaard has previously posted to R-help for improving graphic quality. I had to change the margins a bit, but here is what it looks like: http://www.broad.mit.edu/~finnyk/Rhome.jpg Personally, I think it looks much better. Because
2007 Apr 27
4
how to evaluate a dynamic variable?
Please help me evaluate a "dynamic variable" as show in the code snippet below. # regular variable a = c(1,2,3,4) # dynamic variable set at runtime DV = "a" eval(DV) --> a eval(eval(DV)) --> a # what I want something_goes_here(DV) --> 1,2,3,4 Can someone teach me how to do this? Thanks very much. - Bobby
2007 Apr 27
4
Randomising matrices
I would like to be able to randomise presence-absence (i.e. binary) matrices whilst keeping both the row and column totals constant. Is there a function in R that would allow me to do this? I'm working with vegetation presence-absence matrices based on field observations. The matrices are formatted to have sites as rows and species as columns. The presence of a species on a site is
2007 Apr 26
1
comparing two matrices, row by row
Estimated people, I have two matrices: ar1 <- array(data=c(1:16),dim=c(4,4)) ar2 <- array(data=c(1,2,3,3,5:16),dim=c(4,4)) They only differ in the fourth row. I would like to compare them in order to know which columns are equal. The following works, but I would like to have a better solution, and not to use what someone called "prehistorical loops": for(i in
2006 Oct 25
2
Isn''t it possible to stub / expect on :id ?
Hi all ! Running this: @payout = stub_everything(:id => 141) Payout.stubs(:find).with(@payout.id).returns(@payout) Generates this warning: ./test/functional/payouts_controller_test.rb:22: warning: Object#id will be deprecated; use Object#object_id What am I missing ? :id is a fairly frequent method to override in Rails-based applications. I''m using Mocha from
2011 Apr 16
2
superimpose graphs
Hi there, I have a data frame DF of over 600 people's short term trade data in time order. Below is the simplified structure of the data. id invest payout [1] 1 10 -1 [2] 1 33 33 [3] 1 20 -5 [4] 2 200 33 [5] 2 33 -20 [6] 3 5 -5 [7] 3 5
2011 Apr 16
1
600 people's time series
Hi there, I have a data frame DF of over 600 people's short term trade data in time order. Below is the super simplified structure of the data. id invest payout [1] 1 10 -1 [2] 1 33 33 [3] 1 20 -5 [4] 2 200 33 [5] 2 33 -20 [6] 3 5 -5 [7] 3
2008 Dec 04
2
Ruby fun with MegaMillions
I thought I would write a lottery number generator since I have not had any luck winning the big jackpot - http://megamillions.com/. So far, after over 1.2 million tries, I still have not hit all the numbers from yesterday: 2, 17, 22, 32, 51, 35 (last one is the mega ball). Fun little project that and I thought others would be interested. Let me know if you have a cleaner implementation in mind.
2000 Apr 15
0
problem with function involving ifelse and integrate
Dear R people, There is probably a simple explanation for the following, but I have been unable to come up with one. I want to integrate x(1-x)^{-1/3} over intervals of the form [0,a] where a is between 0 and 1. Hence, consider: fm <- function(x) ifelse(x==0 | x==1 ,0,(x*(1-x))^(-1/3)) inbeta <- function(x) { ifelse(x==0,0,integrate(fm,0,x,maxpts = NULL, eps=0.01)) } Comments:
2012 Jan 13
1
Portfolio Optimization
Hi, I'm an R newbie and I've been struggling with a optimization problem for the past couple of days now. Here's the problem - I have a matrix of expected payouts from different stock option strategies. Each column in my matrix represents a different stock and each row represents the return to the strategy given a certain market move. So the rows are not a time series of percentage
2011 May 31
1
while loop problems
Hi , i am trying to get this loop in my r program to work but it is not giving me the results that I desire. I am trying to model an insurance contract where there are n securities that have a fixed likelihood of default vector(data[i,2]) and a payout vector(data[i,1]). i need to price the value of stop losses at the security level and at the portfolio level. to do this i created two while loops
2009 Apr 27
1
Extract one element from yahooKeystats data
I am trying to extract one particular piece of data(Float) from all the data returned by yahooKeystats, but thus far I'm having no luck. This is what I've got so far: > library(fImport) Loading required package: timeSeries Loading required package: timeDate > data<-yahooKeystats("IBM") trying URL 'http://finance.yahoo.com/q/ks?s=IBM' Content type 'text/html;
2014 Nov 09
1
Bug#767295: Bug#767295: Bug#767295: xl: apparent memory leak
On 11/09/2014 07:18 AM, Gedalya wrote: > That memory block is just a bit larger than the size of the initrd in > the VM, could there be a connection? Nope. I changed the initrd to 2.6mb and that memory block is still exactly at 23852 / 14464 / 14464. Actually the process size is around 12 mb when pygrub is counting down to boot, then jumps up to 14+ mb
2019 Feb 24
2
SAMBA DNS interfaces set to br0
On a machine with virtual networking is enabled and two ether net controllers eth0/192.168.1.2 and eth1/192.168.1.3 and having SAMBA smb.conf set to: dns interfaces = lo br0 is there a chance for: 1) The system not to boot with DNS working 2) The DNS server bounce between eth0 and eth1 3) The DNS server portion work on boot sometimes on eth0, but when software restarted only work on eth1 or
2005 Aug 07
1
request for clarification on Asterisk T.38 bounty
The bounty stands at $5,500. I'm seriously considering taking a shot at it if I can find a decent T.38 provider to test with (I'm still hoping for reliable PAYG T.38). It looks like a lot of very smart people have done a lot of very hard work (t38modem, spandsp) that would go towards getting this working. At this point it appears to be mostly a matter of integration
2010 Mar 10
1
ifelse logic and multiple assignments
I'm a fairly new R user and while I have a solution to my problem I'm wondering if there is a better one. In SAS it's common to use if/then logic along with a "do" statement to make several things happen. While I could do the same thing in R using a "for" loop, and "if" and {}, I've read that loops are less common in R and I wonder if I'm doing
2023 Feb 02
1
A new step in NUT community building - signing up for fiscal hosting!
Hello all, For decades, the NUT project ran without any formal entity or a "money purse" of its own. This proved to be a somewhat limiting factor, since paid services like DNS have to be covered by maintainers (as in ancient times, when city celebrations were paid by randomly elected officials personally), and some other services like hosting for the NUT CI farm have to be solicited
2023 Feb 02
1
A new step in NUT community building - signing up for fiscal hosting!
Hello all, For decades, the NUT project ran without any formal entity or a "money purse" of its own. This proved to be a somewhat limiting factor, since paid services like DNS have to be covered by maintainers (as in ancient times, when city celebrations were paid by randomly elected officials personally), and some other services like hosting for the NUT CI farm have to be solicited
2008 Aug 19
5
RSpec raising routing errors where Rails doesn''t?
Hopefully someone here can help me figure out why the ERB: <% form_for(@fund, :url => {:host => PRIVATE_HOST}, :html => {:class => ''fund'', :multipart => true}) do |f| %> raises an error in my specs: No route matches {:action=>"index"} but works fine in my app and generates the following, desired HTML: <form
2007 Jan 30
5
how to join two arrays using their column names intersection
Dear all, I have a problem that may be someone of you can help. I am a newbie and do not find how to do it in manuals. I have two arrays, for example: ar1 <- array(data=c(1:16),dim=c(4,4)) ar2 <- array(data=c(1:16),dim=c(4,4)) colnames(ar1)<-c("A","B","D","E") colnames(ar2)<-c("C","A","E","B") > ar1