similar to: one problem about how to hold graphic with R

Dear List, I need to add a subscript and a superscript to some of the ions in the labels on some plots. I have got to here but now I'm stuck: plot(1:10, xlab = expression(paste("nm SO"[4], " ", mu, "eq cm"^{-2}, " yr"^{-1}))) Which gives almost what I require. No matter what I tried, however, I could not get bot a sub script *and* a superscript

Hi I'm having a problem with model.frame, encapsulated in this example: y1 <- matrix(c(3,1,0,1,0,1,1,0,0,0,1,0,0,0,1,1,0,1,1,1), nrow = 5, byrow = TRUE) y1 <- as.data.frame(y1) rownames(y1) <- paste("site", 1:5, sep = "") colnames(y1) <- paste("spp", 1:4, sep = "") y1 model.frame(~ y1) Error in model.frame(formula, rownames,

Dear List, I often have to merge two or more data frames containing unique row names but with some columns (names) common to the two data frames and some columns not common. This toy example will explain the kind of setup I am talking about: mat1 <- as.data.frame(matrix(rnorm(20), nrow = 5)) mat2 <- as.data.frame(matrix(rnorm(20), nrow = 4)) rownames(mat1) <- paste("site",

Hi, I got a problem when installing R in Fedora core 4. When I ran .configure, it gave the following error message: configure: error: --with-x=yes (default) and X11 headers/libs are not available Could anyone tell me what's wrong? Am I missing some package in Fedora? Thanks a lot for your help. Peter

Hi all, I would like to save the dendrogram of a hierarchical clustering. Let reshc the result of the fucntion hclust(). To save the dendrogram, I can use the function postscript: postscript(file="hc605.ps") plot(as.dendrogram(reshc),horiz=T,ylab="",main=" ") dev.off() Using the functions plot and as.dendrogram, it is possible to obtain an horizontal tree with

Dear list, given this formula: > fmla <- formula(y1 ~ spp1 + spp2 + spp3 + spp5) > fmla[[3]] spp1 + spp2 + spp3 + spp5 is this the intended behaviour of as.character: > as.character(fmla[[3]]) [1] "+" "spp1 + spp2 + spp3" "spp5" ? Where does the extra "+" come from? > as.character(fmla) [1] "~"

Dear List, I have the following function: coca <- function(x, ...) { if(is.null(class(x))) class(x) <- data.class(x) UseMethod("coca", x) } and a default method coca.default <- function(x, y, method = c("predictive", "symmetric"), reg.method = c("simpls", "eigen"), weights = NULL,

##data y1 <- matrix(c(3,1,0,1,0,1,1,0,0,0,1,0,0,0,1,1,0,1,1,1), nrow = 5, byrow = TRUE) y2 <- matrix(c (3,0,10,3,3,0,0,1,1,0,0,0,0,0,1,0,1,0,0,2,1,0,1,1,0,2,1,1,4,1), nrow = 5, byrow = TRUE) y1 <- as.data.frame(y1) y2 <- as.data.frame(y2) rownames(y1) <- rownames(y2) <- paste("site", 1:5, sep = "") colnames(y1) <-

Hi, I was wondering whether a package that can perform dynamic linear models on times series data was available for R? Many Thanks, Gavin Simpson %~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~%~% Gavin Simpson [T] +44 (0)20 7679 5522 ENSIS Research Fellow [F] +44 (0)20 7679 7565 ENSIS Ltd. & ECRC [E] gavin.simpson at

something like "sprintf" in C? so I can do: print(sprintf("the correct result is %3.4f\n", myresult)); ------- Also, I am desperately looking for a "clear console screen" function in R... thanks a lot! [[alternative HTML version deleted]]

Dear List, I have the following problem with axis.Date, here is an artificial example: dates <- scan(what = "character") "25/03/2000" "26/03/2000" "27/03/2000" "28/03/2000" "29/03/2000" "30/03/2000" "31/03/2000" "01/04/2000" "02/04/2000" "03/04/2000" "04/04/2000"

I use R for the first time. The install file is R-2.4.0-win32.exe, and my OS is windows XP SP2. I chose the full install, but when i open it , one Error occured:"R for windows GUI front-end occurs error, You must end it" Does anyone know how to solve this? Waiting for your reply. Thanks. -- Baohua Yang Email:yangbaohua@gmail.com [[alternative HTML version deleted]]

I have two data sets: File1.txt: Name id1 id2 id3 ... N1 0 1 0 ... N2 0 1 1 ... N3 1 1 -1 ... ... File2.txt: Group id1 id2 id3 ... G1 1.22 1.34 2.44 ... G2 2.33 2.56 2.56 ... G3 1.56 1.99 1.46 ... ... I like to do: x1<-c(0,1,0,...) y1<-c(1.22,1.34, 2.44, ...)

hello I read "Practical Time Series" (Gareth Janacek; 2001) and they presented e.g the smoothing functions msmooth(x,k) or the bivariate function crosscorr(x,y,k), but both didn't work on my machine. I only load the ts library, is another library necessary or did this function change since 2001? Is there a more recent and detailed manual for ts? thanks, cheers Martin -- Martin

Hello, I suppose this is a basic question but couldn't find a solution.: I have a large matrix with let say 3 columns: V1 V2 V3 a x 2 a x 4 a y 8 b z 16 and I want to compute some statistics based on the levels resulting form the combination of the two first columns e.g.: SUM-> V1 V2 V3 a x 6 a y 8 b z 16 Thanks for your hints . Marc

Hi, I noticed the following problem with xy.coords() in R 2.2.1-patched (version info at the foot of this email) and R 2.3.0 unstable (subversion no: r37123): > xy.coords(x = matrix(1:20, ncol = 2)) Error in xy.coords(x = matrix(1:20, ncol = 2)) : argument "y" is missing, with no default > xy.coords(x = matrix(1:20, ncol = 2), y = NULL) $x [1] 1 2 3 4 5 6 7 8 9

Dear list, I am using Sweave to build a small report. I want to produce a series of figures, each figure containing a number of plots and then have them included in the Sweave file. An example would be to : postscript(file = "ANCbwplot%03d.eps", onefile = FALSE, other options...) oldpar <- par(mfrow = c(2,2)) .... do lots of plots to produce a number of eps files .... par(oldpar)

Hello there! When I do freq=F on hist, I get on the left a small number, what exactly does that mean? Thanks, Martin

Hi In trying to fit a linear model , I use the leaps() function to determine wich predictors I should include in my model. I would like to plot the Mallow's Cp criteria against p with the indexes of selected model variates as points labels Is there already such a function? (I could not find it) Thanks Anne [[alternative HTML version deleted]]

where is the cook-distance in R? i can't find it!please help me!