similar to: help_aov

Hi, I run windows vista ultimate in my laptop and run R 2.5 I am trying to update the packages but it comes up with an error message ""Warning in install.packages(update[instlib == l, "Package"], l, contriburl = contriburl, : 'lib' is not writable Error in install.packages(update[instlib == l, "Package"], l, contriburl = contriburl, :

Hi, help.I would like to plot the mean and standard deviation against a factor in the xaxis- in other words I want an errorplot. I also want to put the standard deviation like a "T" on top of a barplot. How can do this in R Bragadeesh

Hi, I am trying a linear regression model where the dependent variable is the size of the heart corrected for the patient's height and weight. This is labelled as LAVI. The independent variables are race (european or non-eurpoean), age, sex (male or female) of the patient and whether they have diabetes and high blood pressure. sample size 2000 patients selected from a community. when I

At one time (version 1.7), the code below used to work for converting and extracting based on the Date Time. In version 1.8.1, something changed I know, but I cannot for the life of me figure out what... Data: UserName,RequestDate,PO,OrderDate,ExpDelivDate,Vendor,Total "Woody, Jim",12/19/2002,AP15063,1/7/2003,2/10/2003,Ames ,8570 "Harrold,

Dear all, I'm having some problems with using the step() function inside another function. I think it is an environment problem but I do not know how to overcome it. Any suggestions are appreciated. I've prepared a simple example to illustrate my problem: > library(MASS) > data(Boston) > my.fun <- function(dataset) { + l <- lm(medv ~ .,data=dataset) + final.l <-

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 > Here is my first attempt at a patch. > It introduces a new header file where > people can put templates to be used wherever. > I have put "endof" and "lengthof" > which replace most uses of sizeof. > This should make the code a little neater. I have added Chris Lattner's modifications. I hope that this

Dear R guru, I am Saikat Sarkar working as a researcher of Economics in Tampere University, Finland. I am trying to estimate some Garch related tests with Bayesian analysis by R programme. I am not good in R but trying to survive. Anyway I have the coding but not working properly. I have tried to find the problem but failed. I am writing to all R gurus to help me out. Could you please look at

Hi All, I have set up a box that will be used as follows: SIP Phone ----> Asterisk ----> Cisco H323 VoIP Server 192.168.1.5 192.168.1.50 192.168.1.80 Asterisk is running the latest CVS and oh323 driver. The SIP phone is a Grandstream Budgetone 100. I have everything setup and running with G.711 ALAW and ULAW and i'm able to make calls through

Hi Christian, Chuck (and lists) It seems that the problem may be the strange behaviour of 'unstack' inside a function. See this thread in the R mailing list: http://tolstoy.newcastle.edu.au/R/help/04/03/1160.html Anyway, I got round the problem by using 'aggregate' instead of converting to a list and then tapply to sum values of metric. Probably more efficient as well. Thanks

I'm running an LSODA to generate some graphs, but I need to stop at a certain point and use those values to generate another LSODA output. This is working fine, but when I try to run the second LSODA, I get the "Error in eval(expr, envir, enclos) : object 'N' not found". Any ideas what can be causing this? I have no object 'N' anywhere in the script. I made an

Dear Guys, I do converting codes from Fortran into R and got stuck in solving LOOPING procedure with R. In FORTRAN, it is (DO and END DO) for looping in the net. In R, it is (FOR with { }). I believe there is something wrong with my coding in R, do hope that you can help me solving following problems. It seems easy, but results are not the same.

Hi everyone, I have a problem with running a glm using a subset of my data. Whenever I choose a subset, in the summary the factors arent shown (as if the variable was a continuous variable). If I dont use subsets then all the factors are shown. I have copied the output from summary for both cases. Thanks for the help, Muri > model<-glm(log(cpue)~year,family=gaussian) Call: glm(formula =

Hi, I have a casting/formatting question on hist.POSIXt: The histogram plot from POSIXct works perfect (with help of Prof. Ripley -thanks!). When processing the hist(plot=FALSE) output and then plotting the results over the x-axis (bins) coming from hist(), I lose the date/time labels, getting instead integers displayed. Trying to cast the $breaks with as.POSIXct gives silly results with

------------------------------ On Fri, Dec 13, 2013 16:29 GMT David Winsemius wrote: > >On Dec 11, 2013, at 7:30 PM, Hin-Tak Leung wrote: > >> Here is a rather long discussion etc about freetype 2.5.2, problem with the survival package, and build R 2.15.x with gcc 4.8.x. Please feel free to skip forward. >> >> - freetype 2.5.2: >> >> the fix to cope with

Hello R users, For the last few days I am struggling with the following task: my data.frame: A1 A2 A3 B1 B2 B3 58.81 53.292 54.501 13.013 17.39 19.407 56.02 56.251 54.033 20.099 13.15 10.411 55.376 53.099 57.625 13.396 21.031 13.22 58.584 53.194 54.218 13.038 16.854 19.289 55.7 55.921 53.847 19.942 13.153 9.828 55.093 52.934

Hallo, I have this dataset with repeated measures. There are two within-subject factors, "formant" (2 levels: 1 and 2) and "f2 Ref" (25 levels: 670, 729, 788, 846, 905, 1080, 1100, 1120, 1140, 1170, 1480, 1470, 1450, 1440, 1430, 1890, 1840, 1790, 1740, 1690, 2290, 2210, 2120, 2040, 1950), and one between-subject factor, lang (2 levels:1 and 2). The response variable