similar to: memory management

Hi All, I have a vector of data, a vector of bin breakpoints and I want to put my data in the bins and then extract fanciful informations like the mean value of each bin. I know I can write my own function, but I would have thought that R should have somewhere a function that took as arguments something like (data, breaks, what to do with the data in the bins). I surey could not find it

Hi All, I cannot upgrade r-base and r-recommended because the latest (latest as in it was not listed as 'upgradable' yesterday but today is) r-base-cose is 2.7.1-2hardy0 not hardy1: r-base: Depends: r-base-core (>=2.7.2-1hardy1) but 2.7.1-2hardy0 is to be installed Depends: r-recommended (=2.7.2-1hardy1) but 2.7.1-2hardy0 is to be installed r-base-core: r-recommended:

Hi All, I would like to ask the following. I have an array of data in an objetct, let's say X. I need to use a for loop on the elements of one or more columns of X and I am having a debate with a colleague about the best memory management. I believe that if I do: col1 = X[,1] col2 = X[,2] ... colx = X[,x] and then for(i in whatever){ do something using col1[i], col2[i] ... colx[i] }

Hi All, I have some data I need to write as a file from R to use in a different program. My data comes as a numeric matrix of n rows and 2 colums, I need to transform each row as a two rows 1 col output, and separate the output of each row with a blanck line. Foe instance I need to go from this: V2 V3 27 2032567 19 28 2035482 19 126 2472826 19 132 2473320 19 136 2035480 135

Hi All, is there a way of predicting memory usage? I need to build an array of 86000 by 2500 numbers (or I might create a list of 2 by 2500 arrays 43000 long). How much memory should I expect to use/need? Cheers, Fede -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St. Mary's Campus Norfolk Place, London W2 1PG Tel +44 (0)20 75941602 Fax +44

Hi All, I am trying to build a new R package to submit, but it's failing to create a tex manual: R CMD check Biodem * checking for working latex ... OK * using log directory '/home/greatsage/Fede/R-packages/temp/Biodem.Rcheck' * checking for file 'Biodem/DESCRIPTION' ... OK * checking if this is a source package ... OK * Installing *source* package 'Biodem' ... ** R

Hi All, I have a list of matrices: > x [,1] [,2] [1,] 1 4 [2,] 2 5 [3,] 3 6 > y [,1] [,2] [,3] [,4] [,5] [,6] [1,] 18 21 24 27 30 33 [2,] 19 22 25 28 31 34 [3,] 20 23 26 29 32 35 > z =list(x,y) I want to create a second list that is has a subset each matrix in the list subsetting so I get the 2nd and 3rd row of each (and

Dear All, I saved by mistake the environment I was working in after typing q(), and now I get the annoying message: [Previously saved workspace restored] I have already deleted all the objects in the environment, saving it as an empty environment, so it's just a matter of nitpicking I suppose. The message does not appear if I start R from any other place in the directory tree. I am

Hi All, a colleague wants to calculate the Fisher information matrix for a model he wrote (not in R). He can easily get the neg-log-likelihood and the best fit parameters at the minimum. He can also get negLLs for other parameter values too. Given these data, is there a way in R to calculate the Fisher information matrix? Best, Federico -- Federico C. F. Calboli Department of Epidemiology

Hi You could try to find an equivalent representation as a string and try to match those. > (A <- cbind(sample(1:2, 10, rep=TRUE), sample(1:2, 10, rep=TRUE))) [,1] [,2] [1,] 1 2 [2,] 1 2 [3,] 1 2 [4,] 2 2 [5,] 1 1 [6,] 1 2 [7,] 1 2 [8,] 1 1 [9,] 1 2 [10,] 1 1 > (B <- unique(A)) [,1] [,2] [1,] 1 2

Hi All, I have two data frames. The first contains data about a number of individuals, coded in the first column with a name, in an order I find convenient. The second contains different data about the same indivduals, in a different order. Both data frame have the individual names in the first column. I need to reorder the second data frame so the rows are rearranged in the same manner as

Hi All, does anyone ever import old SPSS files in a sl3 format? read.spss('file.sl3') does not seem to work... it's not recognised as a supported SPSS format at all. Best, Fede -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St. Mary's Campus Norfolk Place, London W2 1PG Tel +44 (0)20 75941602 Fax +44 (0)20 75943193 f.calboli

Hi All, can I have a plot where the symbol for the dots is smaller than pch =20 but bigger than pch = '.'? Best, Fede -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St. Mary's Campus Norfolk Place, London W2 1PG Tel +44 (0)20 75941602 Fax +44 (0)20 75943193 f.calboli [.a.t] imperial.ac.uk f.calboli [.a.t] gmail.com

Hi All, I have the following problem: x = c(1,2) x [1] 1 2 as.matrix(x) [,1] [1,] 1 [2,] 2 BUT, if I add: y = c(3,4) as.matrix(rbind(x,y)) [,1] [,2] x 1 2 y 3 4 It does not transpose. Since I will need as.matrix() for a list of data that is in one or more lines, I need as.matrix to behave in a consisten fashions, so I get as.matrix(x, whatever) [,1] [,2] x 1

Hi All, is there an equivalent of the Unix command 'less' (or 'more'), so I can look at what's inside a data.frame or a matrix without having it printed out on console? I am using R on Debian Linux and Mac OS 10.4.5 Cheers, F -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St Mary's Campus Norfolk Place, London W2 1PG Tel +44

Hi All, I am using plot(x, type = 'l') for some plotting, but I would like rounded edges rather than jagged edges in the plot (purely for aestetic reasons). How could I achieve that? Cheers, Federico -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St Mary's Campus Norfolk Place, London W2 1PG Tel +44 (0)20 7594 1602 Fax (+44) 020

Hi All, I am (almost) successfully using apply() to apply a function recursively on a data matrix. The function is question is as.genotype() from the library 'genetics' apply(subset(chr1, names$breed == 'lab'),2,as.genotype,sep ="") Unfortuantely apply puts it's results into a matrix object rather than a data frame, tranforming my factors into numerics and

Hi everyone, I would like to find out when and where exactly I get the following warning in a piece of code I've written: Error in "[<-"(`*tmp*`, iseq, value = numeric(0)) : nothing to replace with The code is a for () loop performing a somewhat trivial calculation, modulated by a number of logical if(){} else(){} conditions, involving the creation of a number of

Hi All, is there a function in R that allows me to work with fractions without transforming them to floats (or whatever) in between? Something that would calculate something like: (1/2 + 1/8) * 1/2 = 5/16 without ever transforming to 0.5 and 0.125? Best, Federico -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St Mary's Campus Norfolk Place,

HI All, I have a data frame such as: > test x y p d [1,] 1 0 10 21 0 [2,] 2 3 11 12 0 [3,] 3 4 12 23 0 [4,] 3 5 13 24 0 and I want to perfor some operations on the first two coulums, conditional on the uneqaulity values on the 3rd and 4th columns. For instance: j = 3 test[test[,1] == j, 5] = test[test[,1] == j,2] + test[test[,2] == j,1] gives me the result: test: x y p d