similar to: comparing 2 lists

User administrator without access to several shares -- ?A menos que modifiquemos a nossa maneira de pensar, n?o seremos capazes de resolver os problemas causados pela forma como nos acostumamos a ver o mundo". Albert Einstein

----- Mensagem encaminhada ---- De: Ricardo A. Reis <ricardo_bsd@yahoo.com.br> Para: security@freebsd.org Enviadas: Sexta-feira, 3 de Novembro de 2006 10:54:14 Assunto: FreeBSD and the new virtual machine-based rootkits Hi All, Recently i participated in Brazil on October 2006 The FIRST/TRANSITS and II Latin American Incident Response Conference (COLARIS). In the II COLARIS - Joanna

Hi all, I need to solve double integrals with no closed solution. Calling x and y the two variables we have x ~ Normal(y*v,1) and y ~Half-Normal(0,1). In fact, given a joint funcion g(x,y), I need evaluate the integral of this function under that random structure. Could anyone suggest me a package or even a suitable method to solve this problem? Thanks all, Caio

In ubuntu 6,06 the R normally run, but latter to install the a vesion 6,10 plot this not appearing. computer with problem: /usr/share/X11/fonts$ ls misc Type1 X11R7 In computer OK: /usr/share/X11/fonts$ls 100dpi(*) 75dpi encodings fonts.cache-1 misc Type1 ----- Mensagem original ---- De: Peter Dalgaard <p.dalgaard@biostat.ku.dk> Para: Ricardo Arias Brito

Dear R users, A co-worker and I are writing a function to facilitate graph plotting in R. The function makes use of a lot of lists in its defaults. However, we discovered that R does not necessarily preserve the defaults if we were to input them in the form of list() when initializing the function. For example, if you feed the function codes below into R: myfunction=function( list1=list

I everyone, i have a little problem with tklistbox,the " " character and Rcmdr. Please look at this code require(tcltk) tt<-tktoplevel() levels.list2 <-tklistbox(tt,selectmode="multiple",exportselection="FALSE", height=4, yscrollcommand=function(...)tkset(levels.list2.scroll,...))

I can''t see how to use variables so I am using console to test things out... clients table - a column named first_name My very brief console session... >> clients = Client.find_by_sql("select * from clients where first_name = FN") ActiveRecord::StatementInvalid: RuntimeError: ERROR C42703 Mcolumn "fn" does not exist Fparse_expr.c L1034

Hi, Algorithm question: I have two sets of "intervals", where an interval is an ordered pair [a,b] of two numbers. Is there an efficient way in R to generate the intersection of two lists of same? For concreteness: I'm representing a set of intervals with a data.frame: > list1 = as.data.frame(list(open=c(1,5), close=c(2,10))) > list1 open close 1 1 2 2 5

Hi, I have 2 questions on list object:   1. Suppose I have a matrix like: dat <- matrix(1:9,3)   Now I want to replicate this entire matrix 3 times and put entire result in a list object. Means, if "res" is the resulting list then I should have:   res[[1]]=dat, res[[2]]=dat, res[[3]]=dat   How can I do that in the easilest manner?   2. Suppose I have 2 list objects: list1 <- list2

hi, i'm trying to figure out if there's any possibility to write a whole vector into a matrix or data.frame or something like that. i don't mean transormation. Here an example: [,1] [,2] [1,] "a" "d" [2,] "b" "e" [3,] "c" "f" where e.g. a is a<-c(0,1) vector of length 2, b a vector of length 4,... (i know that

Hi R users I was wondering on how to use lapply & co when the applied function has a conditional statement and the output is a 'growing' object. See example below: list1 <- list('A','B','C') list2 <- c() myfun <- function(x,list2) { one_elem <- x cat('one_elem= ', one_elem, '\n') random <- sample(1:2,1) show(random)

Hi, This has bugged me for a bit. First question is how to keep classes with rbind, and second question is how to properly return vecotrs instead of lists after turning an rbind of lists into a data.frame list1=list(a=2, b=as.Date("20090102", format="%Y%m%d")) list2=list(a=2, b=as.Date("20090102", format="%Y%m%d")) rbind(list1, list2) #this loses the

Hello, am I using 'setIs' in the correct way in the subsequent (artifical) example? Do I have to specify explicit 'setAs' for 'list' and 'vector' or should this work automatically, since "getClass("List1")" states an explicit coerce also for these classes. I'm working with R 2.0.0 Patched (2004-10-06) on windows 2000. Thanks for your

I am new to R, and I have been running into the following situation when I mistype a variable name in some code: > list1 <- list( a=1, b=2 ) > list2 <- list( a=1 ) > list2$b <- list1$c > list2 $a [1] 1 I would think at the point where I am trying to reference a field called "c" -- that does not exist -- in list1, there would be an error flagged. Instead, list1$c

R-helpers: Say I have two lists of arbitrary elements, e.g.: list1=list(c(1:3),"R is fun!",c(3:6)) list2=list(c(10:5),c(5:3),c(13,5),"I am so confused") I would like to produce a single new list that is composed of all combinations of the "top level" of list1 and list2, e.g.: listcombo=list(list(list1[[1]],list2[[1]]),list(list1[[1]],list2[[2]]

Hi, I am wondering whether we can apply 'cbind/rbind' on many **equivalent** list objects. For example please consider following: > list1 <- list2 <- vector("list", length=2); names(list1) <- names(list2) <- c("a", "b") > list1[[1]] <- matrix(1:25, 5) > list1[[2]] <- matrix(2:26, 5) > list2[[1]] <- 10:14 > list2[[2]] <-

I know that if I have a function that returns multiple values, I should do return(list(foo, bar)). But what do I do on the recieving end? fn <- function(x) { return(list(foo, bar)) } I know that at this point I could say values.list <- fn(x) and then access values.list[1] values.list[2] But that's hideous. I'd rather be able to say something like list(local_foo, local_bar)

I am struggling to understand the methodology here... I have a find.rhtml <%= start_form_tag :action => ''list2'', :first_name = client %> <%# render :partial => ''form'' %> <p><label for="client_first_name">First name</label><br/> <%= text_field ''client'', ''first_name''

Hi, I have two lists 1) List1- 30,000 rows and 104 columns 2) List2- a list of 14000 selected rownames  from List 1 Now, I want to extract all the 104 columns of List1  matching with the 14000 selected rownames from List2.  Psedocode will be something like this: match rownames(List2) with rownames(List1) extract selected matched 104 coloumns from (List1) strore in-> List3 So the

Silly question, but, can I test to see if any value of list a is contained in list b without doing a loop? A loop is easy enough, but wanted to see if there was a cleaner way. By way of example: List 1: a, b, c, d, e, f, g List 2: z, y, x, w, v, u, b Return true, since both lists contain b List 1: a, b, c, d, e, f, g List 2: z, y, x, w, v, u, t Return false, since the lists have no mutual