Displaying 20 results from an estimated 10000 matches similar to: "MLE Methods"
2008 Jan 22
2
MLE for censored distributions in R
Hi just wondering if there is a package that can get the maximum likelihood
or method of moments estimator for distributions with censored data? The
distributions I'm interested in are: Exponential, pareto, beta, gamma and
lognormal.
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2009 Feb 06
1
MLE for right-censored data with covariates
I am a student (and very to new to R) working on a senior design project that
is attempting to determine the demand distributions for single copy
newspaper draws at individual sales outlet locations. Our sales data is
right-censored, because sell-outs constitute a majority of the data, and we
are also testing the relevance of including covariates (weather,
seasonality, economic condition, etc.).
2006 Jan 19
2
Tobit estimation?
Folks,
Based on
http://www.biostat.wustl.edu/archives/html/s-news/1999-06/msg00125.html
I thought I should experiment with using survreg() to estimate tobit
models.
I start by simulating a data frame with 100 observations from a tobit model
> x1 <- runif(100)
> x2 <- runif(100)*3
> ystar <- 2 + 3*x1 - 4*x2 + rnorm(100)*2
> y <- ystar
> censored <- ystar <= 0
2008 Apr 08
1
Weibull maximum likelihood estimates for censored data
Hello!
I have a matrix with data and a column indicating whether it is censored
or not. Is there a way to apply weibull and exponential maximum
likelihood estimation directly on the censored data, like in the paper:
Backtesting Value-at-Risk: A Duration-Based Approach, P Chrisoffersen
and D Pelletier (October 2003) page 8?
The problem is that if I type out the code as below the likelihood
1999 Dec 09
1
nlm() problem or MLE problem?
I am trying to do a MLE fit of the weibull to some data, which I attach.
fitweibull<-function()
{
rt<-scan("r/rt/data2/triam1.dat")
rt<-sort(rt)
plot(rt,ppoints(rt))
a<-9
b<-.27
fn<-function(p) -sum( log(dweibull(rt,p[1],p[2])) )
cat("starting -log like=",fn(c(a,b)),"\n")
out<-nlm(fn,p=c(a,b), hessian=TRUE)
2005 Oct 28
2
Uncensoring a dataset - resent
Does anyone know of an R package that I can use to uncensor a normal or
log-normal dataset? I'm particularly interested in the MLE method of
Cohen (1959), "Simplified estimators for the normal distribution when
samples are single censored or truncated," Technometrics, 1(3), 217-237.
Of course, if there is anything better, I'd be glad to hear about that
too.
Thanks.
Rick
2003 Apr 20
1
survreg penalized likelihood?
What objective function is maximized by survreg with the default
Weibull model? I'm getting finite parameters in a case that has the
likelihood maximzed at Infinite, so it can't be a simple maximum
likelihood.
Consider the following:
#############################
> set.seed(3)
> Stress <- rep(1:3, each=3)
> ch.life <- exp(9-3*Stress)
> simLife <- rexp(9,
2011 Aug 31
6
Weights using Survreg
Dear R users,
I have been trying to understand what the Weights arguments is doing in the
estimation of the parameters when using the Surreg function.
I looked through the function's code but I am not sure if I got it or not.
For example, if I inclue the Surv function in it:
survreg(Surv(vector, status)~1,weights=vector2,dist="Weibull")
will it try to maximize the likelihood with
2009 Mar 08
2
survreg help in R
Hey all,
I am trying to use the survreg function in R to estimate the mean and
standard deviation to come up with the MLE of alpha and lambda for the
weibull distribution. I am doing the following:
times<-c(10,13,18,19,23,30,36,38,54,56,59,75,93,97,104,107,107,107)
censor<-c(1,0,0,1,0,1,1,0,0,0,1,1,1,1,0,1,0,0)
survreg(Surv(times,censor),dist='weibull')
and I get the following
2012 Aug 31
3
fitting lognormal censored data
Hi ,
I am trying to get some estimator based on lognormal distribution when we have left,interval, and right censored data. Since, there is now avalible pakage in R can help me in this, I had to write my own code using Newton Raphson method which requires first and second derivative of log likelihood but my problem after runing the code is the estimators were too high. with this email ,I provide
2006 Feb 13
2
Survreg(), Surv() and interval-censored data
Can survreg() handle interval-censored data like the documentation
says? I ask because the command:
survreg(Surv(start, stop, event) ~ 1, data = heart)
fails with the error message
Invalid survival type
yet the documentation for Surv() states:
"Presently, the only methods allowing interval censored data are
the parametric models computed by 'survreg'"
2005 Jan 31
2
ML-Fit for truncated distributions
Hello,
maybe that my Question is a "beginner"-Question, but up to now, my research
didn't bring any useful result.
I'm trying to fit a distribution (e.g. lognormal) to a given set of data
(ML-Estimation). I KNOW about my data that there is a truncation for all
data below a well known threshold. Is there an R-solution for an
ML-estimation for this kind of data-problem? As
2004 Oct 17
2
Errors while compiling packages with namespace?
Hello,
I try to set up namespaces for packages. It is fine for several of them,
except one whose compilation fails (under Windows XP & R 2.0.0):
---------- Making package svViews ------------
adding build stamp to DESCRIPTION
installing NAMESPACE file and metadata
Error in parse(file, n, text, prompt) : syntax error on line 21
Execution halted
make[2]: *** [nmspace] Error 1
make[1]: ***
2008 Dec 23
6
Interval censored Data in survreg() with zero values!
Hello,
I have interval censored data, censored between (0, 100). I used the
tobit function in the AER package which in turn backs on survreg.
Actually I'm struggling with the distribution. Data is asymmetrically
distributed, so first choice would be a Weibull distribution.
Unfortunately the Weibull doesn't allow for zero values in time data,
as it requires x > 0. So I tried the
2007 Nov 29
1
Survreg(), Surv() and interval-censored data
Can anybody give me a neat example of interval censored data analysis codes in R?
Given that suvreg(Surv(c(1,1,NA,3),c(2,NA,2,3),type="interval2")~1)
works why does
survreg(Surv(data[,1],data[,2],type="interval2")~1)
not work where
data is :
T.1 T.2 Status
1 0.0000000 0.62873036 1
2 0.0000000 2.07039068 1
3 0.0000000
2012 Jul 05
3
Maximum Likelihood Estimation Poisson distribution mle {stats4}
Hi everyone!
I am using the mle {stats4} to estimate the parameters of distributions by
MLE method. I have a problem with the examples they provided with the
mle{stats4} html files. Please check the example and my question below!
*Here is the mle html help file *
http://stat.ethz.ch/R-manual/R-devel/library/stats4/html/mle.html
http://stat.ethz.ch/R-manual/R-devel/library/stats4/html/mle.html
2006 Dec 30
3
wrapping mle()
Hi,
How can we set the environment for the minuslog function in mle()? The
call in this code fails because the "ll" function cannot find the object
'y'. Modifying from the example in ?mle:
library(stats4)
ll <- function(ymax=15, xhalf=6) {
-sum(stats::dpois(y, lambda=ymax/(1+x/xhalf), log=TRUE))
}
fit.mle <- function(FUN, x, y) {
loglik.fun <- match.fun(FUN)
2005 May 03
2
comparing lm(), survreg( ... , dist="gaussian") and survreg( ... , dist="lognormal")
Dear R-Helpers:
I have tried everything I can think of and hope not to appear too foolish
when my error is pointed out to me.
I have some real data (18 points) that look linear on a log-log plot so I
used them for a comparison of lm() and survreg. There are no suspensions.
survreg.df <- data.frame(Cycles=c(2009000, 577000, 145000, 376000, 37000,
979000, 17420000, 71065000, 46397000,
2007 May 08
1
Fitting Random effect tobit model
Dear R-user:
I have a left censored longitudinally measured data set with 4 variables such as sub (which is id), x (only covariate), y (repeatedly measured response) and w (weights) (note, ?-5? indicates the left censored value in the attached data set). I am using following R codes (?survival? library and ?survreg? package) for fitting a random effect tobit model for the left censored
2005 Jun 07
1
R and MLE
I learned R & MLE in the last few days. It is great! I wrote up my
explorations as
http://www.mayin.org/ajayshah/KB/R/mle/mle.html
I will be most happy if R gurus will look at this and comment on how
it can be improved.
I have a few specific questions:
* Should one use optim() or should one use stats4::mle()?
I felt that mle() wasn't adding much value compared with optim, and