similar to: Help on direction of axis in R needed

Dear R-users, I am sorry if I ask for something that has been asked before, however, I still could not solve my little problem by consulting the previous thread on this topic: I would like to replace several values in a data frame, such as in: colorful subject response 1 me black 2 me brown 3 you red 4 me black 5 you brown read in with

I'm trying to do a linear regression between the columns of matrices. In example below I want to regress column 1 of matrix xdat with column1 of ydat and do a separate regression between the column 2s of each matrix. But the output I get seems to give correct slopes but incorrect intercepts and another set of slopes with value NA. How do I do this correctly? I'm after the slope and

Can anyone explain to me what this error message means, why I'm getting it, and how to fix it? lines(lowess(xdat, ydat, f=.5), col=3) Error: NAs in foreign function call (arg 1) ______________________________________________________________________ Stuart Luppescu -=-=- University of Chicago ºÍʸ ¤ÈÃÒÆàÈþ¤ÎÉã(EUC) -=-=- s-luppescu at uchicago.edu

I can't get identify to work, using R 2.0.1 under windows xp pro, service pack 2. Here's what I enter, and the result: > plot((our.frame2$c1),(our.frame2$c9)) # Produces desired plot > identify(our.frame2$c1) # Plot comes to forefront, so I select a point warning: no point with 0.25 inches numeric(0) Is my call to identify correct? The help page for indentify (from

i am trying to replicate the following graph using xyplot : attach(x) plot ( jitter(type), mortality, pch=16, xlim = c(0.25, 3.75)) lines ( c(1-0.375,1.375) , c ( median(mortality[type==1]), median(mortality[type==1])), lwd=5,col=2) lines ( c(2-0.375,2.375) , c ( median(mortality[type==2]), median(mortality[type==2])), lwd=5,col=2) lines ( c(3-0.375,3.375) , c ( median(mortality[type==3]),

hi all: Here's a dataframe(dat) and a vector(z): dat: x1 x2 x3 0.2 1.2 2.5 0.5 2 5 0.8 3 6.2 > z [1] 10 100 100 I wanna do the following: 10*x1,100*x2,1000*x3 My solution is using the loop for z and dat(since the length of z is the same as ncol of dat),which is tedious. I wanna an efficient solution to do it . Any help? Many thanks! My best

AMD's patch series for adding DSC support to the MST helpers unfortunately introduced a few regressions into the kernel that I didn't get around to fixing until just now. I would have reverted the changes earlier, but seeing as that would have reverted all of amd's DSC support + everything that was done on top of that I realllllly wanted to avoid doing that. Anyway, this should fix

Dear All, I'm trying to read a text data file that contains several records separated by a blank line. Each record starts with a row that contains it's ID and the number of rows for the records (two columns), then the data table itself, e.g. 123 5 89.1791 1.1024 90.5735 1.1024 92.5666 1.1024 95.0725 1.1024 101.2070 1.1024 321 3 60.1601 1.1024 64.8023 1.1024 70.0593

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Hello, First of all, let me apologize that my statistics background is modest at best. I am doing some extreme value analysis on model output (WRF) which have the following dimensions: speed(time,lat,lon) I am trying to fit the GPD (gpd.fit) to each point (time,lat,lon) to get a return level plot with values at each grid point. (Map with return level by location.) Here is some code I

Hola a todos, Soy nuevo en R y estoy intentando modelizar una serie de datos no estacionarios usand la distribucion Generalizada de Valores Extremos GEV. ¿Podriais indicarme como se modeliza una tendencia polinómica (cuadrática, por ejemplo) en alguno de los 3 parámetros (situación, escala o forma)? He encontrado documentación a cerca de modelización linear o exponencial, pero no acabo de

Dear forum users, It's 3:35am and I am swamped with statistics homework lol I'm terrible with R and this time I have no idea what the prof wants. Here is the question: Consider the (two-??sample) Wilcoxon rank statistic T = ?rank(Xi). For n1=106 and n2=192, determine by simulation the ?=.05 critical point for testing H0: ?=0, H1:?<0. We can do this as follows: For m=10000 (no wimpy

On Wed, Mar 04, 2020 at 05:36:12PM -0500, Lyude Paul wrote: > It's next to impossible for us to do connector probing on topologies > without occasionally racing with userspace, since creating a connector > itself causes a hotplug event which we have to send before probing the > available PBN of a connector. Even if we didn't have this hotplug event > sent, there's still

If I run the following example from: http://www.stat.auckland.ac.nz/~paul/grid/doc/grobs.pdf > grid.newpage() > pushViewport(viewport(w = 0.5, h = 0.5)) > myplot <- gTree(name = "myplot", children = gList(rectGrob(name = "box", + gp = gpar(col = "grey")), xaxisGrob(name = "xaxis"))) > grid.draw(myplot) >

Dear all, I have a large vector (lets call it myVector) and I want to plot its value with the logic below yaxis<-myVector[1] yaxis<-c(xaxis,mean(myvector[2:3]) yaxis<-c(xaxis,mean(myvector[4:8]) yaxis<c(xaxis,mean(myvector[9:16]) yaxis<c(xaxis,mean(myvector[17:32]) this has to stop when the new ..... yaxis<c(xaxis,mean(myvector[1024:2048]) will not find the correspondent number

On Thu, Mar 05, 2020 at 01:13:36PM -0500, Lyude Paul wrote: > On Thu, 2020-03-05 at 15:11 +0200, Ville Syrj?l? wrote: > > On Wed, Mar 04, 2020 at 05:36:12PM -0500, Lyude Paul wrote: > > > It's next to impossible for us to do connector probing on topologies > > > without occasionally racing with userspace, since creating a connector > > > itself causes a

Hi R list, I like the default ticks that are set up using grid.xaxis() or grid.yaxis() with no arguments. Finding good values for the 'at' argument is usually not a trivial task; the default behavior of these functions seems to work well. The problem with this strategy is that I cannot figure out how to "recover" the positions of these ticks when you do NOT specify the

Hello All, Is there any R function out there to turn a multi-way contingency table back to a flat file table of individual rows and attribute columns.? Thanks! marco --------------------------------- [[alternative HTML version deleted]]

Hi all, I am doing some clustering and the clustered results are presented in a "pairs" plot showing 4 clusters... I made the data points belong to 4 different clusters displaying different colors. Now I want to select the best clustered class, how can I click on the data point, and the program returns the index of that cluster(its class number, or color number)? Also, if I would

Hi, I have a string vector, say, x <- "a", "aab" and anther string vector, say, y <- "a", "aa", "aab", "aabc". Is there any R function to get the indices of y for the elements of x, that is, foo(x, y) will give me the index vector c(1, 3)? I know i can combine apply() and grep("^aab$", y) to do it. But is there any