similar to: spliting

I have a file that has 90 columns and 20,000 rows and looks like C/G CC GG CG G/T GG TT GT C/T CC TT CT A/G AA GG AG A/C AA CC AC A/T AA TT AT I want to write a code that will read through each row first the first looks at the first column and then replace the three columns with 12 if it is the same as the first column e.g. third column 11 if it is a repeat of the first alphabet like the

Dear mailing list I have a data that have 20,000 rows and 20 columns. Io wonted to extract the 10th row only. Example the 10th, 20th, 30th 40th…..20000 th. can you please help me how do I do that.Than kyou. Example is below. Inpute: AG GG GG AG CC CC CC CC CT CC CT CT GG GG GG GG CC CC CC CC GG GG GG GG CC CC CC CC GG CG CG GG GG GG GG GG *CC CC CC CC* AA AG AG AA AA AA AA AA GG AG AG GG GG AG AG

Dear mailing list, may some one be kind to help me solve following problem. I am trying to write a code that will combine two tables "x" and "y". The first columns of both tables are unique identification for the rows. The first column of table "X" is a sub set of the first column of "Y". I need to find the matching rows in both tables by looking on their

First I would really like to thank the mailing list for help I got in the past, as a new to R I am really needing some support on hoe to code the following problem. I am trying to sort some data I have in a big file. The file has 4 columns and 19000 rows. An example of it looks like this:- G 0.892 A 0.108 G 0.883 T 0.117 T 0.5 C

Dear mailing list I have a data in two columns and how can i convert it to one row . thank you in advance inpute 1 2 3 4 5 6 7 8 9 1 out put 1 2 3 4 5 6 7 8 9 1 [[alternative HTML version deleted]]

I HAVE A VERY BIG DATA OF 67 COLMS AND 25000 ROWS AND WOULD LIKE TO TRANSPOSE IT THE R HELP WAS NOT ENOUGH INFORMATION BECOUSE I AM NOT A PROGRAMMER AND FIRST TIME R USER. SO CAN YOU GIVE SOME HINTS OF CODING, AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC TO AA AA AA AA AA TT TT TT TT TT GG GG GG GG GG GG GG GG GG GG CC CC CC CC CC [[alternative HTML

---------- Forwarded message ---------- From: Dr. Venkatesh <drvenki at liv.ac.uk> Date: Sun, May 9, 2010 at 4:55 AM Subject: R apply() help -urgent To: r-help at r-project.org I have a file with 4873 rows of 1s or 0s and has 26 alphabets (A-Z) as columns. the 27th column also has 1s and 0s but stands for a different variable (pLoss). columns 1 and 2 are not significant and hence lets

Dear R users, I am trying to do the forest plot follow the function given on web. However, the order of the tests has been sorted alphabetically. I would prefer keeping the order as data frame input so that I can group and compare (from the graph) the target immune NS1, IgG and IgM (where SD, BioRad, Pb etc are the brand names) > d x y ylo yhi SD.NS1

Dear All I have a data.frame like that: structure(list(name = c("Gga_rs10722041", "Gga_rs10722249", "Gga_rs10722565", "Gga_rs10723082", "Gga_rs10723993", "Gga_rs10724555", "Gga_rs10726238", "Gga_rs10726461", "Gga_rs10726774", "Gga_rs10726967", "Gga_rs10727581", "Gga_rs10728004",

Hi, I am trying to split multiple columns. One column works just fine, but I want to do it for multiple columns??? Example > a ID V2 V3 V4 V5 V6 V7 V8 V9 V10 1 PBBA0644 -- GG AA -- AA -- AA GG GG 2 PBBA1010 -- GG AA -- AA -- AA GG GG 3 0127ATPR -- GG AA -- AA -- AA GG GG 4 0128EHAB -- GG AA -- AG -- AA AG GG 5 PBBA0829 -- GG AA -- AA -- AA GG AG

Dear list, I am trying to evaluate how many elements in a vector equal a certain value. The vectors are the columns of a data.frame, read in using read.table(): > dim(data) [1] 2600 742 > data[1:5,1:5] SNP001 SNP002 SNP003 SNP004 SNP005 1 GG AA TT TT GG 2 GG AA TC TT GG 3 GG AC CC TT GG 4 AG AA TT TT GG 5

The documentation for assignment says: In all the assignment operator expressions, 'x' can be a name or an expression defining a part of an object to be replaced (e.g., 'z[[1]]'). A syntactic name does not need to be quoted, though it can be (preferably by backticks). But the implementation allows assignment to a character string (i.e. not a name), which it

Dear R users, I am trying to fill in arrays (5 different according to distinct "id") from objects produced from arbitrary data set below. a <-

Dear Contributors I have a problem with the collection of data from the results of a test. I need to perform a comparative test over groups of data , recall the value of the pvalue and create a table. My problem is in the way to replicate the analysis over and over again over subsets of data according to a condition. I have this database, called y: gg t1 t2 d 40 1 1

I was going through the example below which is taken from the example section in the R documentation for accessing the function call stack. I am confused and I have 3 questions that I was hoping someone could answer. 1) why is y equal to zero even though the call was done with gg(3) 2) what does parents are 0,1,2,0,4,5,6,7 mean ? I understand what a parent frame is but how do the #'s relate

I have a more complicated function I am trying to write, but I run in to a problem when I want to add something to the plot from more than one data set while simultaneously controlling the appearance of the additional layer. # Toy data: foo <- data.frame ( x = 1:4, y = 4:1 , membership = c( "A", "A", "B", "B" ) ) bar <- data.frame ( x = 1:4 + 1 , y

Hi, I have a large dataset on which I would like to do the following: x<-data.frame(id=c(1,2,3), snp1=c("AA","GG", "AG"),snp2=c("GG","AG","GG"),snp3=c("GG","AG","AA")) > x id snp1 snp2 snp3 1 1 AA GG GG 2 2 GG AG AG 3 3 AG GG AA And then

I'm switching from OpenLDAP to the newly released Fedora Directory Server (formely known as the Netscape Directory Server) as a LDAP backend for my Samba domain. I'm now faced with a problem regarding how Fedora DS handles the userPassword field. Unlike OpenLDAP it encodes it in base64 so instead of reading userPassword: {SSHA}0lP+r3Z1NVan7Caf4CG9oSgnTbQRrv/p it reads: userPassword::

I am trying to create plots within a for loop and output them to a pdf. Here is a working example using plot: gg <- data.frame(datadate=1:4, spread=5:8) pdf() for (i in 1:3) { plot(gg$datadate, gg$spread, main=i) } dev.off() I am trying to learn more about ggplot2 so I try a slight modification and it doesn't work. Anyone

I'm new to R (previously used SAS primarily) and I have a genetics data frame consisting of genotypes for each of 300+ subjects (ID1, ID2, ID3, ...) at 3000+ genetic locations (SNP1, SNP2, SNP3...). A small subset of the data is shown below: SNP_ID SNP1 SNP2 SNP3 SNP4 Maj_Allele C G C A Min_Allele T A T G ID1 CC GG CT AA ID2 CC GG CC AA ID3 CC GG nc AA