similar to: deparse(substitute(foo))

Displaying 20 results from an estimated 50000 matches similar to: "deparse(substitute(foo))"

2013 Jan 09
1
deparse substitute
Hi, I'm writing a function that needs the input names (as characterstrings) as part of the output. With deparse(substitute( ) ) that works fine, until I replace all zeros with 0.001 (log is calculated at some time): tf <- function(input) { input[input==0] <- 0.001 ; deparse(substitute(input)) } myguess <- 42 tf(myguess) # not "myguess", but "42" Now when
2012 Apr 12
1
deferred call
I must admit I'm a little ashamed to have been using R for so long, and still lack a sound understanding of deferred calls, eval, deparse, substitute, and friends. I'm attempting to make a deferred call to a function which has default arguments in the following way: call.foo <- function(f) { x <- f() } x <- 1:10 f <- function(x=x) { x^2 } call.foo(f) However, I'm
2011 Jan 14
2
question about deparse(substitute(...))
Dear R helpers: I like to apply deparse(substitute()) on multiple arguments to collect the names of the arguments into a character vector. I used function test.fun as below. it works when there is only one input argument. but it does not work for multiple arguements. can someone kindly help? test.fun <- function(...){deparse(substitute(...))} test.fun(x) #this works test.fun(x,y,z) # I like
2008 Jan 22
1
deparse, substitute and S4 generics
Hello everyone, I encountered the following confusing behavior of 'deparse' and 'substitute' while programming with S4 classes (see example below). It seems like the presence of '...' argument in the definition of the generic generates the problem. I have no clue why, can anyone explain that to me? Are there any "workarounds"? Thanks a lot for your time!
2006 Sep 22
2
behavior of [<-.foo
Can someone help me understand the following behavior of "[<-" ? If I define a simple class based on a matrix, the [<- operation only inserts into the first column: > x <- matrix(rnorm(10),nrow=5,ncol=2) > class(x) <- "foo" > "[<-.foo" <- function(x, i, j, value) { + if(missing(i)) i <- 1:nrow(x) + if(missing(j)) j <-
2017 May 07
2
deparse(substitute(x)) fails in implied call to an S3 print method
In an implied call to an S3 print method, deparse(substitute(x)) returns "x", regardless of the name of object in .GlobalEnv, as indicated in the following: > Xnamed <- 1 > class(Xnamed) <- 'name.x' > print.name.x <- function(x, ...){ + namex <- deparse(substitute(x)) + cat('How can I get the name of x in .GlobalEnv?\n', +
2009 Nov 19
3
Issue when calling deparse(substitute(x)) from C with "anonymous" R vectors ?
Dear list, When calling R from C, what appears like a spurious error can be triggered during the execution of chisq.test(x, y). This is happening when the following conditions are met: - x and y are "anonymous" C-level R vectors (they do not have a symbol), but they are protected from garbage collection - x and y are "not too small" (it was experienced as soon as they are
2012 Feb 04
1
'deparse(substitute'))' then 'assign' in a S4 methods
Hi the list, I am writing a function in which I need to affect a variable on a higher level. My fnction could be: ++++++++++++++++++ fooBis <- function(x){ nameObject <- deparse(substitute(x)) print(nameObject) assign(nameObject,4,envir=parent.frame()) } > fooBis(e) [1] "e" > e [1] 4 ----------------- (to simplify, this fnction can affect only the number
2012 May 03
1
deparse(substitute(x)) on an object with S3 class
Dear list, can someone explain to me why deparse(substitute(x)) does not seem to work when x is of a user-defined S3 class? In my actual problem, my print method is part of a package, and the method is registered in the NAMESPACE, if that should make a difference. > print.testclass <- function(x,...){ xname <- deparse(substitute(x)) cat("Your object name
2017 Jan 09
1
problem with print.generic(x)deparse(substitute(x))
Hi, Peter et al.: On 2017-01-09 4:24 AM, peter dalgaard wrote: > On 09 Jan 2017, at 10:53 , Spencer Graves <spencer.graves at prodsyse.com> wrote: > >> # Define an object of class 'dum' >> k <- 1 >> class(k) <- 'dum' >> str(k) # as expected >> >> # Define print.dum >> print.dum <- function(x, ...) >>
2017 Jan 09
2
problem with print.generic(x)deparse(substitute(x))
Hi, All: I'm having trouble getting deparse(substitute(x)) inside print.generic to consistently I'm having trouble getting a print.something to work consistently. Consider the following toy example: # Define an object of class 'dum' k <- 1 class(k) <- 'dum' str(k) # as expected # Define print.dum print.dum <- function(x, ...)
2002 Sep 18
3
problem in deparse(substitute())
Hi all, I am experiencing the following quite strange (at least in my knowledge) problem in a simple function like the following: fn<-function(y,v=2){ n<-length(y) y<-y[(v+1):(n-v)] plot(y,type="l",lty=3,xlab="Time",ylab=deparse(substitute(y))) } fn(rnorm(50)) #look at the plot!!! The plot appears with numbers on the left side! If I delete the
2004 Apr 18
1
deparse(substitute(arg)) in C?
In R code, "deparse(substitute(arg))" is the usual way to construct a label for an argument. Is there an equivalent to this in C code working on an SEXP, inside a function called by .Internal()? Duncan Murdoch
2005 Aug 03
1
deparse(substitute(x)) and S3 methods
Dear List, I have the following function: coca <- function(x, ...) { if(is.null(class(x))) class(x) <- data.class(x) UseMethod("coca", x) } and a default method coca.default <- function(x, y, method = c("predictive", "symmetric"), reg.method = c("simpls", "eigen"), weights = NULL,
2002 Jan 23
1
Question about substitute (and eval, parse and deparse)
I would like to define a function at run-time, but I just can't make it work (please don't question why I want to do this, because that would be too much to explain). For example, I want to define the the following function foo <- function(x) { cat("Function", "foo", "was called with argument", x, ".\n") } However, I would like to
2007 Mar 23
1
substitute and S4 objects
Hi all, I don't understand why this does not what I expect : ## code start here ############## setClass("num",representation(x="numeric")) num<-function(x) new("num",x=x) add<-function(e1,e2) { cat("Computing ",deparse(substitute(e1)),"+",deparse(substitute(e2)),"\n") e1@x+e2@x }
2016 Jan 04
1
deparse with parentheses for SUBSET
Hi, maybe there?s a reason for it, but the discrepancy between the handling of `[` and `$` in deparsing seems odd to me: > substitute(a[1], list(a = quote(x * y))) x * y[1] > substitute(a$b, list(a = quote(x * y))) (x * y)$b The former is still executed in the right order (`*` first, then `[`), which is not what you?d expect looking at the deparse result. Some code that shows the execution
2006 Apr 11
1
Changing character limit in deparse, as.character and toString
Dear R-help Listers, I am curious if there is some (hopefully easy) way to change the number of characters that can be converted to a single string via any of deparse, as.character or toString. It seems that the limit is 500 for all of these. I saw a previous post where Prof. Ripley suggested that it was a "trivial" change in the R internals to change as.character's limit from 60
2006 Oct 19
1
lapack tests fail -- is this something to worry about?
I see the comment here about some 64bit combinations failing. Well, my configuration fails. Is this really something to worry about? for R-patched: fi1->cat SVN-REVISION Revision: 39576 Last Changed Date: 2006-10-03 fi1-> > ## failed for some 64bit-Lapack-gcc combinations: > sm <- cbind(1, 3:1, 1:3) > eigenok(sm, eigen(sm)) Error: abs(A %*% V - V %*% diag(lam)) < Eps is
2008 Jun 10
2
substitute() reading data instead of name
I seem to have run across a bug in which substitute() inside a function definition gets 'confused.' The code is listed below. The same behavior occurs under OSX 10.3.9, PPC, w/ R2.2 and Rgui 1.14 and under OSX 10.4.11 Intel w/ 2.70 and the latest Rgui. What I see is that 'xlab' properly has the name of the data I entered for the x-input. But 'ylab' contains the string