similar to: seeking robust test for equality of variances w/ observation weights

Here it is again, hope this is more clear I am using the following data (only a small subset is given): Habitat Fungus.yield Birch 20.83829053 Birch 22.9718181 Birch 22.28216829 Birch 24.23136797 Birch 22.32147961 Birch 20.30783598 Oak 27.24047258 Oak 29.7730014 Oak 30.12608508 Oak 25.76088669 Oak 30.14750974 Hornbeam 17.05307949 Hornbeam 15.32805111 Hornbeam 18.26920177 Hornbeam 21.30987049

This problem was posted a couple years ago here: http://tolstoy.newcastle.edu.au/R/help/04/01/0231.html Using Windows XP with R 2.3.1, I am now experiencing the same problem again: when a plot is saved and/or copied as a WMF, the labels do not have the correct character spacing. I am trying to insert the WMF into a MS Word 2003 document (my first mistake, I know), but even when the WMF is

Package: logcheck Version: 1.2.23 Severity: normal Hello, I have: # /bin/cat ignore.d.server/cron ^\w{3} [ :0-9]{11} [._[:alnum:]-]+ crontab\[[0-9]+\]: \([[:alnum:]-]+\) LIST \([[:alnum:]-]+\)$ ^\w{3} [ :0-9]{11} [._[:alnum:]-]+ crontab\[[0-9]+\]: \([[:alnum:]-]+\) REPLACE \([[:alnum:]-]+\)$ and: # /bin/cat ignore.d.paranoid/cron ^\w{3} [ :0-9]{11} [._[:alnum:]-]+

I am trying to use Levene's test (of package car), but I do not understand quite well how to use it. '?levene.test' does not unfortunately provide any example. My data are in a data frame and correspond to 1 factor plus response. Could someone please give me an example about how to use the command levene.test(y, group) Thanks in advance, marta -- View this message in

Hello all, I am low down on the learning curve of R but so far I have had little trouble using most of the packages. However, recently I have run into a wall when it comes to bootstrapping a Levene's test (from the car package) and thought you might be able to help. I have not been able to find R examples for the "boot" package where the test statistic specifically uses a

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Hi all! My question is why, and what I can do about that I sometimes, but not always, get warning-messages like nlminb returned message singular convergence (7) in: LMEopt(x = mer, value = cv) or IRLS iterations for PQL did not converge when trying to fit a model looking like this: lmer<-(cbind(Diseased,Healthy)~Fungus+(1|Family)+(1|Fungus:Family), family="binomial") to four

Dear all, I have a tree data matrix. For some trees I lack info about tree species, but I want to set them to be spruce. For some reason the tree species names on the remaining (non-NA) rows are changed into numbers (that I do not recognise). I guess that ifelse is not the correct function to use, but I have not found any better one in my searches. Thanks in advance! Sincerely, Tord >

Dear All I am trying to use Levene's test (of package car), but I do not understand quite well how to use it. '?levene.test' does not unfortunately provide any example. My data are in a data frame and correspond to 4 factors plus response. Could someone please give me an example about how to use the command levene.test(y, group) ? Thanks in advance, Paul

I'm thinking about replacing my Birch T1 integrator with an Asterisk box. The Integrator has 12 voice & 768k data, so the Asterisk box would become a router & PBX. Has anyone done anything similar, what experiences have you seen &/or read about. TIA

Hello, I notice that when I do Levene's test to test equality of variances across levels of a factor, I get different answers in R and SPSS 16. e.g.: For the chickwts data, in R, levene.test(weight, feed) gives F=0.7493, p=0.5896. SPSS 16 gives F=0.987, p=0.432 Why this difference? Which one should I believe? (I would like to believe R :) Ravi -- View this message in context:

Has the Levene test of homogeneity of variance been implemented in any library in R? Thanks, Maurice Haynes National Institute of Child Health and Human Development Child and Family Research Section 6705 Rockledge Drive Bethesda, MD 20892 Voice: 301-496-8180 Fax: 301-496-2766 E-Mail: mh192j at nih.gov

> From: Peter Dalgaard BSA <p.dalgaard at biostat.ku.dk> > Date: 01 Sep 2000 09:54:59 +0200 > > Prof Brian D Ripley <ripley at stats.ox.ac.uk> writes: Important omission: specification from Murray Jorgensen The test that I was thinking of basically does an anova on a modified response variable that is the absolute value of the difference between an observation

Hello, I am unable to figure out how to code a new column in a data frame based on an existing column that matches a column in a reference data frame, in a relational-db fashion. I would like this to maintain a minimum set of reference tables that may be reused over several similar datasets. Specifically, I have two data frames as listed below, 'Bos' and 'tree.' For each case in

Hello R-listers, I'm working in an experiment that try to determine the degree of infection of different clones of a fungus and, one of the measures we use to determine these degree is the counting of antibodies in the plasma at different dilutions, in this experiment the maximum number of dilutions was eleven. I already checked for differences on the maximum concentration of the

Hi all, I know that I can run an one way ANOVA on the absolute residual values to check the assumption of equal variances: model<- lm(y~x) summary(lm(abs(model$resid~x))) What if I have two factors? As far as I know I have to check this assumption on very factor/level combination. So if I have 3 factors with three levels, I would have to test 9 factor/level combinations. Here comes my

Hi, All! To calculate Levene's Test for Homogeneity of Variance I use R Commander, and this is the output: > levene.test(Dataset$age, Dataset$sex) Levene's Test for Homogeneity of Variance Df F value Pr(>F) group 1 0.8739 0.3567 33 I am not sure what means "Pr(>F)"? Can anyone explain/translate this? Regards, Iurie Malai Department of Psychology and

Hello, I am searching for the classic Levene test of variances in R but I don't find the function. Is there any command or do I have to programm the test by myself? Does anybody know? Help would be fine because R is very new to me. S.Zank [[alternative HTML version deleted]]

I just had another thought on this topic. What if we have a setting to select the maximum possible bitrate instead of a target bitrate setting. This satisfies the streaming people, but means that for an ordinary user to set a bitrate he'll have to set the quality to 9.999999 *and* the maximum bitrate to whatever he wants. ie. If he sets quality to "near CD" and max_bitrate to

Hi there, I'm learning Samba and I really appreciate somebody out there can help me out. I'm using RedHat advanced server and a windows 2000. I created a workgroup on samba and only samba machine and win2k machine are members. I shared the printer attached to the Linux. From win2k PC, I can see the workgroup, but I can not find the samba host from the workgroup, nor does the printer.