similar to: Converting data frame to zoo

Dear list, I know it must be obvious and I did my homework. (In fact I've RSiteSearched with keyword "remove AND library" but got timed out.(why?)....) How do I unload a library? I don't mean getting ride of it permanently but just to unload it for the time being. A related problem : I have some libraries loaded at startup in .First() which I have in .Rprofile. Now, I exited R

Hi all, I have two questions. Can some one give some help? The first question is regarding the pair of operators "&" and "&&". What is the difference between the two? The second question is regarding "<-" and "=". Usually we use "<-" as the assignment operator. I saw some people use "=". Is there any

Hi Folks! I'm struggling with dates - but enough about my personal life..... I have two daily time series files. In one (x) the date format is Y/m/d and the other (y) is d/m/y. I used read.zoo on both and they read into R with no problem. Then I use: weekdays(as.Date(x$DATE)) and get what I expect - all the days of the week in my data set. When I use:

Hi list, I'm sure the explanation must be laughably simple to the experts out there, but I just could figure it out. I have a simple data frame that looks like, >head(da.off) DDate OffP 1 2005-01-01 41.23 2 2005-01-02 44.86 3 2005-01-03 44.86 4 2005-01-04 43.01 5 2005-01-05 45.47 6 2005-01-06 48.62 where the first column DDate currently is character, and OffP is numeric. I want

does anyone know how to put a column name on a zoo object. I think achim and gabor are off line or they have gotten totally tired of me an decided to ignore me ( which is totalyy understandable ). logbidask<-log((aggfxdata[,"bid"] + aggfxdata[,"ask"])/2.0) logbidask doesn't have a name and I can't figure out how to get one on it ? aggfxdata is a zoo object.

Hi folks, Is there a function to show the size of an R object? eg. in Kbytes? Couple months ago Bendix Carstensen posted this marvelous little function lls(), which shows all objects in the current workspace by mode, class and 'size'. This is a wonderful enhancement to the build-in ls() already and I now have it sourced in my Rprofile.site at startup. The only drawback is,

Hi list, I'm trying to turn a date into something productive. (Not what you may be thinking....) I want three functions so I could take a "date" object and get the day of week, month, and year from it. xx <- as.Date("2006-01-05") month(xx) equal 1 day(xx) equal 5 year(xx) equal 2006 I'm aware of the weekdays() and months() functions in the base package. But

Following the official instructions to install R on ubuntu 10.04, I issued this command on the prompt, sudo apt-get install r-base Here is the error msg, Reading package lists... Done Building dependency tree Reading state information... Done Some packages could not be installed. This may mean that you have requested an impossible situation or if you are using the unstable distribution that

Hi folks, This is really minor but to someone not familiar with the various tentacles of the lmer package it could be really annoying. I was trying to plot the posterior density of the fixed effect parameters of a lmer model, > hr.mcmc = mcmcsamp(hr.lmer, n=50000) > densityplot(hr.mcmc, plot.points=F) There is this error, "Error in densityplot(hr.mcmc, plot.points = F) : no

Folks, i thought it should be straightforward but after a few hours poking around, I decided it's best to post my question on this list. I have a data frame consisting of a (large) number of date columns, which are read in from a csv file as character string. I want to convert them to Date type. Following is an example, where the first column is of integer type, while the rest are type

Dear list, First apologize that this is trivial and just betrays my slothfulness at the keyboard. I'm sick of having to type a long name just to get a glimpse of something. For example, if my data frame is named 'AuroraStochasticRunsJune1.df" and I want to see what the middle looks like, I have to type AuroraStochasticRunsJune1.df[ 400:500, ] And often I'm not even sure rows

Folks, The projection pursuit regression function in the base R seems to crash when the optimization level is set to zero, i.e. the initial ridge terms are accepted without refitting. I encountered this problem in an out-of-sample prediction exercise using predict. But further investigation suggests the issue is with the ppr fit and predict just sppeds up the crash. The other optlevels seem to be

Peter et al Thanks for the comments on dates. Some of the respondents missed the point, by showing ways that I could work around the problems, when my main argument is that one shouldn't have to work around problems. So I hereto present round 2 of the debate. 1 Postulates a. In my 35 year computing experience, I think that nothing frustrates me more than a computer program that

Dear all, I import my data from a csv-file containing one row with date-entries. How can I tell R to treat this data as dates? I've tried to bring it in character-format (as.charachter()) followed by as.POSIXlt() but I get an error message, that the character string is not in a standard unambiguous format, although the date is of format yyyy-mm-dd (what is standard format according to R

Hi all! I would like to import a matlab or gauss code to R. Could you help me? Bye, Sebasti?n. 2007/6/23, r-help-request en stat.math.ethz.ch <r-help-request en stat.math.ethz.ch>: > Send R-help mailing list submissions to > r-help en stat.math.ethz.ch > > To subscribe or unsubscribe via the World Wide Web, visit >

Hello, I was hoping for advice regarding resolving the above error. I have a csv file that contains the following variable: $ Order.Made.Date : Factor w/ 299 levels "1-Apr-08","1-Aug-05",..: 278 285 91 286 159 132 108 261 282 147 ... I want to calculate a variable named F.length, which is today's date minus the values contained in the variable:

require( zoo ) inp <- c( 5, 9, 4, 2, 1 ); m <- zoo( cbind( inp ), as.Date("2003-02-01") + (0:(length(inp)-1))); dim( m ) # [1] 5 1 dim( m[1,,drop=FALSE] ) # [1] 1 1 - ok dim( lag( m, -1 )) # [1] 4 1 - ok dim( rbind( m[1,,drop=FALSE], lag(m,-1) )) # NULL - converted from zoo matrix to zoo vector!?!? # any way to keep the last line as a zoo matrix??? -- View this message in

Hi all, I have following monthly time series : > head(data1) V1 V2 V3 1 Nov-80 NA 1007.44 2 Dec-80 NA 982.05 3 Jan-81 NA 994.25 4 Feb-81 NA 996.31 5 Mar-81 NA 939.91 6 Apr-81 NA 923.32 Now I want to convert it to a 'zoo' object. I wrote following syntax : ss = zoo(data1[,3], as.Date(data1[,1], format="%m/%y")) However I got following : > head(ss)

I wrote the date package long ago, and it has been useful. In my current task of reunifying the R (Tom Lumley) and Splus (me) code trees for survival, I'm removing the explicit dependence on 'date' objects from the expected survival routines so that they better integrate. Comparison of 'date' to 'Date' has raised a couple of questions. Clearly Date is more

Dear R users, I have a column with dates (character) in a data frame: 12-Jan-01 11-Jan-01 10-Jan-01 9-Jan-01 8-Jan-01 5-Jan-01 and I need to convert them to (Julian) dates so that I can sort the whole data frame by date. I thought it would be very simple, but after checking the documentation and the list I still don't have something that works. 1. as.Date returns the error below. What am I