similar to: non parametric MANOVA

Displaying 20 results from an estimated 900 matches similar to: "non parametric MANOVA"

2007 Nov 02
4
Permutation test, grouped data
I am perfectly aware that this question is not an R question, at least not yet, but I have not succeeded in finding what I want in other ways, so ... What I am looking for are two algorithms, preferabley in Pascal, but other languages may do. For (a) systematic (complete) permutations for grouped data with unequal group sizes, and (b) random permutations for the same kind of data. I know
2006 May 05
1
MRPP in R
Hello, I'm looking for a R function proceeding MRPP (Multi-Response Permutation Procedures). Is it available? Thanking you in anticipation, Jeanne Vallet, PhD student [[alternative HTML version deleted]]
2012 Mar 28
1
blocked MRPP and ISA
I have been trying to find a way to do a blocked MRPP (MRBP) and blocked ISA in R but have not found anything (in fact I found some things that say it is not possible). Does anyone know of a package, or written a script, that can do either of these? Thank you for any help.
2009 May 12
1
adonis help - (non-parametric (permutational) manova)
I am trying to apply this technique (M.J Anderson 2001) to a dataset of aquatic insect abundances. There is a sample in the unrestored and restored segement of a stream for every time period. I would like to compare the centroids of the distance matrices for the treatments up (unrestored) and dn (restored) to see if there is a difference in insect communities between the treatments. I will not
2015 Aug 06
3
consulta graficas para GLM
Estimados amigos y expertos del R, Les escribo para hacerles una pregunta que parece un poco sencilla pero me ha costado mucho. Estoy tratando de graficar los datos correspondientes a tasas de consumo de algunos organismos cuando están expuestos o no expuestos a un químico sobre tres tipos de presa. Por definición, debía ajustar los datos a un glm con distribución gama. Las gráficas pueden ser
2010 Dec 14
1
How to specify compiler options when using R CMD SHLIB
Hi I've built a dll using Fortran code and can call it by either R or Fortran. Calling by the former gives me the wrong answer and the later gives the correct answer. >From what I've read, it looks like I should use the subroutines DBLEPR, INTPR and REALPR to print to the R console rather than using Fortran standard I/O and that if I use the command R CMD SHLIB source.f that these
2013 Jun 11
1
'Boolean Index too long'
#Hi, I am trying to run an MRPP with community data (spp-site-matrix). I use the following code: mzbtaxa_mrpp <- mrpp(mzbdist,mzbsites$Site) #mzbdist being a distance object (Bray-Curtis similarity matrix) derived from my sqrt transformed community data set, created with function 'vegdist', mzbsites$Site refers to factors structuring my community. #when I run this code, I get the
2010 Dec 22
3
Estimate "between-axes" vs "within-axes heterogeneity of multivariate matrices
Hi! My question(s) in the end might be silly but I am no expert on this, so here it goes: Noy-Meir (1973), Pielou (1984) and a few others have pointed to non-centered PCA being in some cases useful. They clearly explain that "it is the case" when multi-dimensional data display distinct clusters (which have zero, or near-zero, projections in some subset of the axes) and the task is
2012 May 10
1
Problems with 64bit dll compile in R-2.15.0
I built my package under the R version 2.14.1 on windows without any problems by first checking for issues using R CMD check (no warnings) and then R CMD build to build the tar.gz. I can install this on version 2.14.1 using install.packages(...). I next tested to see if I could also install on version 2.15.0 (also on my computer) using install.packages() with the version 2.14.1 tar.gz this
2023 Apr 06
4
R does not run under latest RStudio
I updated to latest RStudio (RStudio-2023.03.0-386.exe) but R would not run. Error message: Error Starting R The R session failed to start. RSTUDIO VERSION RStudio 2023.03.0+386 "Cherry Blossom " (3c53477a, 2023-03-09) for Windows [No error available] I also tried RStudio 2022.12.0+353 --- same problem. I then tried another older version of RStudio (not sure version as I changed file
2013 May 03
1
MANOVA summary.manova(m) :" residuals have rank"
Dear All, I am trying to perform MANOVA. I have table with 504 columns(species) and 36 rows) with two grouping (season and location) Zx <- Z[c(4:504)] Zxm <- as.matrix(Z) m<- manova(Zxm~Season*location, data=Z) when I do summary.aov, I get respond for each species but summary.manova summary.manova(m) :" residuals have rank" 24<501. What can it be the reason for this error
2006 Feb 16
2
MANOVA: how do I read off within and between Sum-of-Squares info from the manova result?
Hi all, I am experimenting the function "manova" in R. I tried it on a few data sets, but I did not understand the result: I used "summary(manova_result)" and "summary(manova_result, test='Wilks')" and they gave a bunch of numbers... But I need the Sum-of-Squares of BETWEEN and WITHIN matrices... How do I read off from the R's manova results? Any
2004 May 24
2
Manova and specifying the model
Hi, I would like to conduct a MANOVA. I know that there 's the manova() funciton and the summary.manova() function to get the appropriate summary of test statistics. I just don't manage to specify my model in the manova() call. How to specify a model with multiple responses and one explanatory factor? If I type:
2007 Feb 22
1
MANOVA usage
Hello, I had a couple questions about manova modeling in R. I have calculated a manova model, and generated a summary.manova output using both the Wilks test and Pillai test. The output is essentially the same, except that the Wilks lambda = 1 - Pillai. Is this normal? (The output from both is appended below.) My other question is about the use of MANOVA. If I have one variable which has a
2004 Feb 15
1
manova() with a data frame
I'm trying to learn to use manova(), and don't understand why none of the following work: > data(iris) > fit <- manova(~ Species, data=iris) Error in lm.fit(x, y, offset = offset, singular.ok = singular.ok, ...) : incompatible dimensions > fit <- manova(iris[,1:4] ~ Species, data=iris) Error in model.frame(formula, rownames, variables, varnames, extras,
2012 Mar 19
1
car/MANOVA question
Dear colleagues, I had a question wrt the car package. How do I evaluate whether a simpler multivariate regression model is adequate? For instance, I do the following: ami <- read.table(file = "http://www.public.iastate.edu/~maitra/stat501/datasets/amitriptyline.dat", col.names=c("TCAD", "drug", "gender", "antidepressant","PR",
2011 Jun 21
1
Stepwise Manova
Hello all, I have a question on manova in R: I'm using the function "manova()" from the stats package. Is there anything like a stepwise (backward or forward) manova in R (like there is for regression and anova). When I enter: step(Model1, data=Mydata) R returns the message: Error in drop1.mlm(fit, scope$drop, scale = scale, trace = trace, k = k, : no 'drop1'
2003 Nov 22
3
summary.manova and rank deficiency
Hi all, I have received the following error from summary.manova: Error in summary.manova(manova.test, test = "Pillai") : residuals have rank 36 < 64 The data is simulated data for 64 variables. The design is a 2*2 factorial with 10 replicates per treatment. Looking at the code for summary.manova, the error involves a problem with qr(). Does anyone have a suggestion as to how to
2006 Mar 30
2
Unbalanced Manova
Dear all, I need to do a Manova but I have an unbalanced design. I have morphological measurements similar to the iris dataset, but I don't have the same number of measurements for all species. Does anyone know a procedure to do Manova with this kind of input in R? Thank you very much, Naiara. -------------------------------------------- Naiara S. Pinto Ecology, Evolution and Behavior 1
2003 Jun 10
1
Bootstraping with MANOVA
Hi, Does anyone know what the error message mean? > Boot2.Pillai <- function(x, ind) { + x <- as.matrix(x[,2:ncol(x)]) + boot.x <- as.factor(x[ind, 1]) + boot.man <- manova(x ~ boot.x) + summary(manova(boot.man))[[4]][[3]] + } > > man.res <- manova(as.matrix(pl.nosite) ~ + as.factor(plankton.new[,1]))$residuals > boot2.plank <-