similar to: Special characters: plus/minus

Dear R-people: François Michonneau's method to obtain the special character plus/minus works on Windows 2000 professional. Many Thanks to François for his work! Phil Smith Centers for Disease Control and Prevention Atlanta, GA _____ From: François MICHONNEAU [mailto:francois.michonneau@gmail.com] Sent: Monday, March 20, 2006 1:58 PM To: r-help@stat.math.ethz.ch; Smith, Phil

I want to put the "plus or minus" symbol into a character variable, so that this can be turned into a factor and be displayed in the "strip" of a faceted ggplot2 plot. A very nice solution, thanks to Professor Ripley's post of Nov 16, 2008; 3:13pm, visible at http://r.789695.n4.nabble.com/Symbols-to-use-in-text-td874239.html and subsequently

Hi List, I want to print ? in a lattice graph label. This works in windows, but the linux version has problems - it cannot translate the character. Error is "invalid input in mbcsToLatin1". I use the standard encoding and also dev.print(file="filename",dev=pdf, encoding="PDFDoc.enc") I am afraid I don't know enough about the linux font encodings to figure out

Hi R-Help: I want to produce a map of the US with different colors for selected states. I installed the map package, and then used: library(maps) I can see that by using map( 'state' ) you get the state boundaries, also. How do I fill in different colors for the different states? I see there is a col parameter for map, but can't see how to get it to work! Please reply

I am using a similar dataset to the following: a= c("Fruits", "Adam","errorA", "steve", "errorS", "apples", 17.1,2.22, 3.2,1.1, "oranges", 3.1,2.55, 18.1,3.2 ) a_table=data.matrix(t(matrix(a,nrow=5))) I would like to plus minus every second column starting from errorA (using xtable/ hmisc) example output (ignoring

Hi R people: I'm trying to set the dimnames of a data frame called "ests" and am having trouble! First, I check to see if "ests" is a data.frame... > is.data.frame( ests ) [1] TRUE ... and it is a data frame! Next, I try to assign dimnames to that data frame.... > dimnames( ests )[[ 1 ]] <- as.character( ests$stfips ) Error in

Dear R-users, please consider the following minimal example: \documentclass[a4paper,titlepage,onecolumn,12pt]{article} \usepackage[italian]{babel} \usepackage{amssymb} \usepackage[utf8x]{inputenc} \usepackage[pdftex]{graphicx} \begin{document} <<label=test, echo=FALSE, results=tex>>= df.data1 <- cbind.data.frame(A = rnorm(18), B =factor(rep(LETTERS[1:6],

I am using a similar dataset to the following: a= c("Fruits", "Adam","errorA", "steve", "errorS", "apples", 17.1,2.22, 3.2,1.1, "oranges", 3.1,2.55, 18.1,3.2 ) a_table=data.matrix(t(matrix(a,nrow=5))) I would like to highlight the smallest value in the Adam and Steve columns and, also plus and minus the errors

Dear R devolepers! Wouldn't you change src/main/devPS.c file (patch will follow). Problem is with minus sign in ps output. The original code forces the name /minus to the character number 45 (-). But /minus symbol is not defined in standard Adobe encoding and (even worse) is not defined in most type1 fonts (where the name /hyphen is used instead), in this case you will have an empty

Dear R devolepers! Wouldn't you change src/main/devPS.c file (patch will follow). Problem is with minus sign in ps output. The original code forces the name /minus to the character number 45 (-). But /minus symbol is not defined in standard Adobe encoding and (even worse) is not defined in most type1 fonts (where the name /hyphen is used instead), in this case you will have an empty

Hi R Community: I want to take the difference in two dates: dt2 - dt1. But, I want the answer in months between those 2 dates. Can you advise me? Please respond to: pzs6 at cdc.gov Thank you! Phil Smith Centers for Disease Control and Prevention

dear reserachers, I am looking for a expression about a special symbol (±) in a Legend and add on front of "Mean ± SD" the symbol of bracket sorry if the example is not great disptest <- matrix(rnorm(10),nrow=10) disptest.means<- rowMeans(disptest) plot(1:10,disptest.means) dispersion(1:10,disptest.means,(disptest.means+disptest ),(disptest.means-disptest

Hi: I am using step.glm() as follows: form1 <- as.formula(haspdata ~ 1) lg.mod1 <- glm ( formula=form1, data=st.mtx, family=binomial , na.action=na.omit ) upper <- as.formula( haspdata ~ ( c5+childnm+educ1+incpov1+marital+msa+racekid+racemom+sex+shotcard )^2) lower <- as.formula(haspdata~1) lst <- list( upper=upper , lower=lower ) form1a.step <- step(lg.mod1, scope=lst

Here is a question from an old guy: I want to use the boxplot function as follows: boxplot( p.prop ~ R + bins ) This command makes nice boxplot for the factor "R" crossed with the factor "bins". I am having alot of trouble getting control of the labels on the X axis. I want to control it more by specifying what the labels are, controling the 'size' of those

Hi Everyone, as part of a larger script, I need to insert the result of a simple minus operation into an if statement. I have noticed that the precision that appear on the screen is not the precision in which R stores the result of the minus operation, and that this change alters the result of the if statement. For example, when running this simple script:   > a=0.90 > b=0.95 >

Hello, since a couple of days I'm trying hard to elicit a certain thing out of the Sweave function of R. Unfortunately I'm quite unsuccessful. It's only about a small, ridiculous minus sign, which does not appear in the final pdf of a latex file, if I try to incorporate the Computer- Modern fonts into the plot. It seems, that R uses different encodings for minus signs, which are put

Dear Sweave users, Could you help me to find a way to place Sweave output files in a subdirectory of the currentfolder without giving them a subname? If the option "prefix.string=foo/" is used, all files are placed in this folder, but begin with an hyphen-minus, which makes it difficult to work with them. If the option "prefix=FALSE" is used, then files won't be placed in

How to do this in an elegant way formatrix/data frame/zoo? mat= 1 2 3 4 5 6 7 8 9 vector= 1 2 3 result= 0 1 2 2 3 4 4 5 6 ie 1-1 2-1 3-1 4-2 5-2 6-2 7-3 8-3 9-3 Thanks in advance. _________________________________________________________________ 08 [[alternative HTML version deleted]]

I used the following to assign each row the group average, where w is the new group average variable, x is the variabale to be averaged, and g is the nominal group indicator: w <- ave(x,g) Now I want to calculate the group average, but WITHOUT each row's value of x. Is there an easy way to do this? I'm sure I'm missing something obvious here, but for the life of me I can't

For most cases, I''ve got search working in Rails as follows: ## controller: term = params[:search][:term] @results = MyModel.find_by_contents "#{term}*" The ''*'' character is appended to the search term so that searches match anything that begins with ''term''. For the most part, this is great, but let''s say term is equal to