similar to: click on graph and select data points?

Dear R-users, I would like to process some spectroscopic data with R, and I was hoping some people might have some example code on how to do this. I would like to be able to do the following things: * Detect outlier-spectra -> This can be done by using scoreplot from the pls package * Determine the range of the spectrum to be used -> For this, I should be able to calculate the regression

Hi I installed R 2.2.0 from source and I have the packages for tcl and tk installed on my system, but the package tcltk says, when I try to load the library tcltk: Tcl/Tk support is not available on this system. Are there any settings / variables which I have to set so that R recognises that Tcl/Tk support is installed on the system? Rainer -- NEW TELEPHONE NUMBER Tel: +27 - (0)72 808

How can I write a text, such as a result of a function or an explanation to a graphic device? When I try plot, I'm unable to reduce the axes. Greetings torsten

Hi! I'm translating some code from Matlab to R and I found a problem. I need to translate Matlab's function 'lsqnonlin' (http://www-ccs.ucsd.edu/matlab/toolbox/optim/lsqnonlin.html) into R, and at the beginning I thought it would be the same as R's 'optim'. But then I looked at the definition of 'lsqnonlin' and I don't quite see how to make

Hi I have a square matrix Ainv of size N-by-N where N ~ 1000 I have a rectangular matrix H of size N by n where n ~ 4. I have a vector d of length N. I need X = solve(t(H) %*% Ainv %*% H) %*% t(H) %*% Ainv %*% d and H %*% X. It is possible to rewrite X in the recommended crossprod way: X <- solve(quad.form(Ainv, H), crossprod(crossprod(Ainv, H), d)) where quad.form() is a little

Hello all I am playing with R for to make a animated GIF. any suggestions, improvements are welcome :-) case somebody could help me, i thanks! Cleber N. Borges ( klebyn ) my objective: (steps TODO) ------------------- 1) to save PNG files; -----> i don't know the best way to make this; 2) transform the PNG files into GIF files (easy! no problem! ... i think ...) 3)

Hi, I?m trying to get smooth curves connecting points in a plot using "spline" but I don?t get what I whant. Eg.: x<-1:5 y <- c(0.31, 0.45, 0.84, 0.43, 0.25) plot(x,y) lines(spline(x,y)) Creates a valley between the first and second points, then peaks at 3rd, and another valley between 4th and 5th. I?m trying to get a consistently growing curve up to the 3rth point and then a

Dear All, I'm trying to read a text data file that contains several records separated by a blank line. Each record starts with a row that contains it's ID and the number of rows for the records (two columns), then the data table itself, e.g. 123 5 89.1791 1.1024 90.5735 1.1024 92.5666 1.1024 95.0725 1.1024 101.2070 1.1024 321 3 60.1601 1.1024 64.8023 1.1024 70.0593

Hello All, Is there any R function out there to turn a multi-way contingency table back to a flat file table of individual rows and attribute columns.? Thanks! marco --------------------------------- [[alternative HTML version deleted]]

Hi, I have a string vector, say, x <- "a", "aab" and anther string vector, say, y <- "a", "aa", "aab", "aabc". Is there any R function to get the indices of y for the elements of x, that is, foo(x, y) will give me the index vector c(1, 3)? I know i can combine apply() and grep("^aab$", y) to do it. But is there any

Hello, I have two dataframes of the following structures: str(a) `data.frame': 1354896 obs. of 14 variables: $ V1 : int 0 1 2 3 4 5 6 7 8 9 ... $ V2 : int 0 0 0 0 0 0 0 0 0 0 ... $ V3 : int 74 12305 103 12337 46 57 12446 90 12097 79 ... $ V4 : num 11.8 1529.2 17.8 1579.4 6.7 ... $ V5 : int 88 11040 104 11557 56 58 11040 74 10991 81 ... $ V6 : num 15.5 1921.3 20.3

Hello everyone, does anybody know how to increase the decimal places that R uses to calculate something. I think that in default R uses 6 decimal places but I need 12. Thank you very much! Best regards, Maja! --

Hello. In the file list.txt, I have the name of n files in data frame format. I want to make an image for each file and save the images in pdf format. To do this, I do the following: llista = scan(file="list.txt",what=list(nom="")) for (file.name in llista[[1]]){ aux=read.table(file=file.name) aux=as.matrix(aux) pdf() image(aux)

I am ashamed to be asking this question, but I couldn't find the solution anywhere. Searching for "if" and "R" is not very productive... I cannot get a simple if statement to work. I have data on college students. I want to make a string variable that has the names of the years. That is, when the year variable i is equal to 1, I want to have a variable called years

Dear friends, suppose i want to do the following caulation for 100 times, how to put the results of x , y and z into the same dataframe/dataset? x<-runif(1) y<-x+1 z<-x+y thanks in advance! -- Kind Regards, Zhi Jie,Zhang ,PHD Department of Epidemiology School of Public Health Fudan University Tel:86-21-54237149 [[alternative HTML version deleted]]

Are there ways to load a csv file without row.names by read.csv? Thanks. [[alternative HTML version deleted]]

Dear mailing list, may some one be kind to help me solve following problem. I am trying to write a code that will combine two tables "x" and "y". The first columns of both tables are unique identification for the rows. The first column of table "X" is a sub set of the first column of "Y". I need to find the matching rows in both tables by looking on their

Hi there. I have the following graph: http://www.nabble.com/file/p10928148/map.jpg However, some datapoints occur at the same place as other datapoints and are so layered on top of each other. I would like to know if there is any possible way in which I could view those datapoints that are layered on top of each other ...maybe by rotating using latitude to show the datapoints underneath (but

Hi! I'd like to plot things with axes going from the highest to the lowest value, so that e.g. high values on the xaxis are plotted to the left and low values to the right. Could anyone tell me how this is done? I couldn't find anything in the documentation. Thanks a lot! Silli

Hi All, I want to use "hist" to get the relative frequency plot. But the range of ylab is greater than 1,which I think it should be less than 1 since it stands for the probability. Here is my code: x<-c(1,1,1,0,0,1,1,5,1,1,0,1,1,0,1,0,1,1,0,0,1,1,1,1,1,1,1,1,1,4,1,0,2,1,1,1 ,1,1,0,0,1,0,1,1,1,1,1,1,1,1,1)