similar to: POSIX time zone codes

Dear Listers, Apologize to pile up on the 'tz' issue in POSIX objects. I have a 'simple' thing on which I must make up my mind but cannot do it from the existing R-help threads. I am currently working on dog telemetry in China, and download time information from GPS collars. I would like to set up the corresponding POSIXxx variables in R to a given time zone. Eg Pekin

Say you have a POSIX object that is in UTC. How do you change the values to another timezone? If I do this: times <- strptime(times, "%H:%M:%S") times1 <- as.POSIXct(times, tz="UTC") times2 <- as.POSIXct(times, tz="CDT6CST") times1 id UTC, but times2 is still UTC, not CTD. Why? Is the only was to change time zones to add seconds to POSIX objects?

On Sun, 11 Jan 2004, Dirk Eddelbuettel wrote: > On Fri, Jan 09, 2004 at 06:01:27PM +0100, christoph.schmutz@meteoschweiz.ch wrote: > > Full_Name: Christoph Schmutz, MeteoSchweiz, Switzerland > > Version: R1.7.1, R1.8.1 > > OS: windows2000, solaris sunOS 5.8 > > Submission from: (NULL) (141.249.133.6) > > > > > > > > I'm not sure if I

Can anyone think of a way to create a pretty() sequence that excludes zero? Or a way to remove the zero from a sequence after using pretty()? Thanks, - Jason Jason Horn Boston University Department of Biology 5 Cumington Street Boston, MA 02215 jhorn@bu.edu office: 617 353 6987 cell: 401 588 2766 [[alternative HTML version deleted]]

Full_Name: Christoph Schmutz, MeteoSchweiz, Switzerland Version: R1.7.1, R1.8.1 OS: windows2000, solaris sunOS 5.8 Submission from: (NULL) (141.249.133.6) I'm not sure if I don't get the clue, but please consider this: > strptime("19930870150","%Y%j%H%M") [1] "1993-03-28 01:50:00" > strptime("19930870250","%Y%j%H%M") [1]

Sorry to ask such a simple question, but I can't find the answer after extensive searching the docs and the web. How do you remove a component from a list? For example say you have: lst<-c(5,6,7,8,9) How do you remove, for example, the third component in the list? lst[[3]]]<-NULL generates an error: "Error: more elements supplied than there are to replace" Also,

I have a vector of POSIX times/dates (called "times") that I want to plot. But I'm having trouble because R reports the length of the vector incorrectly. Can someone help me figure out what's going on here? This code.... print(times) print(class(times)) print(length(times)) Produces this... . . . [355] "2006-03-06 18:34:00" "2006-03-06 18:32:00"

Dear R-help, I was trying to convert a date and time record extracted from a fortran subroutine I worte and I encounter some problem. The data read in time and date in a format like "2000-05-11_01:00:00.0000" in fortran output. It is in GMT. I need to convert it to CST (GMT+8). I did the following steps. > cdate [1] "2000-05-11_01:00:00.0000\005\003" # I am not sure

Hi all, This is a question for any of you who use R.app (OS X). Is there any way to resize the quartz plot window from within R? I know that you can resize the window by dragging the corner of the window, and fro the preferences panel. But is there a way to specify the window size from the console? I want to specify the size of the plot window from inside an R function. Also a

Hi all, I'm new to the list here, and I have what I think is a simple question. Using the "circular" package, is there a way to plot the mean and variance on top of a rose diagram or other plot of the data? Thanks in advance... - Jason Jason Horn Boston University Department of Biology 5 Cumington Street Boston, MA 02215 jhorn@bu.edu office: 617 353 6987 cell: 401 588

Dear R-helpers, We marked 6000 leaves from 5 SPECIES - 10 individuals/species - in two different TREATMENTs: a control and a dry-plot from which 50% of incoming precipitation was excluded. We followed those leaves for 42 months and noted the presence and absence at each visit. I then carried out a Cox Harzard model to see differences in leaf mortality between parcels and among species over time:

I am working with time-date data to plot temporal activity. I would like to create a "template" to repeat the date and time for all potential data sets that may have differing time zone origins. Reading the > ?strptime help section I note that time zone is a variable to add. Looking at the output of a sample data set Species Location Date Time 1 Sppaaa One 1/13/2009

I am having trouble getting RMySQL working with R. It did at one point, work with an older 1.x version of R, but now with R2.2.1, I am getting the following messages on my OS X 10.4.5 system: RS-DBI driver warning: (MySQL mismatch between compiled version 4.0.24 and runtime version 4.1.14) if I then try to run any further db commands such as dbConnect, R crashes with a bus error. When

I'd like to replace a value in a data frame with an NA, but can't figure out how. For example, say you have a<-c(1,2,3,4) b<-c(5,6,7,8) data<-data.frame(a,b) Now, how would you set the third row of the second column ( data [[3,2]] ) to NA? I have tried all types of permutations with is.na, including is.na<- data[[3,2]], which does not work. Thanks

Does anyone know how to get a vector of column sum from a data frame? You can use colSums(), but this gives you a object of type "numeric" with the column labels in the first row, and the sums in the second row. I just want a vector of the sums, and I can't figure out a way to index the "numeric" object. Thanks!

Can anyone tell me how to select just one row of a data frame? Say I want just the third row, what would be the syntax? Every notation I try just gives me columns. Thanks - Jason

Hi. I frequently convert date and time data to and from character representations. I'm frustrated with chron, because 'seconds' are required to create a time object (my input data never has seconds). More importantly, I cannot make chron print the format 12/30/2006 (which my output data requires). I really like the format flexibility of strftime() and strptime(), but of course

Hello, Following Dirk's post here: https://github.com/Rdatatable/data.table/issues/1619 we would like to clarify if this is the right behaviour, and if so, the rationale behind it. Here's the summary (thanks to Dirk and Joshua): Sys.setenv("TZ"="America/Chicago") dates = as.Date("2016-03-02") + (0:3)*7 # four Wednesdays # [1] "2016-03-02"

> Date: Tuesday, June 23, 2015 03:48:36 PM -0400 > From: Jonathan Billings <billings at negate.org> > > On Tue, Jun 23, 2015 at 01:56:13PM -0500, g wrote: >> each and every time i run yum or yumex, system time is advanced >> by 5 hours. >> >> this has gone on thru several updates, maybe even upgrades. >> >> centos = 6.6 current >> yum

I'm rehashing/reliving my issues from 2010: http://www.dovecot.org/list/dovecot/2010-October/053528.html In short, when calling deliver from vdelivermail (or procmail), and delivering via NFS to Maildir, the timestamp on the file is GMT.? If procmail or vdelivermail completely handle the email, the timestamp is CST. The server is set to CST. What's changed from the original issue??