Displaying 20 results from an estimated 2000 matches similar to: "warnings in glm (logistic regression)"
2005 Oct 27
2
how to predict with logistic model in package logistf ?
dear community,
I am a beginer in R , and can't predict with logistic model in package
logistf,
could anyone help me ? thanks !
the following is my command and result :
>library(logistf)
>data(sex2)
>fit<-logistf(case ~ age+oc+vic+vicl+vis+dia, data=sex2)
>predict(fit,newdata=sex2)
Error in predict(fit, newdata = sex2) : no applicable method for
"predict"
2005 Feb 07
3
problem with logistic regression
Hi,
we try to do a logistic regression with the function glm.
But we notice that this function don't give the same results as the SAS proc
catmod (differents estimate given).
We try to change the contrast on R system with:
> options(contrasts=c(unordered="contr.SAS",ordered="contr.poly"))
We also try with brlr and logistf functions.
Unfortunately, the estimate
2013 Feb 27
1
Separation issue in binary response models - glm, brglm, logistf
Dear all,
I am encountering some issues with my data and need some help.
I am trying to run glm analysis with a presence/absence variable as
response variable and several explanatory variable (time, location,
presence/absence data, abundance data).
First I tried to use the glm() function, however I was having 2 warnings
concerning glm.fit () :
# 1: glm.fit: algorithm did not converge
# 2:
2006 Jan 12
1
Firths bias correction for log-linear models
Dear R-Help List,
I'm trying to implement Firth's (1993) bias correction for log-linear models.
Firth (1993) states that such a correction can be implemented by supplementing
the data with a function of h_i, the diagonals from the hat matrix, but doesn't
provide further details. I can see that for a saturated log-linear model, h_i=1
for all i, hence one just adds 1/2 to each count,
2006 Jan 29
1
extracting 'Z' value from a glm result
Hello R users
I like to extract z values for x1 and x2. I know how to extract coefficents
using model$coef
but I don't know how to extract z values for each of independent variable. I
looked around
using names(model) but I couldn't find how to extract z values.
Any help would be appreciated.
Thanks
TM
#########################################################
>summary(model)
Call:
2005 Jun 16
1
logistic regression - using polys and products of features
Hi
I can get all my features by doing this:
> logistic.model = glm(similarity ~ ., family=binomial, data =
cData[3001:3800,])
I can get the product of all my features by this:
logistic.model = glm(similarity ~ . ^ 2, family=binomial, data =
cData[3001:3800,])
I don't seem to be able to get polys by doing this:
logistic.model = glm(similarity ~ poly(.,2), family=binomial, data
2006 Aug 31
3
what's wrong with my simulation programs on logistic regression
Dear friends,
I'm doing a simulation on logistic regression model, but the programs can't
work well,please help me to correct it and give some suggestions.
My programs:
data<-matrix(rnorm(400),ncol=8) #sample size is 50
data<-data.frame(data)
names(data)<-c(paste("x",1:8,sep="")) #8 independent variables,x1-x8;
#logistic regression model is
2010 Mar 08
1
error_hier.part
Hi everyone,
BEGINNER question:
I get the error below when running hier.part. Probably i´m doing
something wrong.
Error in glm.fit(x = X, y = Y, weights = weights, start = start, etastart =
etastart, :
object 'fit' not found
In addition: Warning messages:
1: In glm.fit(x = X, y = Y, weights = weights, start = start, etastart =
etastart, :
no observations informative at iteration 1
2008 May 12
4
Several questions about MCMClogit
Hello everybody,
I'm new to MCMClogit. I'm trying to use MCMClogit to fit a logistic
regression model but I got some warnings I can't understand.
My input data X is 32(tissue sample)*20(genes) matrix, each element in this
matrix corresponds to the expression value of one particular gene in one of
32 samples. And the Y presents the corresponding classes (0-non cancer,
1-cancer)
2005 Aug 05
1
question regarding logit regression using glm
I got the following warning messages when I did a
binomial logit regression using glm():
Warning messages:
1: Algorithm did not converge in: glm.fit(x = X, y =
Y, weights = weights, start = start, etastart =
etastart,
2: fitted probabilities numerically 0 or 1 occurred
in: glm.fit(x = X, y = Y, weights = weights, start =
start, etastart = etastart,
Can some one share your thoughts on how to
2010 Apr 26
2
Unexpected warnings from summary() on mcmc.list objects
I am trying to get summary statistics from WinBUGS/JAGS output in the
form of mcmc.list objects, using the summary() function. However, I
get odd warning messages:
Warning messages:
1: In glm.fit(x = X, y = Y, weights = weights, start = start, etastart
= etastart, :
algorithm did not converge
2: In glm.fit(x = X, y = Y, weights = weights, start = start, etastart
= etastart, :
algorithm did
2006 Jan 15
1
problems with glm
Dear R users,
I am having some problems with glm. The first is an error message "subscript out of bounds". The second is the fact that reasonable starting values are not accepted by the function.
To be more specific, here is an example:
> success <- c(13,12,11,14,14,11,13,11,12)
> failure <- c(0,0,0,0,0,0,0,2,2)
> predictor <- c(0,80*5^(0:7))
>
2005 Apr 13
1
logistic regression weights problem
Hi All,
I have a problem with weighted logistic regression. I have a number of
SNPs and a case/control scenario, but not all genotypes are as
"guaranteed" as others, so I am using weights to downsample the
importance of individuals whose genotype has been heavily "inferred".
My data is quite big, but with a dummy example:
> status <- c(1,1,1,0,0)
> SNPs <-
2005 Jan 28
3
GLM fitting
DeaR R-useRs,
I'm trying to fit a logist model with these data:
> dati
y x
1 1 37
2 1 35
3 1 33
4 1 40
5 1 45
6 1 41
7 1 42
8 0 20
9 0 21
10 0 25
11 0 27
12 0 29
13 0 18
I use glm(), having this output:
> g<-glm(y~x,family=binomial,data=dati)
Warning messages:
1: Algorithm did not converge in: glm.fit(x = X, y =
Y, weights = weights, start = start, etastart =
2009 Mar 27
1
deleting/removing previous warning message in loop
Hello R Users,
I am having difficulty deleting the last warning message in a loop so that the only warning that is produced is that from the most recent line of code. I have tried options(warn=1), rm(last.warning), and resetting the last.warning using something like:
> warning("Resetting warning message")
This problem has been addressed in a previous listserve string,
2007 Dec 29
1
COMPAR.GEE error with logistic model
Hello,
I am trying to run the APE program COMPAR.GEE with a model containing a
categorical response variable and a mixture of continuous and categorical
independent variables. The model runs when I have categorical (binary)
response and two continuous independent variables (VAR1 and VAR2), but when
I include a categorical (binary) independent variable (VAR3), I receive the
following output with
2005 Jul 02
2
Is it possible to use glm() with 30 observations?
I have a very simple problem. When using glm to fit
binary logistic regression model, sometimes I receive
the following warning:
Warning messages:
1: fitted probabilities numerically 0 or 1 occurred
in: glm.fit(x = X, y = Y, weights = weights, start =
start, etastart = etastart,
2: fitted probabilities numerically 0 or 1 occurred
in: glm.fit(x = X, y = Y, weights = weights, start =
start,
2009 Dec 30
1
lm() and factors appending
How for the love of god can I prevent the lm() function from padding on to
my factor variables?
I start out with 2 tables:
Table1
123123
124351
...
626773
Table2
Count,IS_DEAD,IS_BURNING
1231,T,F
4521,F,T
...
3321,T,T
Everything looks fine when I import the data.
then we get a
oh_crap <- lm(table1 ~ Count + IS_DEAD + IS_BURNING, table2)
Magically when I look at my oh_crap coefficents
2004 Jan 25
3
warning associated with Logistic Regression
Hi All,
When I tried to do logistic regression (with high maximum number of
iterations) I got the following warning message
Warning message:
fitted probabilities numerically 0 or 1 occurred in: (if
(is.empty.model(mt)) glm.fit.null else glm.fit)(x = X, y = Y,
As I checked from the Archive R-Help mails, it seems that this happens when
the dataset exhibits complete separation. However, p-values
2009 May 27
1
Warning message as a result of logistic regression performed
I am sorry if this question sounds basic but I am having trouble understanding a warning message I have been receiving in R after attempting logistic regression.
I have been using the logistic regression function in R to analyse a simulated data set. The dependent variable "failure" has an outcome of either 0 (success) or 1 (failure). Both the independent variables have been previously