similar to: What does this command "~" mean?

Hello Given the following data for a data set called airquality. To identify the nature of the objects from the data set airquality example "Ozone" would it be best to use the command is. like is.character(airquality$Ozone) ....... I tried attributes(airquality$Ozone) but it came up null. Would there be a better way to identify these objects. Thanking you in advance for your

I think I've gotten my Emacs/Sweave/R system set up correctly, thanks to Vincent and Jim, but I haven't been successful getting my first document produced. I'm trying to use one of Friedrich Leisch's examples, http://www.ci.tuwien.ac.at/~leisch/Sweave/example-1.Snw. I cut and pasted the text into a document sweaveexample.Rnw in Emacs. It seemed to be processed successfully with R:

>>>>> peter dalgaard <pdalgd at gmail.com> >>>>> on Mon, 26 Jun 2017 13:43:28 +0200 writes: > This seems to be due to changes made by Martin Maechler in > 2008. Presumably this fixed something, but it escapes my > memory. Yes: The change set (svn -c46441) also contains the following NEWS entry BUG FIXES o

> library(reshape2) > x = melt(airquality, id=c('month', 'day')) With reshape I can cast with multiple functions: > library(reshape) > cast(x, month+variable~., c(mean,sd)) month variable mean sd 1 5 ozone 23.615385 22.224449 2 5 solar.r 181.296296 115.075499 3 5 wind 11.622581 3.531450 4 5 temp 65.548387

An Sweave file, 'test.Rnw': \documentclass{article} \title{Sweave minimal} \author{MK} \begin{document} \maketitle We try Sweave: <<1>>= data(airquality) summary(airquality) x <- airquality[1, 1] @ I try Sexpr: \Sexpr{x} We plot: \begin{center} <<2, fig=TRUE, echo=FALSE >>= boxplot(Ozone ~ Month, data = airquality) @ \end{center} \end{document} I check the

Dear R-devel list, I realized that removing a predictor in lm through the "-"'s operator in formula() does not affect the complete cases that are considered. A minimal example is: summary(lm(Wind ~ ., data = airquality)) # 42 observations deleted due to missingness summary(lm(Wind ~ . - Ozone, data = airquality)) # still 42 observations deleted due to missingness, even if only 7

I would like to add a column to the airquality dataset that contains the date 1950-01-01 in each row. This method does not appear to work: > attach(airquality) > data1 <- transform(airquality,Date=as.Date("1950-01-01")) Error in data.frame(list(Ozone = c(41L, 36L, 12L, 18L, NA, 28L, 23L, 19L, : arguments imply differing number of rows: 153, 1 I can't decipher what

Hi All, I've reproduced the example from Prof. Friedrich Leisch's webpage. When I write sweave("Example-1.Snw") OR sweave("Example-1.Rnw"), (yes, I renamed them). I get the following error: Writing to file example-1.tex Processing code chunks ... 1 : echo term verbatim Error: chunk 1 Error in library(ctest) : there is no package called 'ctest' Also while

My apologies in advance for my thickness but I can't seem to solve the following, seemingly simple, data manipulation problem: I have a data frame that contains multiple factors and multiple continuous response variables, but duplicates of some factor combinations. The duplicates contain bad data, so I would like to eliminate the duplicates. I would like to retain the entire rows

I'm trying to understand how to set graphical parameters for trees created with the party package.  For example take the following code:   library(party)     data(airquality)     airq <- subset(airquality, !is.na(Ozone))     airct <- ctree(Ozone ~ ., data = airq,                    controls = ctree_control(maxsurrogate = 3))     plot(airct)   My problem is, I've got a ctree that has

Hi, I'm experimenting with random forests and want to perform a binary classification task. I've tried some of the sample codes in the help files and things run, but I get a message to the effect 'you don't have very many unique values in the target - are you sure you want to do regression?' (sorry, don't know exact message but r is busy now so can't check). In

> On Jun 21, 2017, at 9:11 AM, Evan Cooch <evan.cooch at gmail.com> wrote: > > Suppose I have the following sort of dataframe, where each column name has a common structure: prefix, followed by a number (for this example, col1, col2, col3 and col4): > > d = data.frame( col1=runif(10), col2=runif(10), col3=runif(10),col4=runif(10)) > > What I haven't been able to

Hi all, We are facing a problem while introducing ourselves to Reshape package use. Melt seems to work fine, but cast fails when we use mean as fun.aggregate. As you see here, length and sum work fine, but mean throws this same error whatever dataset we use. > cast(aqm, month ~ variable, length) month ozone solar.r wind temp 1 5 26 27 31 31 2 6 9 30 30

Gracias a los tres, Raúl, Marcelino y Carlos. Lo del "get" de Marcelino me da la respuesta a lo que yo exactamente preguntaba, y funciona, pero ahora tengo problemas con el for, por lo que probablemente recurra al eval parse de Raúl o Carlos, que ya tienen el for. Aún así, lo intento 1º con el get. Con subset(df, subset=get(GT[i])>0) el problema es que en el for hago un

Gracias Marcelino. Si, (i in 1:length(GT)), lo he utilizado mil veces, pero se me sigue olvidando de una vez a otra. Lo iba a mirar, pero me centré primero en que me hiciera bien el mapa. He probado el for y me da este error: Error in aes(x = lon, y = lat, color = get(GT[i]), size = 2) + scale_colour_gradient(low = ("white"), : non-numeric argument to binary operator

Hi all I know this must be an easy one so sorry for the trouble. I would like to select a list of variables within a factor The following example is given in help for subset: subset(airquality, Temp > 80 select = c(Ozone, Temp)) So how do I select all temperatures of 90 and 80 ie Temp = c(80,90) I would appreciate your help. Kind regards andy Andrew McFadden MVS BVSc Incursion

This must have been there for a while> In the datasets package, the help for airquality says: A data frame with 154 observations on 6 variables. But: > str(airquality) 'data.frame':??? 153 obs. of? 6 variables: ?$ Ozone? : int? 41 36 12 18 NA 28 23 19 8 NA ... ?$ Solar.R: int? 190 118 149 313 NA NA 299 99 19 194 ... ?$ Wind?? : num? 7.4 8 12.6 11.5 14.3 14.9 8.6 13.8 20.1 8.6

Estimados -Este paquete parece que saca un reporte bastante completo, a mi me da error y no comprendo porque,por favor audenme en esto library(DataExplorer) create_report(iris) create_report(airquality, y = "Ozone") error que me da Error: pandoc document conversion failed with error 99 TENGO INSTALADO PANDOC

Hola, parece que el problema está relacionado con la versión de Pandoc. La última da problemas, según parece: https://github.com/boxuancui/DataExplorer/issues/119 DataExplorer failed on the iris and mtcars data.frames on 3 of 4 computers today. It took hours, but the problem seems related to newer versions of Pandoc. Only Pandoc 2.6 works with DataExplorer. It will fail with newer versions 2.7

[ R 1.6.1 ] PROBLEM The plot of the appended code does produce a postscript file which is not interpretable by gv under Linux. REMARK If the srt argument is commented out or set to a constant like 45 or 90, the ps file becomes interpretable. CODE xytest <- function( ... ){ with( airquality, { print( xyplot( Ozone ~ Temp | Month , panel