similar to: question about "system" command

Displaying 20 results from an estimated 400 matches similar to: "question about "system" command"

2006 Jan 26
1
DOS command using "system"
HI R users I have one question for using DOS command through "system" I like to delete a file that is located at C:\Program Files\DOSPROGRAM\input.dat I can use a DOS command "del" on Dos prompt like this C:\Documents and Settings> del "C:\Program Files\DOSPROGRAM\input.dat" to delete input.dat file. When I try to do the same thing on R using "system"
2006 Feb 05
3
reading in a tricky computer program output
Hi R user I need to read in some values from a computer program output. I can't change the output format because the developer of the program doesn't allow to change the format of output. There are two formats. First one looks like this if I have 10 variables, ------------------------------------------------------------------------------------------------------ [ 1]
2006 Nov 06
3
CPU or memory
Hi R users Having both a faster CPU and more memory will boost computing power. I was wondering if only adding more memory (1GB -> 2GB) will significantly reduce R computation time? Taka, _________________________________________________________________ Get FREE company branded e-mail accounts and business Web site from Microsoft Office Live
2006 Feb 05
2
generating strings in a tricky order
Hi R users I like to generate some strings (a character vector) in a special way like If i have 5 variables "002.001", "003.001", "003.002", "004.001", "004.002", "004.003", "005.001", "005.002", "005.003", "005.004" so the created string vector's elements are "002.001",
2006 Feb 18
2
figure out whether 1 is between two numbers
Hi R users I have two variables (X and Y) X <- rnorm(100,.7,.5) Y <- rnorm (100,.3,.1) I like to know whether 1 is between each pair of X and Y or not. Thanks TM
2006 Jul 11
2
0* log(0) should be zero but NaN
Dear R-users >prob <- c(0.5,0.4,0.3,0.1,0.0) >cal <- prob * log(prob,base=2) >cal [1] -0.5000000 -0.5287712 -0.5210897 -0.3321928 NaN Is there any way to change NaN to zero ? I did come up with this by applying Ripley's relpy to my previous question cal <-prob*log(pmax(prob,0.00000001),base=2) Any suggestion ? Thank you Taka
2006 Sep 19
2
looking for some functions to analyze a data set.
Hi R-users I have a data set. There are 10 products and the numbers of people who ranked the products. The format of the data set is productID rank1 rank2 rank3 rank4 rank5 rank6 rank7 rank8 rank9 rank10 ------------------------------------------------------------------------------------------------------- 1 10 2 3 3 6 4 2 5
2006 Feb 07
1
(second round) creating a certain type of matrix
Hi R users Here is what I got with help from Petr Pikal (Thanks Petr Pikal). I modified Petr Pikal's code to a little to meet my purpose. I created a function to generate a matrix generate.matrix<-function(n.variable) { mat<-matrix(0,n.variable,(n.variable/2)/5+1) #matrix of zeroes dd<-dim(mat) # actual dimensions mat[1:(dd[1]/2),1]<-1 #put 1 in first half of first column
2006 Aug 10
2
index.cond in xyplot
Dear R-users I have 5 dependent variables (y1 to y5) and one independent variable (x) and 3 conditioning variables (m, n, and 0). Each of the conditioning variables has 2 levels. I created 2*4 panel plots. xyplot(y1+y2+y3+y4+y5 ~ x | m*n*o,layout = c(4,2)) I would like to reorder the 8 panels. I tried to use index.cond (e.g., index.cond = list(c(1,3,2,4,5,7,6,8)) but it didn't work out.
2006 Jun 27
3
looking for a more efficient R code.
Dear R-users I have four simple linear models, which are all in the form of a*X+b The estimated parameter vectors are a <- c(1,2,3,4) b <- c(4,3,2,1) My goal is to draw a plot where x-axis is X (range from -100 to 100) and y-axis is the sum of all four linear models X <- seq(-100,100, length=10000) plot(X, sum of the four linear functions) I started with a function for summing
2006 Feb 14
2
combine elements of a character vector into a character
Hi R users I have a simple question to ask x <- c("a","b","c") x [1] "a" "b" "c" I like to have "abc" instead of having "a" "b" "c" I tried to use paste and other functions related to character. Is there any function (command) that enable me to combine elements of a character vector into
2006 Feb 04
2
saving a character vector
Hi R users I wrote a function that generates some character strings. generate.index<-function(n.item){ for (i in 1:n.item) { for (j in ((i+1):n.item)) { cat("i",formatC(i,digits=2,flag="0"),".",formatC(j,digits=2,flag="0"),"\n",sep="") } } } I
2006 Feb 07
1
creating a certain type of matrix
Hi R users I like to generate a certain type of matrix. If there are 10 variables, the matrix will have nrow=10, ncol=((10/2))/5+1. so the resulting matrix's dimension 10 by 2. If there are 50 variables the dimension of the resulting matrix will be 50 by 6. The arrangement of elements of this matrix is important to me and I can't figure out how to arrange elements. If I have 20
2006 Feb 02
1
table() command
Hi R users I am trying to get cross-tabulation tables using tables. All variables used are binary ones (0 and 1). Each time I constructed cross-tabluation table using a different variable pair (e.g., variable 1 and variable 2, variable 1 and variable 3 etc) In doing so, I ran into some problems i.V2 i.V1 1 0 17 1 33 For variable 2 (i.V2) there was no one belonging to ZERO
2006 Feb 17
1
extracting a element with a name attribute from a list
Hi R users I like to extract (or collect) a numeric element with a name from a list. Is there any way to extract just a numeric element without the name attached to the element. For example, >mylist Mantel-Haenszel chi-squared test with continuity correction data: table(mydata[, x]) Mantel-Haenszel X-squared = 8.3832, df = 1, p-value = 0.003787 alternative hypothesis: true
2006 Nov 08
1
a list with row.names = c(NA, 1000)
R users, I posted a message on "error message for row names". I looked at a saved file that has a list structure. I found that some of list components have row.names = c(NA, 1000). I compared what I did with R.2.3.0 with what I did with R.2.4.0. Previously, with R.2.3.0, row.names = c("1", "2", "3", ...., "1000"). What do I need to read the
2007 Jun 29
1
extracting df and MS values from aov
Dear R users, I would like to extract df and Mean Sq values. I tried several things (e.g., str(model1), names(model1)) but I can't find a way to extract these values. I also tried to search using RSiteSearch. Any help will be appreciated. Thanks Taka, model1<-aov(dv~iv.1*iv.2*iv.3) summary(model1) Df Sum Sq Mean Sq iv.1 1 3.200 3.200
2006 Jul 10
2
problem in my code
Dear R-users I wrote a small program for assigning a membership Here is my script sample.size <- 60 x <- rnorm(sample.size, 0, 1) y <- rnorm(sample.size, 0, 1) x.mean <- mean(x) y.mean <- mean(y) membership <- numeric(sample.size) for (i in 1:sample.size) { if ((x[i] < x.mean) && (y[i] < y.mean)) { membership[i]
2004 Mar 15
2
Speed issue
Hi all, I am trying to migrate a NetWare file server to samba (on Red Hat 9). My problem is that unfortunatelly samba is somehow painfully slow, when we run DOS programs from it on the client machines. The NetWare server is an ancient machine. P1, probably. The Samba server is P4 3G, 1G RAM, RAID mirroring, etc. We are running and old DOS program on the client machines, and when it's
2006 Jan 27
3
[Q] extracting lower diagonal elements of a matrix
Hi R users I like to extract lower diagonal elements of a matrix in such a way like, data[1,2], data[1,3], ...., data[5,6] are extracted from a matrix called 'data' This short script below is what I have written so far. ########################################## data <- matrix(rnorm(36,0,1),nrow=6) temp<-c() for (i in 1:(nrow(data)-1)) { for (j in (i+1):nrow(data)) {