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dear list, i have a problem using the par function. in one graphic device i want to have two plots so i tried to use par(mfror=c(1,2)). of course it worked out, but the height now is twice the length of the width for each single plot. what i actually wanted is something like par(mfrow=c(2,2)) where only the top (or bottom) two plots are drawn with entire length proportions of 1 to 2 ( height 1,

dear list, i have a matrix with missing values like 1 2 3 4 x x 2 2 2 2 2 2 2 x 2 the x stands for the missing value. i have to substitute it to NA substitute or replace didn´t work out, as they are for vectors only however matrix[,i] also didn´t work. can anybody tell me, who i can change these values easily? thanks stefan [[alternative HTML

I have a data set for different time intervals. The data has three comment lines before data for each time interval. For each time interval there are 500 data points. I want to change the dataset such that I have the following format: t1 t2 t3 ................ 0.00208 0.00417 0.00625 ................. a1 a2 a3 ...................

Hello R-user! I am running R 2.7.0 on a Power Book (Tiger). (I am still R and statistics beginner) I try to find the most important variables to divide my dataset as given in a categorical variable using randomForest. Is randomForest() able to deal with count data? Or is there no difference because only the ranks are used in the trees? Thanks in advance Birgit Birgit Lemcke Institut f?r

Hello R-user! I am running R 2.7.0 on a Power Book (Tiger). (I am still R and statistics beginner) I tried rfImpute (randomForest) and as far as I understood should it replace NA`s using a proximity matrix: > set.seed(100000) > Subset5Imputed<-rfImpute(Sex~., data=Subset5) ntree OOB 1 2 300: 11.78% 12.36% 11.21% ntree OOB 1 2 300: 12.07% 12.64%

R version 2.6.2 PowerBook G4 Hello R User, I try to perform an ANCOVA using the glm function. I have a dataset with continuous and categorical data (explanatory variables) and my response variable is also binary categorical. Fehler: NA/NaN/Inf in externem Funktionsaufruf (arg 4) Zus?tzlich: Warning messages: 1: In Ops.factor(y, mu) : - nicht sinnvoll f?r Faktoren (makes no sense for

Hello R-user! I am running R 2.7.0 on a Power Book (Tiger). (I am still R and statistics beginner) I try to find the most important variables to divide my dataset as given in a categorical variable. code: Test.rf4<-randomForest(Sex~.,na.action=na.roughfix, data=Subset4, importance=TRUE, proximity=TRUE, ntree=10000, do.trace=1000, keep.forest=FALSE) My dataset contains also ordered

Hello R-user community! I am running R 2.7.0 on a Power Book (Tiger). (I am still R and statistics beginner) I did the following : pdf("InLnegthMaxHomogeneity.pdf") boxplot(inflorescence_length_Max~Sex, main="Bartletts Homogeneity for inflorescence length",data=FemMal_Sex) Homo<-bartlett.test(FemMal_Sex$inflorescence_length_Max,FemMal_Sex$Sex) text( 2, 500,

Hello world, I am actually transferring a course in data management for students in biology, geography and agriculture from statistica to R - it works surprisingly well. If anyone is interested in my scratch/notepad (in German language), please see www.hydrology.uni-kiel.de/~schorsch/statistik/statistik_datenauswertung.pdf (pages 40-52) The dataset is:

Hello R-user community! I am running R 2.7.0 on a Power Book (Tiger). (I am still R and statistics beginner) Presently I try to run the function metaMDS (vegan) using an existing dissimilarity-matrix. As I would like to start with this matrix I thought I could just give the matrix using the x= -argument Test<-metaMDS(x=Dist.Gower) Fehler in inherits(comm, "dist") :

dear list, i have a problem plotting revenue against the date. the str. of date looks like: Class 'Date' num [1:10493] -3649 -3648 -3647 -3646 -3643 ... the head looks like: [1] "1960-01-05" "1960-01-06" "1960-01-07" "1960-01-08" "1960-01-11" [6] "1960-01-12" i´d like to plot it against the years, but can´t figure out how

daer list, i want to save a result as mentioned above. for (i in 1:100) { a[i] <- write.table(a[i], "C:/.../result"i"") } how is the correct way to save the results? thank you stefan

Hi Ben, >Thorsten: I've attached a patch which I tested briefly in QEMU. Let me >know if this works for you. sorry for the delay. I was able to test this on eller today. To reproduce the issue, this was needed, because the value read was a nanosecond field and so the test didn?t always fail: (sid_mips64el-dchroot)tg at eller:~$ while sleep 0.1; do :>b; ./mksh -c 'test a -nt

I am trying to plot an nMDS plot using ggplot2. My rownames are coded so that they can be broken down by Site, Species, Treatment, or Replicate based on unique separators. There are no column headers. I am having trouble coding ggplot2 to plot by Site -or- Species -or- Treatment and NOT by all unique row names. This is probably a simple question but I'm still very new with command line

Having the same trouble that Mark ( http://www.zytor.com/pipermail/syslinux/2002-March/000244.html) had over a test platform I have here. Having a redhat 7.3 with dhcp V3.0rc12 and atftp (0.6.2) on a local small hub and a W2k Server with RIS installed. If I stop binlsvc on nt server my network boot run ok to pxelinux, but as soon as binlsvc is started, RIS server always respond over my local

hi all, i'd like to know if it would be possible with asterisk (and which hardware would i need) to implement the following (or is it not possible with asterisk - but possible with ...) I'd like to set up something like a "Mobile to Conventionel Network Gateway" - so that users (with there Mobile Phone) which are registered (known Call Number) can Call a Conventionel Network

Thanks Ben, Here the reproducible example. It works without notch=TRUE, but provides an error with notch=TURE Error in `geom_boxplot()`: ! Problem while converting geom to grob. ? Error occurred in the 1st layer. Caused by error in `ans[ypos] <- rep(yes, length.out = len)[ypos]`: ! replacement has length zero Run `rlang::last_trace()` to see where the error occurred. Warning message: In

I don't see anything obviously wrong here. There may be something subtle, but we probably won't be able to help without a reproducible example ... On 2024-08-16 9:24 a.m., SIBYLLE ST?CKLI via R-help wrote: > Dear community > > > > I tried the following code using geom_boxplot() and notch=TRUE. Does anyone > know if the command ?notch=TRUE? is at the wrong place in

Hello R-list, I am trying to calculate a ridge regression using first the *lm.ridge()* function from the MASS package and then applying the obtained Hoerl Kennard Baldwin (HKB) estimator as a penalty scalar to the *ols()* function provided by Frank Harrell in his Design package. It looks like this: > rrk1<-lm.ridge(lnbcpc ~ lntex + lnbeerp + lnwinep + lntemp + pop, subset(aa,

That's not really a reprex Sibylle.? I did try to use it to see if I could work out what you were trying to do and help but there is so much in there that I suspect is distraction from the notch issue and its error message. Please can you give us something stripped of all unecessary things and tell us what you want? Something like data that we can read as a tribble() or from a dput() of