similar to: Canonical Variance Analysis by any other name?

Hi, from what I understand about the canonical correlation function 'cancor', it looks for correlations in two sets of variables, each represented in matrix form. Right? Sounds exactly like what I need. I have tried the following but I am not sure how to interpret the results. AudioPCs <- c(ArTHarF0PCA$x[,2], ArTHarF1PCA$x[,2], ArTHarF2PCA$x[,2], ArTHarF3PCA$x[,2],

Hi, I have come to my wits end again (lately, it's a very short trip). I have been trying to connect to Samba 3.0.21b but Windows keeps throwing up the logon dialog. I'm using "Map network drive" to try to mount this share. It seems the problem is only on the Windows side since I have tested the connection through the Unix account. Both user id and password work fine.

Hi, Problem: Out of the blue Vista on my laptop decides it doesn't want to mount a share over PPTP VPN connection. I can mount the share in the local network but I can't do it over VPN. When trying to access the server, using "net view \\172.16.1.71" it shows the error in the subject. Platform/Versions: OS: Sun Solaris 10 11/06 release Samba version:

Hi, Does anybody know some package or function that computes canonical variates? Luis & Janete -------------------------------------------- sapo.pt/kitadsl -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the

I've been able to do most things I'd like to using the map package, but I can't figure out how to fill a region without drawing a black outline. I can draw the outline in a specified colour, but as soon as I set fill to TRUE, I get a black outline in addition. My map has a lot of activity on the coastline so I don't want a black line obscuring what I do there. A pale colour to

I'm baffled. When I run make check after installing from source, I get a Error 2. From my understanding of how these things work, it would appear to be coming from this (as at the end of base-Ex.Rout.fail: > has.VR <- require(MASS, quietly = TRUE) Attaching package 'MASS': The following object(s) are masked from package:base : confint confint.lm nclass.FD nclass.scott

I have a square matrix wherein a '*' indicates an HSD between the levels indicated by row name and column name. The '.' is simply marking the diagonal. A blank indicates the same group A B C D E F G H I J K L M N A . B . C * * . D * * . E * * * . F * * * .

I've been looking at the kinship package which looks as though it might be appropriate for my purposes. What I can't find is any reference to the data that is used in the example code. A dataframe called d10 with column names, upn, dadid, momid, sex and affect is required. One can get an idea of what sort of values should be in most columns from the description in the pedigree function,

Of course, that's as trivial as it gets on the command line, but I can't work out how to get a column of numbers that are entered as "10^5" from its 'character' format into a numeric one? I feel a bit embarrassed asking such a simple question. Too much Easter.... Thanks -- Patrick Connolly HortResearch Mt Albert Auckland New Zealand Ph: +64-9 815 4200 x 7188

I use rsync on an SSD which is slow at writing, but very fast at reading, so it is important to me to avoid writing data. I had hoped rsync would only write changes in files when using --inplace, but it seems not: # Make a 1 GB file $ perl -e 'print "x"x1000000000' > 1g # rsync it (as expected this costs 1 GB writes) $ ./rsync-3.1.0/rsync --progress --inplace -cva 1g 1g.copy

I seem to remember this was discussed a year or two ago, but I can't find it in the archives. platform i686-pc-linux-gnu arch i686 os linux-gnu system i686, linux-gnu status major 1 minor 7.0 year 2003 month 04 day 16 language R

Some years ago when I used S-PLUS, I seem to remember, there was a discussion about a simple method of removing trailing spaces from vector elements. I'd be fairly sure the same would work in R, but I can't find any mention of anything like it in the R archives or with help.search(). There are ways I could do it with substring(), but I seem to remember there was something more elegant.

Hi, Now suppose I have just one list called FOO, which has 25 objects, e.g.: [[1]] 1 2 3 4 5 [[2]] 6 7 8 9 10 . . . And I want to do something like: FRED <- data.frame(cbind(unlist(FOO[[1]]), unlist(FOO[[2]]), # ... for all 25 subsets )) Is it possible to do this, without doing unlist(FOO[[i]]) 25

I am using the following code: library(lattice) data<-read.csv("data.csv") attach(data) fig<-xyplot(S_t~month|event, key = list(text=list(lab=c("Time to first CV event - Data", "Survival post first CV event - Model", "Survival post first MIA/CA event - Data",

It would appear to me that there is a bug in the postscript device when multiple pages are required. Line widths can be only 1 after the first page. I have not seen reference to this as a problem before. test.device <- function() { # looks like the problem is in the postscript device postscript(file = paste("Test.ps"), horizontal = F) on.exit(dev.off())

I investigated why I was getting this error message... Error in Ops.factor(groups[subscripts], vals[1]) : Level sets of factors are different which led me to putting a browser in panel.superpose: Called from: panel.superpose(x, y, subscripts, ...) Browse[1]> vals vals [1] 1 2 3 Levels: 1 2 3 Browse[1]> groups[subscripts] groups[subscripts] [1] 1 2 3 1 2 1 2 3 1 2 3 1 2 3 Levels: 1 2

V&R describes binomial GLMs with mortality out of 20 budworms. Is it appropriate to use the same approach with mortality out of numbers as low as 3? I feel reticent to do so with data that is not very continuous. There are one continuous and one categorical independent variables. Would it be more appropriate to treat the response as an ordered factor with four levels? If so, what family

Say we have a tab delimited file called bug.txt Part Rep Cage Hb pupae 1 1 S 32 1 M 34 L 42 2 S 36 M 28 L 36 read.delim("bug.txt") Part Rep Cage Hb.pupae 1 1 1 S 32 2 NA 1 M 34 3 NA NA L 42 4 NA NA NA 5 NA NA NA 6 NA 2 S 36 7 NA NA M 28 8 NA NA L 36 >

I'm still having trouble getting to grips with time classes. I wish to calculate the difference in days between events. Browse[1]> insp.j$First [1] "2002-02-19 13:00:00 NZDT" Browse[1]> spray.j$Date [1] "2001-11-29 13:00:00 NZDT" Browse[1]> insp.jk - spray.j$Date Time difference of 82 days If I save insp.jk to a vector, I get a nice useful value of 82.

I'm asking on this list because the question will be more easily understood than on a Perl list. Lots of talented people using R also know how to use Perl, so it's easier to ask them. Running a Perl script with the -d switch can do some pretty neat things, but as far as I can tell, every line has to be done individually. Is there a way to specify where to stop in the way browser() does