Displaying 20 results from an estimated 500 matches similar to: "gplots"
2013 Feb 19
2
introducing jitter in overlapping graphs using ggplots (plotmeans). Also sciplot.
Hi,
I want to plot means with standard deviations of Total Nitrogen (TN) across
4 stations (S1-S4) and over 3 years (2007-2009). I want this plot in one
panel.
I do not want medians (bwplot, boxplot).
I have tried a few different packages and it seems that ggplots with
plotmeans was the fastest (I am not extremely skilled in writing my own
scripts). Unfortunately, there is no grouping
2002 Dec 27
2
RSvgDevice & sapply(plotmeans)
Hi,
anybody know why this not works for several
plots ?
When i set onefile=T the plots are stacked one about another
, onefile=F only the first plot is shown in AllbusMeansPlots.svg.
[h2 is a data.frame]
......hist and sapply works for several plots nice with RSvgDevice !
Maybe setting the title after apply is a problem, but until yet i didn't
found a better solution ?
library(RSvgDevice)
2020 Jan 02
1
New R function is.nana = is.na & !is.nan
"nana" is meant to express "NA, really NA".
Your suggestion sounds good.
On Thu 2 Jan, 2020, 3:38 AM Pages, Herve, <hpages at fredhutch.org> wrote:
> Happy New Year everybody!
>
> The name (is.nana) doesn't make much sense to me. Can you explain it?
>
> One alternative would be to add an extra argument (e.g. 'strict') to
> is.na(). FALSE by
2020 Jan 01
2
New R function is.nana = is.na & !is.nan
Hello R-devel,
Best wishes in the new year. I am writing to kindly request new R
function so NA_real_ can be more easily detected.
Currently if one wants to test for NA_real_ (but not NaN) then extra
work has to be done: `is.na(x) & !is.nan(x)`
Required functionality is already at C level so to address my request
there is not that much to do.
Kevin Ushey made a nice summary of current R C api
2006 Jan 23
1
Trees
Hi.,
I would like to conduct a CHAID tree analysis - Chi-square Automatic
Interaction Detector.
>From what I can make out from MASS, tree, rpart, and a quick search it
isn't available
as a package.
Is that correct or have I missed it? Has anyone an available
implementation of it?
Thanks
Stephen
Nana Mail <http://mail.nana.co.il> - Get Your Free Personal Outlook 2003
Now
2005 Nov 24
4
Survreg Weibull lambda and p
Hi All,
I have conducted the following survival analysis which appears to be OK
(thanks BRipley for solving my earlier problem).
> surv.mod1 <- survreg( Surv(timep1, relall6)~randgrpc, data=Dataset,
dist="weibull", scale = 1)
> summary(surv.mod1)
Call:
survreg(formula = Surv(timep1, relall6) ~ randgrpc, data = Dataset,
dist = "weibull", scale = 1)
2009 Nov 10
3
NetCDF output in R
Dear CSAG R users,
I will be glad if someone can point out what I am doing wrong or not doing at all in this.
I am trying to write out netcdf file in R. I have 26 time step but only the first time step is written.
For example:
>library(ncdf)
>path <- '/home/work/'
>forecast <- open.ncdf(paste(path,'cam.1980.2005.nc',sep=""))
> fore <-
2009 Nov 10
3
NetCDF output in R
Dear CSAG R users,
I will be glad if someone can point out what I am doing wrong or not doing at all in this.
I am trying to write out netcdf file in R. I have 26 time step but only the first time step is written.
For example:
>library(ncdf)
>path <- '/home/work/'
>forecast <- open.ncdf(paste(path,'cam.1980.2005.nc',sep=""))
> fore <-
2006 Jan 02
1
ARIMA?
Hi All.,
Following on from all the help I received earlier ..
Just so as you know a well known text book (T&F) uses "repeated
observations"
- I think perhaps they meant repeated measures in retrospect
I am a total beginer to ARIMA, but have read a a basic text.
I read that ARIMA requires a minimum of 50 repeated measures in time
(repeated measures)-
Unfortunately, I have 8
2005 Jun 26
4
Mixed model
Hi All,
I am currently conducting a mixed model. I have 7 repeated measures on a
simulated clinical trial. If I understand the model correctly, the
outcome is the measure (as a factor) the predictors are clinical group
and trial (1-7). The fixed factors are the measure and group. The random
factors are the intercept and id and group.
I tried using 2 functions to calculate mixed effects.
2005 Nov 22
3
Weibull and survival
Hi
I have been asked to provide Weibull parameters from a paper using
Kaplan Meir survival analysis.
This is something I am not familiar with.
The survival analysis in R works nicely and is the same as commercial
software (only the graphs are superior in R).
The Weibull does not and produces an error (see below).
Any ideas why this error should occur?
My approach may be spurious.
2001 May 24
2
New Package: gregmisc
I've thrown a couple of useful functions into a new package "gregmisc" and
uploaded them to ftp://ftp.ci.tuwien.ac.at/incoming/gregmisc_0.1.1.tgz
Here's DESCRIPTION:
Package: gregmisc
Description: Misc Functions written/maintained by Gregory R. Warnes
Title: Greg's Miscellaneous Functions
Version: 0.1
Date: 2001/05/24
Depends: R
Maintainer: Gregory R. Warnes
2020 Jan 01
0
New R function is.nana = is.na & !is.nan
Happy New Year everybody!
The name (is.nana) doesn't make much sense to me. Can you explain it?
One alternative would be to add an extra argument (e.g. 'strict') to
is.na(). FALSE by default, and ignored (with or w/o a warning) when the
type of 'x' is not "numeric".
H.
On 12/31/19 22:16, Jan Gorecki wrote:
> Hello R-devel,
>
> Best wishes in the new
2005 Jul 18
1
Survival dummy variables and some questions
Hi All,
I am currently conducting some survival analyses. I would like to
extract coefficients at each level of the IVs.
I read on a previous posting that dummy regression using coxph was not
possible.
Therefore I though, hey why not categorize the variables
(I realize some folks object to categorization but the paper I am
replicating appears to have done so ...)
and turn the variables
2010 Jun 22
1
applying ifelse to dataframe
The following dataframe will illustrate the problem
DF<-data.frame(name=rep(1:5,each=2),x1=rep("A",10),x2=seq(10,19,by=1),x3=rep(NA,10),x4=seq(20,29,by=1))
DF$x3[5]<-50
# we have a data frame. we are interested in the columns x2,x3,x4 which
contain sparse
# values and many NA.
DF
name x1 x2 x3 x4
1 1 A 10 NA 20
2 1 A 11 NA 21
3 2 A 12 NA 22
4 2 A 13 NA
2009 Nov 06
2
Adjusting Yaxis (ylim) limits on a plotMeans(DV, IV1, IV2, error.bars="se")
Hello everyone,
I have tried to look for this everywhere and so far have no luck. I have a
plotMeans(DV, IV1, IV2, error.bars="se") graph that plots my data
(DV-continuous, IVs are factors, IV1 - two levels, IV2-four levels). I am
trying to increase a scale of my y-axis (to be consistent with my other
graphs), but unfortunately nothing works with "plotMeans" function, which
2011 Nov 09
2
plot separate groups with plotmeans()
Hi,
I often use plotmeans() from the gplots package to quickly visualize a
pattern of change. I would like to be able to plot separate lines for
different groups, but the function gives an error when a grouping
variable is included in the formula argument.
For instance,
> require(gplots)
> x <- data.frame(Score=rnorm(100), Time=rep(1:10, 10),
2005 Dec 01
8
Impaired boxplot functionality - mean instead of median
Hello to all users and wizards.
I am regulary using 'boxplot' function or its analogue - 'bwplot' from
the 'lattice' library. But they are, as far as I understand, totally
flawed in functionality: they miss ability to select what they would
draw 'in the middle' - median, mean. What the box means - standard
error, 90% or something else. What the whiskers mean -
2014 Aug 04
1
Samba PDC groups in windows
Hello,
I have a samba PDC with an openLDAP backend. on my windows 7 machines which
have joined the Samba PDC domain I cannot see the groups on windows. Does
anyone know the reason why ?
I can see the mapped groups in groupmap list though
root at smb-pdc[~]# net groupmap list
Domain Admins (S-1-5-21-831610874-1793854533-4121639242-512) -> Domain
Admins
Domain Users
2010 Jun 28
2
plotmeans
Hello,
I am using
library(gplots)
to do something like
data(state)
x1 <- state.area/10000
x2 <- x1+round((rnorm(length(state.area),3,3)))
plotmeans(x1 ~ state.region)
Is it possible to plot x2 to x1 in the same graph, something like:
linesmeans(x2 ~ state.region)
Best wishes,
Cheba
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