similar to: Equal number of cuts in a contourplot with trellis

Dear R-helpers, I would like to change the default value of a functions that is call by a package. The function deparse() is called by a set of functions from a library and because I don't think is appropriate to change the library, I am trying to change the default value in deparse(). At the moment the only solution I have come across is to place a function in my working environment like

Dear R-helpers, I recently upgraded to R 1.9.0 in my computer at work and at home: 1.-The computer at home has Windows XP and Office XP and it seems to work perfectly and I copy-paste graphics perfectly. 2.-The computer at work has Microsoft Windows 2000 (5.00.2195 Service Pack 2) and Word 2000 (9.0.4402 SR-1) I cannot copy-paste windows metafiles into Office applications in my computer at

Dear R-helpers, I am trying to reshape a data frame that is in a wide format into a long format one. I have come across the reshape() function, but I have been very successful using it. As an example: ll <- data.frame(time.1=seq(0.1,1,length=10),L1=rnorm(10),time.2=c(seq(1,7),rep(NA ,3)),R2=c(rnorm(7),rep(NA,3)),time.3=c(seq(1,1.5,length=3)+5,rep(NA,7)),M3=c (rnorm(3),rep(NA,7))) which

Dear R-helpers, I have some problem with a model I am trying to run with nlmeODE. I have a covariate that I want to include in the model and I can't find in the documentation how to include it in the model so that it can calculate it. >formula(trial) PME ~ time | Ident abcnoniso <- list(DiffEq=list( debdt = ~ -ksol*pH*eb , desdt = ~

Dear R-helpers, I’ve got a summary of results from a by() call that I am making with a list of more than two of factors not very different from the example in the by() help page require(stats) by(warpbreaks[, 1], warpbreaks[, -1], summary) The result of the command gives a list of the form wool: A tension: L Min. 1st Qu. Median Mean 3rd Qu. Max. 25.00 26.00

Dear R-helpers, Would anybody have a compiled binary version (for Windows) of the Dopt library that is in the development site?. best regards, IOsu -------------------------------------------------------------- Jes?s Mar?a Fr?as Celayeta Dublin Institute of Technology School of Food Sci. and Env. Health. Cathal Bruha St., Dublin 1. Ireland Phone: +353 1 4024459 Fax: +353 1 4024495

Friends: I wish to overlay data points on a contour graph. The following example produces a nice contour plot, but I have not mastered the concept of using panel functions to modify plots. Can someone show me how to overlay the data points (given after contour plot statement) on the contourplot? --Seth model <- function(a,b,c,X1,X2) # provide model function for contour

Hello All, I've problems to interpret the contourplot for a binary response dependent variable. For example, I ploted the survived probability for the titanic3 dataset, http://www.geocities.com/useebi/data/CondenContour.jpeg Trellis displayed two panels of contour, one for dead and one for alive. However, the contours between the two panels didn't conform to the rule of

Gudday, I am generating a series of lattice contourplots that are conditioned on a variable (Year) that has 27 different levels. If I try and put them all on one plot, it ends up pretty messy and you can't really read anything, so instead I have set the layout to 3x3, thus generating three pages of nine plots each. The problem is that I can't display all these on screen at once, because

Hi All, I want to add one point to contourplot().  I used contourplot() in my code like contourplot(z ~ a + b |c, data) I understand there is plot.axes argument for filled.contour(), but it  did not work for my code. I also tried plot() and text() for contourplot(), but got this error: "plot.new has not been called yet" Any suggestion for adding a point in contourplot()? Thank you very

Hi everybody, I want to do a contourplot in lattice with my raw data overlaid on it(xyplot) which seemed to be a very easy thing to do. I've tried it in many ways, but I haven't succeeded at obtaining it. let's say x, y, and z as the variables that comes from the data frame ''ex'': therefore my countourplot is as followed : contourplot(z ~ x * y, cuts=550) I

Hi - I have a dataframe with 4 variables - long, lat, temp and year. I would like to plot temperature by lat and long in contour plots by year. There are 391 data points. When I try contourplot(temp~long*lat|year,data=hake,cuts=10,labels = TRUE,contour = TRUE,pretty = TRUE,region=TRUE) I get plots with dots around by data, but not contour lines or filled in regions. I have also used the

Hi, Is there a way to plot more than one trend surface using the functions contourplot() and wireframe(). I have found an add=T in contour(), but no equivalent argument in contourplot() and wireframe()? I have taken the example 11-2 (pages 441-451) from Design and analysis of experiments (Montgomery 2001, 5th edition) to see if this could be done in R. I have managed to plot individual

Hi, one of the nice things about contour is that it labels all contour lines. contourplot only labels each particular elevation a single time. i.e., if there are two contour lines corresponding to z = 45, it will only label one of them. is there a way to get contourplot to automatically label all the contour lines, even those that are repeated? i ask because i want to plot contour plots *w/

Hello, A weird thing is happening to me. I have a 128x128 elements matrix m with values between 0 and 1. If I do: R> library(lattice) R> contourplot (m, cuts=9) I get the following error message: Error in validDetails.text(x) : Invalid 'rot' value The same for any cuts >9. I can plot m with contourplot(m, cuts=8) but this is not detailed enough. The 'normal'

I'm working on a contourplot( ) graph, the subject of several previous posts to this list. The contours express probabilities from 0 - 1, but the key that is automatically generated by contourplot pads the probability scale with values that are impossible (i.e, range goes from -0.2 to 1.2), which will be confusing to those who view the plot. How can I get the scale to just run from 0 - 1?

Hi, I have done the interpolation for my data and I was able to create the contours in multipanel with the help of Pascal. Now, I want to clip the contour with the shapefile. I want only the portion of contour to be displayed which falls inside the boundary of the shapefile. The data mydata.csv can be found on https://www.dropbox.com/s/khi7nv0160hi68p/mydata.csv The data for shapefile can be

Sorry if I am cluttering up this list with too many rank beginner questions. But I *am* a rank beginner, and I am at my wit's end with this one: I have a data frame df, with components x,y,z. This command to make a contour plot with lattice graphics works just fine: > contourplot(z~x*y,data=df,cuts=20) Then I try > contourplot(z~x*y,data=df,cuts=20,region=T) And it dies on me with

If I have a contourplot (in the lattice package) and I want to add straight lines to it, how do I do this? I see that there are llines() and lsegement() functions for lattice plots, but they don't seem to do anything in this case: library(lattice) library(KernSmooth) x=rnorm(10000) y=x+rnorm(x,0,.5) a=bkde2D(cbind(x,y),.7) z=as.vector(a$fhat) grid=expand.grid(x=a$x1,y=a$x2) grid$z=z

Hi, I am gradually moving from the classical R plot functions to the library Lattice I have some questions about contourplot () and its arguments: 1/ I am working on geographical coordinates which makes necessary that the X (longitude) and Y (latitude) units be represented with the same distance on screen. This was obtained in the classical R plots with plot.default(x,y, asp=1,...) and then