similar to: two y-axis in xy-plot

Dear group, First I provide you with an example, I found in the newsgroup. Then I'd like to explain my problem to you by means of the output. enviro <- data.frame(Year = rep(2001:2002, each = 365), Day = rep(1:365, 2), Precip = pmax(0, rnorm(365 * 2)), Temp = 2 + 0.2 * rnorm(365 * 2)) xyplot(Precip + Temp ~ Day | Year,

Hi all, I have a question concerning xyplot. My data is a data.frame looking like that: In the first column I have numbers from 0 to 23 (hours of a day), the second column contains the name of a weekday (Day as factor) and the third column contains the number I am interested in. So as an example, the first five rows look like that: Hour Day Freq 1 0 Mo 23 2 1 Mo

Hi there, I have a question, which I thought is very easy to solve, but somehow I can't find a solution. Probably someone could help me quickly? Here it is: I have two matrices: a [,1] [,2] [,3] [1,] 1 4 9 [2,] 2 6 10 [3,] 3 6 11 [4,] 4 8 12 b [,1] [,2] [1,] 1 4 [2,] 2 5 [3,] 3 6 Now I want to find

Hi, In voicemail.conf: ; Supported values: ; 'filename' filename of a soundfile (single ticks around the filename ; required) ; ${VAR} variable substitution ; A or a Day of week (Saturday, Sunday, ...) ; B or b or h Month name (January, February, ...) ; d or e numeric day of month (first, second, ..., thirty-first) ; Y Year ; I or l

Dear Group, Having a character vector like this one: [1] "03:38:55" "07:42:38" "08:04:27" "08:17:13" "08:41:14" "08:46:58" [7] "08:47:11" "08:53:51" "08:57:51" "08:58:56" I try to do a histogram over times of a day. All I want to know, if my solution is proper or if there is another

I have some time series data like 01/02/1990 0.531 0.479 01/03/1990 0.510 0.522 01/06/1990 0.602 0.604 there is no weekends and holidays. how do I graph them in a single plot that the x-axis is the dates and the y-axis is the time series? Thank you Regards, Jincai Jiang (Office) 212-761-3984 -------------------------------------------------------- This is not an offer (or solicitation

Hi, I have loaded a dataset in R : data = label freq1 freq2 news 54 35 fun 37 21 milk 19 7 food 3 3 .... etc And I have a vector flist<-c("fun","food") Now I want to use the vector 'flist' for selecting these values from 'data' so that I get the following dataset : label freq1 freq2 fun 37 21 food

Dear masters, I have data that looks like this: #val Freq1 Freq2 0.000 178 202 0.001 4611 5300 0.002 99 112 0.003 26 30 0.004 17 20 0.005 15 20 0.006 11 14 0.007 11 13 0.008 13 13 ...many more lines.. Full data can be found here: http://dpaste.com/173536/plain/ What I intend to do is to have a cumulative graph with "val" as x-axis with "Freq1" & "Freq2" as

Dear List, I'm trying to use R under Windows on a huge database in MySQL via ODBC (technical reasons for this...). Now I want to read tables with some 160.000.000 entries into R. I would be lucky if anyone out there has some good hints what to consider concerning memory management. I'm not sure about the best methods reading such huge files into R. for the moment I spilt the whole

I am wondering if anyone could help me figure out how to turn down the volume on all the dial tones, indications, etc.. and especially the call-waiting CHIRP! I don't want to change the txgain and rxgain because they are working at levels that I would like. However, when voice conversations and voicemail recordings are at good levels then the dial tones, busy tones, etc are way too loud.

Hello, Everyone. Does anyone know how to create a Nightingale’s Rose chart by using R? Hopefully, the graph could be displayed like this: http://mbostock.github.com/protovis/ex/crimea-rose.html Thanks a lot. Kind regards, Henry [[alternative HTML version deleted]]

Hi all, I'd like to know, if I can solve this with a shorter command: a <- rnorm(100) which(a > -0.5 & a < 0.5) # would give me all indices of numbers greater than -0.5 and smaller than +0.5 I have something similar with a dataframe and it produces sometimes quite long commands... I'd like to have something like: which(within.interval(a, -0.5, 0.5)) Is there anything I

Hello, I tried to fit a poisson distribution but looking at the function fitdistr() it does not optimize lambda but simply estimates the mean of the data and returns it as lambda. I'm a bit confused because I was expecting an optimization of this parameter to gain a good fit... If I would use mle() of stats4 package or mle2() of bbmle package, I would have to write the function by myself

Apparently, as.POSIXlt takes one o'clock as the start of the day : > as.POSIXlt(0,origin="1970-01-01") [1] "1970-01-01 01:00:00 CET" > as.POSIXlt(0,origin="1970-01-01 00:00:00") [1] "1970-01-01 01:00:00 CET" > as.POSIXlt(0,origin="1970-01-01 23:59:59") [1] "1970-01-02 00:59:59 CET" Cheers -- Joris Meys Statistical

Hello, I'm looking for a solution for the following problem: I have two vectors V1 <- c("apple","honey","milk","bread","butter") V2 <- c("bread","milk") now, I would like to know for each element in V1 if it's equal to one of the elements in V2 I could do: which(V1 == V2[1] | V1 == V2[2]) but what if I

Hello, I have a question how to reshape a given matrix to a data frame. # ---------------------------------- > a <- matrix(1:25, nrow=5) > a [,1] [,2] [,3] [,4] [,5] [1,] 1 6 11 16 21 [2,] 2 7 12 17 22 [3,] 3 8 13 18 23 [4,] 4 9 14 19 24 [5,] 5 10 15 20 25 > colnames(a) <- LETTERS[1:5] > rownames(a) <-

Hello, I'm not very experienced with lattice and I was wondering whether I get get some hints from you how to create a pure heatmap (using levelplot), without any axis, title, legend, margin at all... I just want to see the coloured squares, nothing else. Any suggestions? Antje

Hello, I hope this question is not too stupid. I would like to know how to update levels after subsetting data from a data.frame. df <- data.frame(factor(c("a","a","c","b","b")), c(4,5,6,7,8), c(9,1,2,3,4)) names(df) <- c("X1","X2","X3") my.sub <- subset(df, X1 == "a" | X1 == "b")

Hi there, as I'm not sure to understand the coloring levelplot uses, I'm looking for another easy way to create a heatmap like this: library(lattice) mat <- matrix(seq(1,5, length.out = 12), nrow = 3) mat[1,2] <- 3.5 my.at <- seq(0.5,5.5, length.out = 6) my.col.regions <- rainbow(5) graph <- levelplot(t(mat[nrow(mat):1, ] ), at = my.at, col.regions = my.col.regions)

Hi there, assume that you have data with different sampling like d1 <- rnorm(100) d2 <- rnorm(150) now, I'd like to create two boxplots in one graph but each plot located at the sampling number at the x-axis. This, I can do with "at" l <- list(d1,d2) boxplot(l, at=c(length(d1), length(d2)), xlim=c(0,200) ) but both plots are very thin and I'd like to increase the