similar to: getting last 2 charcters of a string, other "text" functions?

Hi to all I need a string like temp <- paste("m1","m2","m3",sep=",") But i must know how many items are in the string,afterwards the other option would be to use a vector temp <- c("m1","m2","m3") No problem to get the count of items but I must get afterwards the string "m1,m2,m3" No problem to build the

Hello, we tried to create a trust between a samba 3.4.3 and win 2008. It did not work an we lost two days before we discovered that it did not work because we had a $ in the password. Is there documentation about what characters are valid in a password for a trust account ? Thanks Andreas

Hello. I have a problem using sort() in windows 2000 and windows NT 4.0, running R 1.8.0 on both. I want to sort a vector of characters names, where I have used "Scandinavian" letters, like '?', '?', and '?' (for those who cannot display these letters this question seems rather meaningless, i guess). Windows 2000 sorts the vector like I am used to from other

Those of you who track R development closely, will have noticed yesterday's commit of enhanced versions of nchar() and nzchar(). ------------------------------------------------------------------------ r68254 | maechler | 2015-04-23 18:06:37 +0200 (Thu, 23 Apr 2015) | 1 line Changed paths: M doc/NEWS.Rd M src/library/base/R/New-Internal.R M src/library/base/R/zzz.R M

Hi, I try to create PDF files with an modified script from Buchan Milne and have some problems with the Jobname var %J. Because it is better for the users to find an file with an similar name as the original document I'm looking for a way to read out %J, cut some unnessasary stuff and use the rest as new file name. The problem is: In %J in some circumstances is not the complete Jobname as

I have a vector of dates. I wish to find the month end date for each. Any suggestions? e.g. For 12/15/05, I want 12/31/05, For 10/15/1995, I want 10/31/1995, etc __________________________________________________ [[alternative HTML version deleted]]

What should findInterval(x,vec,all.inside=TRUE) return when length(vec)<=1, so there are no inside intervals? R-3.3.0 gives a decreasing map of x->output when length(vec)==1 and -1's when length(vec)==0. Would '0' in all those cases be better? > findInterval(x=c(10, 11, 12), vec=11, all.inside=TRUE, rightmost.closed=FALSE, left.open=FALSE) [1] 1 0 0 >

In normal tree rotation left process, we will never touch the tree branch above subtree_index and ocfs2_extend_rotate_transaction doesn't reserve the credits for them either. But when we want to delete the rightmost extent block, we have to update the rightmost records for all the rightmost branch(See ocfs2_update_edge_lengths), so we have to allocate extra credits for them. What's more,

Hi Mark/Joel, These are 2 bug fix for b-tree. Please review. I have sent out the first one last week, but it was based on cacheme. So resend it. Now it bases on joel's fixes branch. The second one is another b-tree rotation bug. I guess the reason why we never meet with it is that no one has ever used b-tree like reflink before. ;) Regards, Tao

Hi Mark/Joel, This is the v2 of bug fix for ocfs2_add_branch. Modification from V1 to V2: 1. Create a patch which return EROFS instead of BUG in ocfs2_insert_at_leaf. 2. Use ocfs2_adjust_rightmost_records to change the root and extent blocks in the rightmost path. Regards, Tao

Is there a way of doing this? I'm using plot() to produce a scatter of my data, but it routinely defaults to plotting 2 sets of x axes and 2 y axes. I'd like to not plot the upper and rightmost axes. I can use 'axes=F', and then manually add axes with 'axis', but then the newly created axes do not intercept. TIA, Dan

In ocfs2_add_branch, we use the rightmost rec of the leaf extent block to generate the e_cpos for the new added branch. In the most case, it is OK but if there is a gap between the the root(or branch) 's rightmost rec and the leaf, it will cause kernel panic if we insert some clusters in it. The message is something like: (7445,1):ocfs2_insert_at_leaf:3775 ERROR: bug expression:

what the hell are you talking about? --- On Fri, 2/8/08, wine-users-request at winehq.org <wine-users-request at winehq.org> wrote: From: wine-users-request at winehq.org <wine-users-request at winehq.org> Subject: wine-users Digest, Vol 31, Issue 9 To: wine-users at winehq.org Date: Friday, February 8, 2008, 10:00 AM Send wine-users mailing list submissions to wine-users at

Currently, the cube plugin uses mipmapping only when cube is unfolded. When the cube is rotated, mipmaps are not used, which leads to ugly look of textures. The attached patch fixes this. This leads to another kind of artifacts, which are fixable with anisotropic filtering. http://team.pld-linux.org/~wolf/aniso.png The leftmost image is the current state of cube plugin. The center image is with

Hi all, I've been trying to work out how to slice an array of arbitrary dimension. I found a message showing how to stick two arrays together, but so far have been unable to transform that into what I need. Assume that I have a four dimensional array for example: array4d , , 1, 1 [,1] [,2] [1,] 3 6 [2,] 1 1 , , 2, 1 [,1] [,2] [1,] 4 7 [2,] 8 7 , , 1, 2

On 05/10/2015 7:24 PM, Matt Dowle wrote: > Joris Meys <jorismeys <at> gmail.com> writes: > >> >> Hi all, >> >> I have a puzzling problem related to nchar. In R 3.2.1, the internal > nchar >> gained an extra argument (see >> https://stat.ethz.ch/pipermail/r-announce/2015/000586.html) >> >> I've been testing code using the

The old extent merging code down underneath "ocfs2_mark_extent_written()" can't merge extents between leaf blocks. This patch resolve this. So that a large unwritten extent which has been split up with a bunch of writes can be merged together once all unwritten regions have been written to. Modification from V1 to V2: 1. Add more comments for some functions which is more complicated

Hi, Is nchar function knowingly slow in R? I'm doing some string formatting that requires multiple call to nchar, and nchar seems to be very slow. Experiment 1, pass nchar inside sprintf, and it takes 0.7 seconds > system.time(for (i in 1:10000) + str = sprintf('0005%020d', nchar(op)) + )[3] [1] 0.7 Experiment 2, get the length of op separately using nchar, and then pass

Hi, Before I reinvent the wheel I wanted to kindly ask you for your opinion if there is a simple way to do it. I want to merge a larger number of tables from different data sources in R and the matching criterium are country names. The tables are of different size and sometimes the country names do differ slightly. Has anyone done this or any recommendation on what commands I

Dear R users, the help for findInterval(x,vec) suggests a logarithmic dependence on N (=length(vec)), which would imply a binary search type algorithm. However, when I "test" this hypothesis, in the following manner: set.seed(-3645); l <- vector(); N.seq <- c(5000, 500000, 1000000, 10000000, 50000000);k <- 1 for (N in N.seq){ tmp <- sort(round(stats::rt(N, df=2), 2));