similar to: how to get colnames of a dataframe within a function called by 'apply'

Hi, I am trying to find a way to automate production of page numbers in plots produced using the lattice package. To do this, I started playing around with setHook which works fine with vanilla plot, but the hook 'plot.new' doesn't appear to be relevant to the lattice package. I was wondering if there is a alternative someone can suggest for use with the lattice package. Example

Here is my code, which plots three lines with errorbar. How could I add an extra line without errorbar to the plot? Thank you very much. beta.data <- data.frame ( method = rep(c("Wrong", "Correct", "Full Bayes"), each = T_obs), mean.beta = c(mean.beta1, mean.beta2, mean.beta3), t = rep(points, 3), std.beta = c(std.beta1, std.beta2, std.beta3) ) limits =

Hello, I try to write a bash skript and I want to use the variables from my bash skript into R. Ist that possible? My bash skript creates lots of *.data files. I want forward these files directly into R (in x.data.bz2), so that R creates a few data automatically also in PDF. For example: bash created files: hello.data , world.data how R created these files in pdf? please look my plot.R

Hi, I have done a search on this in vain. How can I add a note to the foot of a graph example below |-----------------------| | Title | | -------- | | | my | | | | graph | | | | | | | | ______| | |note: source | |-----------------------| Many thanks Ronnie

If there are many character variables,and I want to get the mosaic plot of every pair of each variable,how to do then? If the variables are numeric, I can use pairs to get paired scatter plot. But as to the character variables, how to get the "paired mosaic plot"? Many thanks. -- QQ: 1733768559 At 2015-02-07 17:04:26,"Jim Lemon" <drjimlemon at gmail.com>

Hello, I know, this is a real newbie question, but I can't find anything on this in the manuals! I know that I get calculate the column totals of a table with `apply(mytable, 2, sum)'. Now I want each column total to be 100% and calculate the percentage of each field of the column. How would I do that? Rcommander, the ultimate newb-tool, has a function `colPercents' which is exactly

I am trying to save an R data.frame as an Excel sheet. I do NOT want the column names saved into row 1. I set colnames=F. However, it still seems that the colnames are saved into row 1. Is this a bug? Or am I coding incorrectly and.or misunderstanding this feature? #example code: sheet = "c:/test2.xls" temp=data.frame(matrix(data=NA,nrow=10,ncol=15)) temp[1,1] =

Have a class for which I would like to provide a "colnames<-.myclass" function so that colnames(myintsance) <- c("a","b","c") can be called. Witold -- Witold Eryk Wolski [[alternative HTML version deleted]]

Hi there, I cannot find a detailed explanation to the following error message: > colnames(matrix(1:10, ncol = 2)) <- c("X", "Y") Error in colnames(matrix(1:10, ncol = 2)) <- c("X", "Y") : target of assignment expands to non-language object However, when I do the following things, the error message disappear: > z <- matrix(1:10, ncol =

Hi all, How get colnames and rownames in Rcpp method? attecthed file : RGui.exe capture my work environment : R version : 2.11.1 OS : WinXP Pro sp3 Thanks and best regards. Young-Ju, Park from Korea [1][rKWLzcpt.zNp8gmPEwGJCA00] [@from=dllmain&rcpt=r%2Dhelp%40r%2Dproject%2Eorg&msgid=%3C20100728211143%2EH

Hello, please see below my code for a heatmap. Unfortunately my column names do not completely appear. Can you please send me the appropriate code to visualise them? Many Thanks! Nils library(GMD) dat<-data.frame(EntryA=as.numeric(c(4.24,3,1.66,1.28,1.2,-1.32,-1.88)), EntryB=as.numeric(c(4.16,4.82,-1.82,-3.02,0.99,1.1,-3.31)))

Dear maintainers, I'm reporting a bug in qr.coef that mishandles the colnames of matrix. A minimal reproducible example is as follows: x <- cbind(rep(0, 10), rep(0, 10)) y <- rep(0, 10) q <- qr.default(x) qr.coef(q, y) [1] NA NA If x has colnames, then qr.coef will end up with an error: x <- cbind(x1 = rep(0, 10), x2 = rep(0, 10)) y <- rep(0, 10) q <- qr.default(x)

Seems like you got your input and output mixed up a bit... > From: Jack Tanner > > I want to iterate over a data frame by columns, and as I'm processing > each column I want to know its column name. > > > a <- as.data.frame(list(1,2,3)) > > colnames(a) <- c("a", "b", "c") > > colnames(a) You must have the two lines

Try colnames(df)[4:6] <- c("x","y","z") -----Original Message----- From: r-help-bounces at stat.math.ethz.ch [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of xmeng at capitalbio.com Sent: 21 December 2004 09:45 To: r-help at stat.math.ethz.ch Subject: [R] about colnames Hello sir: If there's a data frame(with name "df"): a b c d e f

hi, I have a conversion table for colnames like this: Probe_ID HUMAN_LLID 1 AF106325_PROBE1 7052 2 NM_019386_PROBE1 7052 3 NM_012907_PROBE1 339 4 AW917796_PROBE1 84196 5 L27651_PROBE1 10864 The Probe_ID contains a list of colnames for another data.frame, say x1. I need to convert such colnames to another ID's system, HUMAN_LLID by using the table.

Hello, I have another stupid question. I hope you can give me a hint how to solve this: I have a list and one element is again a list containing matrices, all of the same dimensions. Now, I'd like to set the dimnames for all matrices: example code: m1 <- matrix(1:25, nrow=5) m2 <- matrix(26:50, nrow=5) # ... there can be much more than two matrices l <- list() l[[1]] <-

HI, I have a file named "s1"(which has 14 rows and 4 columns) which is in csv format. I import and call it "A" the file using: A <- read.csv(file="s1.csv",head=TRUE,sep=",") then I transpose it and call it "B"(which will have 4 rows and 14 columns) using: B=t(A) when I want to make 5 samples from "B" (choosing 10 columns) using:

A dataframe holds 3 vars, each checked true or false (1, 0). Another var holds the grouping, r and s: ### start:example set.seed(20) d <- data.frame(sample(c(0, 1), 20, replace=T), sample(c(0, 1), 20, replace=T), sample(c(0, 1), 20, replace=T)) names(d) <- c("A", "B", "C") e <- rep(c("r", "s"), 10) ### end:example How do I get the

Hi, I've this dataframes: > data1 1 2 3 4 5 6 5 0.4963017 0 0 0.2481509 1.9852069 0.4963017 10 0.0000000 0 0 0.0000000 0.6317266 0.0000000 15 0.0000000 0 0 0.0000000 0.0000000 0.0000000 20 0.0000000 0 0 3.3955301 0.0000000 0.0000000 25 0.0000000 0 0 0.0000000 0.0000000 0.0000000 30 0.0000000 0 0 0.0000000 0.0000000

Hi, Do you know how to assign colnames from one list to another, for example. a=c(1,2,3) b=c("A","B","C") how can I get the dataset A B C 1 2 3 where A, B and C are colnames. Thanks. Xumin [[alternative HTML version deleted]]