similar to: hist of dates

Thks for your answer, here is an exemple of what i do with the errors in french... > tmp [1] 200 150 245 125 134 345 320 450 678 > beta18 Erreur : Objet "beta18" not found //NORMAL just to show it > eta [1] 500 > func1<-function(beta18) dweibull(tmp[1],beta18,eta) > func1<-func1(beta18) * function(beta18) dweibull(tmp[2],beta18,eta) Erreur dans dweibull(tmp[1],

hi all I wish to thanks every body on the R mailing list for answering very fast, directly in my mail box ;). I've finish my work with R and i can say that it is very difficult at the beginning, and when you succeed you are stopped by a stack overflow when you call your nice recursive function (which was working with a tab of 100 element) with a tab of 900 elements, but R just do what you

hi all Here is a small part of my code: tab_tmp<-tab[1:(no[off_set[i-1]+1]+(no[off_set[i]+1]-no[off_set[i-1]+1])),length(tab)]; tab_tmp1<-tab[(no[off_set[i-1]+1]+(no[off_set[i]+1]-no[off_set[i-1]+1])):length(TotalFillTimeHours),length(tab)]; tab<-c(tab_tmp,tab_tmp1); attach(tab); Here is the output: Error in attach(tab) : attach only works for lists and data frames Execution halted

hy all, I wish to switch in a part in my code that use "read.table" to "scan", actually i use this: tab<-scan("data.dat",what=integer(),skip=1) dim(tab)<-c(75,length(tab)/75) tab<-t(tab) It gives me a new tab with 75 columns, but i when i was using read.table with headers then attach i could use the columns names to access the data values, now how can i

Hy all, I wish to use the date function to draw againt the lifetime of a motor. This lifetime is given to me in Hours (it can go over 5000 hours) I'm unable to find how to convert this lifetime value to something like %H:%M:%S because when R see 24H it says 1 day, i don't want that, i just want %H:%M:%S with a value of %H higher than 24... for example: i've got this value in hours:

hi all, I wish to draw on the same graphic device 3 functions. But i don't want them to be on different graph, i want to compare them on the same I don't need mfrow or mfcol, I need something else... 1 graph on 1 device inside this graph 3 ploted function. I saw something unsing data.frame, but i think it's overkill, and something less complicated must exist, if not why? why not

hi all, I need to generate a function inside a loop: tmp is an array for (i in 1:10) { func<- func * function(beta1) dweibull(tmp[i],beta1,eta) } because then i need to integrate this function on beta. I could have written this : func<-function(beta1) prod(dweibull(tmp,beta1,eta)) (with eta and beta1 set) but it is unplottable and no integrable... i could make it a bit different but

hi all, I wish to draw on the same graphic device 3 functions. But i don't want them to be on different graph, i want to compare them on the same I don't need mfrow or mfcol, I need something else... 1 graph on 1 device inside this graph 3 ploted function. I saw something unsing data.frame, but i think it's overkill, and something less complicated must exist, if not why? why not

Hy all I use barplot to draw frequencies by dates. On the x axis it shows only 1 date for 2 bars, i've understand why, because R cant put so much date on the same axis, it will get out of the graph. that's why i tought about reducing the size of the font used to stamp the x axis. anyone knows the right way? i've tryed par(cin) and barplot(cin=3) but it says i cannot do it at this

hi all, I load a table with headers that enable me to acces it by the column names: tab<-read.table("blob/data.dat",h=T) attach(tab) everythings are OK, but i try to sort this table against one of his column like this: tab<-tab[order(tab$IndexUI),]; It is still ok, the table is sorted, if i type "tab" i see a sorted table. but, when i call the column by their names,

Hi all, Before the amount of data given has grown i was initially using read.table to load the values inside R. It was feeding my needs because i could tell read.table h=T, then use attach to access the values by columns names. Now it takes 20 seconds to load the data's and the first enhancement i could do is to win some time on the load of the data's... How could i use the scan

Hi all i need to put on one graph 2 functions who's x axis is the same and y not. I mean on horizontal the time, and on vertical left: pressure, on vertical right: rpm of a motor, is R able to do that? i've found this that i could adapt maybe (i don't need time series really?) :/ : (http://tolstoy.newcastle.edu.au/R/help/04/03/1456.html) ## ## Description: A simple function which

hi all, I've got a data frame, this data frame have 76 columns and 22600 rows. The data inside can be redundant because the data can be captured simultaneously and overlap each other. My aim is to supress these overlaps I've test some solutions to do that but they all give a big cpu load and eat all of the memory then swap a lot, then killall R because it don't end. actually

Hi all, I wish to draw 2 hist (or barplot) on the same graph. I can do it simply by using par(new=TRUE) , but it overlap with the first drawn, how to tell R to put in front of the graph the min value of the two graph in order for it to be seen and don't hide each other. I've been looking at help for barplot or hist but didn't find anything... (or my english is too poor to

Hi all, i'm new to R, I need to modelize in R a statistic algorithm, This algo use Weibull, normal law, linear regression, normalisation, root mean square, to find eta and beta fitting the weibull model (to analyse few results) and further when we will get more information apply bayes model . the problem is when When i try to integrate it fails with errors. by the way i like to integrate

hy all I wish to draw a graph against a date, I have a set of date like this DD/MM/YYYY, corresponding to it a set of integer , i wish to draw on x side the dates (the space between the dates have to be constant, not based on the time between 2 dates but on the number of dates) and on y side the integers. Do i have to make a tricky function under R ? I've search the help for graphical

Hi, It seems that hist() has a buggy behavior when breaking over "days". The bug can be reproduced in a few steps: > d=data.frame(date=c("2009-01-01", "2009-01-02", "2009-01-02")) > d$date=as.Date(d$date) > d$date [1] "2009-01-01" "2009-01-02" "2009-01-02" > h=hist(d$date, "days") > h$count [1] 3

Can someone help me with a misunderstanding I'm having with hist? I expected, from the example below, that the number of bins would always be 10 and the length of the counts array the same. According to the help section 'breaks' can be a integer indicating the number of bins. From the example below, the number of bins (length of the counts array) varies. Am I wrong in expecting the

Full_Name: Alex Deckmyn Version: 2.4.0 OS: linux Submission from: (NULL) (193.190.63.62) specifying the "right" option in hist results in a warning when plot=F. The option is taken into account correctly, but a warning is issued anyway. When plot=T there is no warning. > hist(c(1,1.5),breaks=0:4)$counts [1] 1 1 0 0 > hist(c(1,1.5),breaks=0:4,right=T)$counts [1] 1 1 0 0 >

Dear developers, the current implementation of hist.default() calculates 'density' (and 'intensities') as dens <- counts/(n*h) where h has been calculated before as h <- diff(fuzzybreaks) which results in 'fuzzy' values for the density, see e.g. > tmp <- hist(1:10,breaks=c(-2.5,2.5,7.5,12.5),plot=FALSE) > print(tmp$density,digits=15) [1]