similar to: functions available for use with aggregate?

Dear R users, I have a question on using weighted.mean() while aggregating a data frame. I have a data frame with columns Sub, Length and Slope: > x[1:5,] Sub Length Slope 1 2 351.547 0.0025284969 2 2 343.738 0.0025859390 3 1 696.659 0.0015948968 4 2 5442.338 0.0026132544 5 1 209.483 0.0005304225 and I would like to calculate the weighted.mean of Slope, using Length

For the following code below, the x-axis ticks are 1,2,3,4,5,6,7 when I was expection them to be 1,2,8,9,10,11,12. Please help me figure out where is the mistake. library(lattice) testdata <- as.data.frame(t(structure(c( 1,2005,9.24,6.18,634, 2,2005,8.65,6.05,96, 8,2004,6.81,6.51,16, 9,2004,9.0,7.29,8, 10,2004,8.84,6.18,524, 11,2004,8.54,6.35,579, 12,2004,9.97,6.3,614, 12,2005,8.75,5.84,32,

Hi When I use plot(hclust(dist..)...)...) etc to create a dendrogram of a hierarchial cluster analysis, I end up with a vertical tree. What do I need to do to get a horizontal tree? Also, my users are used to seeing trees who's leaves all "end" at the same place (eg. Like in minitab). Is this possible in R? Thanks Mick Michael Watson Head of Informatics Institute for Animal

Dear useRs, I'd like to produce some scatter plots where N units on the X axis are equal to N units on the Y axis (as measured with a ruler, on screen or paper). This approach x <- sample(10:200,40) ; y <- sample(20:100,40) windows(width=max(x),height=max(y)) plot(x,y) is better than plot(x,y) but doesn't solve the problem because of the other parameters (margins etc). Is

I've just encountered a segfault when using DierckxSpline::percur function. Below is the minimal example which triggers the error: --- library(DierckxSpline) x <- 1:10 y <- rep(0, 10) pspline <- percur(x, y) --- *** caught segfault *** address (nil), cause 'memory not mapped' Traceback: 1: .Fortran("percur", iopt = as.integer(iopt), m = as.integer(m), x =

Full_Name: Sundar Dorai-Raj Version: 2.8.0 OS: Windows Submission from: (NULL) (76.220.41.126) The following code crashes R: library(tcltk) tt <- tktoplevel() tc <- tkcanvas(tt, yscrollcommand = function(...) tkset(ts, ...)) > sessionInfo() R version 2.8.0 (2008-10-20) i386-pc-mingw32 locale: LC_COLLATE=English_United States.1252;LC_CTYPE=English_United

Hi all, Say I have a matrix A with dimension m x 2 and matrix B with dimension n x 2. I would like to find the row in A that is closest to the each row in B. Here's an example (using a loop): set.seed(1) A <- matrix(runif(12), 6, 2) # 6 x 2 B <- matrix(runif(6), 3, 2) # 3 x 2 m <- vector("numeric", nrow(B)) for(j in 1:nrow(B)) { d <- (A[, 1] - B[j, 1])^2 + (A[,

Hi all, Here's a curosity I ran into since upgrading to 1.6.2 (precompiled for Windows). When using the chm help I get the following warning. I saw a recent post regarding this as a new warning (``dyn.load warning message in R1.6.2 on Windows XP'' dated 1/28/03), but not in the context of the help system. The warning only appears once and does not prevent the chm file from

>From: Sundar Dorai-Raj <sundar.dorai-raj at PDF.COM> >Reply-To: sundar.dorai-raj at PDF.COM >To: Zhen Pang <nusbj at hotmail.com> >CC: r-help at stat.math.ethz.ch >Subject: Vectorising and loop (was Re: [R] optim "a log-likelihood >function") >Date: Wed, 29 Sep 2004 18:21:17 -0700 > > > >Zhen Pang wrote: > >> >>I also use

I just noticed the following in update.formula and I'm wondering if this behavior is the intention of the developers. Here's an example: update(`a: b` ~ x, ~ . + y) Note now that the response has no backticks and is interpreted as a:b (i.e. ":" is now an operator). This is because in update.formula the call to terms.formula uses simplify = TRUE. I'm working with data that

Hi I am using R version 2.4.1. How can I upgrade to version 2.5 without having to install all the packages again? Thanks Jason Dr. Iasonas Lamprianou Department of Education The University of Manchester Oxford Road, Manchester M13 9PL, UK Tel. 0044 161 275 3485 iasonas.lamprianou@manchester.ac.uk ___________________________________________________________ now. [[alternative HTML

Hi, Anyone can tell me how to generate "A01", "A02", ..., "A99"? paste("A", 1:99, sep="") generates "A1", "A2",..., "A99". This is not what I want. Thanks for the help. -MY [[alternative HTML version deleted]]

Hi, All, I'm writing a wrapper for stop that produces a popup window using tcltk. Something like: error <- function(...) { msg <- paste(..., sep = "") if(!length(msg)) msg <- "" if(require(tcltk, quiet = TRUE)) { tt <- tktoplevel() tkwm.title(tt, "Error") tkmsg <- tktext(tt, bg = "white") tkinsert(tkmsg,

I'm new to lattice and can't figure out what the problem is with the following example: ######################### > library(lattice) Loading required package: grid Attaching package `lattice': The following object(s) are masked _by_ .GlobalEnv : xyplot The following object(s) are masked from package:base : levels > test.data <- data.frame(x=rnorm(100), +

How can I see more of the structure than displayed by 'str'? Consider the following: tstDF <- data.frame(a=1, row.names='b') > str(tstDF) 'data.frame': 1 obs. of 1 variable: $ a: num 1 The object 'tstDF' has row.names, but I have to suspect they are there -- AND know a function like 'row.names' or 'dimnames' -- to see

I couldn't resist adding a more literal answer unback <- function(x) { chars <- unlist(strsplit(deparse(x),"")) chars <- chars[-c(1,length(chars))] paste(gsub("\\\\","/",chars),collapse="") } unback("\n") | David Duffy (MBBS PhD) ,-_|\ | email: davidD at qimr.edu.au ph:

I couldn't resist adding a more literal answer unback <- function(x) { chars <- unlist(strsplit(deparse(x),"")) chars <- chars[-c(1,length(chars))] paste(gsub("\\\\","/",chars),collapse="") } unback("\n") | David Duffy (MBBS PhD) ,-_|\ | email: davidD at qimr.edu.au ph:

I have two data sets: File1.txt: Name id1 id2 id3 ... N1 0 1 0 ... N2 0 1 1 ... N3 1 1 -1 ... ... File2.txt: Group id1 id2 id3 ... G1 1.22 1.34 2.44 ... G2 2.33 2.56 2.56 ... G3 1.56 1.99 1.46 ... ... I like to do: x1<-c(0,1,0,...) y1<-c(1.22,1.34, 2.44, ...)

Hello, i know that i have to use optim, but i'm confused how its possible maximize the sum over all l[i] and get the optimized max(LL), r and alpha? LL <- function(trans,time){ for(i in 1:length(trans){ l[i] <- log(lgamma(r+trans[i] - gamma(r+1)*(alpha/alpha+t[i]))**r)*(t[i]/alpha+t[i]))**trans[i] } return(sum(l)) } i'm confused how i have to set r and alpha and i

Hi, all, I'm looking a utility for removing a directory from within R. Currently, I'm using: foo <- function(...) { mydir <- tempdir() dir.create(mydir, showWarnings = FALSE, recursive = TRUE) on.exit(system(sprintf("rm -rf %s", mydir))) ## do some stuff in "mydir" invisible() } However, this is assumes "rm" is available. I know of