similar to: function agruments

Displaying 20 results from an estimated 1000 matches similar to: "function agruments"

2005 Aug 20
2
diagonal matrices
Hello all, I have matrices V.i of dimension n.i x n.i, where i = 1, ..., J, and the sum of n.i equals N. (and n.i ! = n.j) goal: create one large matrix V, where V has matrices V.i on diagonal. I create each matrix V.i in a for loop (1 to J), so each time I'd like to augment V with the most recently calculated V.i, such that I'll have V after the final iteration of the for loop.
2005 Aug 09
2
numeric operations w/ lists
Hello all, X is a list of 20 lists, and each individual list has 65 elements. Y is a list of 65 elements. WANT: subtract Y from each of the 20 lists in X. Here's what I tried and the error messages: > X - rep(Y, 20) Error in X - rep(Y 20) : non-numeric argument to binary operator I tried several methods w/o success. Any suggestions kindly appreciated. Thanks, Dave ps - please copy
2005 Oct 10
2
wildcards and removing variables
All, Is there are a wildcard in R for varible names as in unix? For example, rm(results*) to remove all variable or function names that begin w/ "results"? cheers, Dave ps - please respond directly to afshar@miami.edu [[alternative HTML version deleted]]
2006 Feb 03
2
workspace question
All, When starting R, how does one prevent the loading the previous workspace which was saved? I'd like to start a new project and save the new image in a different directory, but I'd like to partition this from the old project. Does there exist a better way than just deleting the files associated w/ the old project manually? I looked in the Intro to R manual and searched for
2005 Nov 16
2
save to ascii
All, Usually when I save a variable I have ascii = FALSE since I usually load the variable via the load(variable) command and do not need to view the variable outside of R. When I set ascii = TRUE and view the variable outside of R in a text editor, I notice additional characters (starting w/ RDA2 ...) before the first actual value in the vector. Is there are way to save to ascii such that this
2009 Jul 24
1
Aggregate, max and time of max
All, For data consisting of serial measurements on subjects, one may use the aggregate function to say compute the peak response for each subject for each design condition. Is there a way to alter this or another one-liner to also retain the time at which the peak occurred and thus avoid writing a doing this via a loop? I suppose one could attempt to employ the split function but that's
2010 Jun 02
2
pdf function, resize xyplot plot automatically
All, When saving plots to a pdf file via the pdf function, I would like to be able to automatically expand the graphics device to achieve the same result as when one does this manually (e.g., clicking the green expand button on the upper left of the graph on Mac OS). Consider simple example below: library("lattice") foo.frm = data.frame(Subject = rep(c(1:4), each = 9), Y =
2006 Jun 14
3
appending
All, In the function below I have 24 individuals and 6 calculations per individual. The 6 calculations are collected each time in a 1:24 loop when calculating "delta". I'd like to collect all 144 = 24*6 calculations in one vector ("delta.patient.comb"). The function works as is via indexing, but is there an easier way to collect the measurements via appendinng the 6
2005 Oct 07
3
index question
All, I'm having a problem selecting directly from a vector. I've written ways to do this indirectly, but I'd rather do it directly and didn't see this in the manual. Essentially, I have: > group.label.new [1] 7 9 6 1 10 4 8 3 2 5 > junk [1] 1 2 > group.label.new[junk && 8:10] [1] 7 9 6 1 10 4 8 3 2 5 I'd like to select the elements
2006 Sep 07
5
augPred plot in nlme library
All, I'm trying to create an augPred plot in the nlme library, similar to the plot on p.43 of Pinheiro & Bates (Mixed Effects Models in S and S-Plus) for their Pixel data. My data structure is the same as the example but I still get the error msg below. > comp.adj.UKV <- groupedData(adj.UKV ~ Time | Patient_no/Lisinopril, data = comp.adj.UKV.frm, order.groups = F) >
2006 Sep 23
4
plotting grouped data object
All, I'd like to plot the main relationship of a grouped data object for all levels of a factor in a single panel. The sample code below creates a separate panel for each level of the factor. I realize that this could be done in other ways, but I'd like to do it via plotting the grouped data object. thanks! dave z = rnorm(18, mean=0, sd=1) x = rep(1:6, 3) y =
2006 Sep 12
11
levels of factor when subsetting the factor
All, When I take a subset of a factor the reduced factor still maintains all the original levels of the factor when say forming the key in a plot. The data is correct, but the variable still "remembers" the original levels. See below for reproducible code. Does anyone know how to fix this? cheers, dave fact = as.factor(c(rep("A", 3),rep("B", 3), rep("C",
2006 Sep 06
1
Covariance/Correlation matrix for repeated measures data frame
All, I have a repeated measures data frame and was wondering if the covariance matrix can be calculated via some created indexing or built-in R function. Specifically, say there are 3 variables, where potassium concentration is measured 6 times on each patient. Patient number (discrete) Time (1 to 6, discrete) Potassium (continuous variable) I want the covariance/correlation matrix for the
2006 Jun 27
2
supplying dynamic main argument to plot?
All, Simple question but I don't seem to be able to find the answer in the documentation: When using "plot" within a loop, is there any way to supply the argument to "main" dynamically, i.e., so that the title is Patient k below as the loop cycles through each value of k? plot(x,y, xlim=c(0,250), ylim=c(0,1000), xlab="gamma", ylab="r1",
2007 Jul 05
3
summarizing dataframe at variable/factor levels
All, Is there an efficient way to apply say "mean" or "median" to a dataframe according to say all combinations of two variables in the dataframe? Below is a simple example and the outline of a "manual" solution that will work but is not very efficient (could also generalize this to a function). Searched the archives and docs but didn't see anything close to
2006 Jun 28
5
sapply question
sent this to the list yesterday but didn't see it listed in the daily summary ... apologies if you receive it twice ... ________________________________ From: Afshartous, David Sent: Tuesday, June 27, 2006 10:02 AM To: 'r-help@stat.math.ethz.ch' Subject: sapply question All: I'm trying to use sapply to break up data within another function. (tapply doens't seem to work
2007 Jun 28
3
applying max elementwise to two vectors
All, Is there one liner way to obtain the max per observation for two vectors? I looked at apply and lapply but it seems that groundwork would have to be done before applying either of those. The code below does it but seems like overkill. Thanks! Dave x = rnorm(10) y = rnorm(10) ind = which(x < y) z = x z[ind] <- y[ind] ## z now contains the max's
2011 Jan 07
1
AGI->Macro w/Agruments
OK, I need to dial a macro from AGI and needs to pass an argument. Ok, I found an bug report, but it was stated "un fixable?" really after 5 years? https://issues.asterisk.org/view.php?id=2470 I found this email in the archive, but no solution other then the dodgy work around? http://www.mail-archive.com/asterisk-users at lists.digium.com/msg85048.html I have
2007 Jul 03
1
xyplot and autokey, maintaining colors specified via "col" in key
All, When specifying colors to xyplot w/ a groups argument, using auto.key no longer maintains the colors properly. I've searched the docs and help but haven't found exactly what I need ... I saw a few examples in the archives involving par.settings but that doesn't seem to do it. I also saw some people using key instead of auto.key, but that didn't seem consistent. Is there a
2005 Oct 03
2
"symbol print-name too long"
All, I've coded a function and it works manually if I copy it line by line into R. However, when I try to "load" (copy and paste) the entire function into R, I get the following error after the listed line of code: + N.j.list = lapply(rej.hyp, length) Error: symbol print-name too long Does anyone you know what this error means? Strangely, when I copy the same line verbatim