similar to: ylim for graphic

Dear List: I'm creating a series of barplots using Sweave that must assume a standard format. This is student achievement data and the x-axis must include all grades 3 to 8. In some cases, the data for a grade (or more than one grade) are missing in the vector math.bar, but are never missing for the vector apmxpmeet. The following sample code illustrates the issue. Using the code below to

Hello, R 2.3.0 Windows XP I have spent quite a bit of time trying to resolve my problem below, which included a R site search. The "vertical bars" syntax below produces a vertical bar chart with the values displayed above each bar. I want to cast this graphic horizontally, but I have not been able to arrive at a suitable outcome. The best I have been able to do, using the second block

Hello, I am trying to add R code to my dissertation and the length of a line of text that Sweave generates is longer than the right margin in my dissertation. I have found no way to tell Sweave how to set the line length. I am using an iMac with tiger ver. 10.4.10, and R: ver. 2.5.1. Here is the R code that is longer than my right margin: input to Sweave:

Hello I am trying to add a ternary plot as a corner inset graph to a larger main ternary plot. I have successfully used add.scatter in the past for different kinds of plots but It doesn't seem to work for this particular function. It overlays the old plot rather than plotting as an inset. Here is a simple version of what I'm trying. Note that if I change the inset plot to be an ordinary

Hi all, I post it on both r-help and r-finance since I don't know where is most appropriate for this topic. Sorry if it bothers you. I did garch fitting on S&P500 monthly returns with garchFit from fSeries. I got same coefficients from all cond.dist except normal. I thought that is probabaly usual for the data. But when I play with it, I got another question. I plot skew normal with

Dan, Another tweak ! If you want the 'legend' to look pretty you can resize it by adding,say, 'cex=0.6' into the legend code; try--- legend("topleft", #inset=-1, legend = do.call("expression", L), bg='white', ncol = 2, pch=c('','','',':',':',':'), x.intersp = 0.4,

Hi: I'm trying to plot dates on the x-axis of a code, but the legend is not being displayed. I receive the following error: Error in match.arg(x, c("bottomright", "bottom", "bottomleft", "left", : 'arg' should be one of bottomright, bottom, bottomleft, left, topleft, top, topright, right, center In addition: Warning message: longer

Dear List: I am working to generate graphs for individual students that will be created through a series of loops in Sweave. Before doing so, I am still trying to design the graph. The code for creating the barplot is below with some sample datapoints just made up for now. Ultimately, this chart will take data from an lme object using longitudinal student data. So, the dots represent the

Full_Name: Elizabeth Purdom Version: 1.9.1 OS: Windows XP Submission from: (NULL) (171.64.102.199) It would be nice if legend had the option of some default locations you could choose instead of entering specific coordinates, like "topleft", "topright","topcenter", etc. based on par("usr") coordinates. I know I've wanted it so often I've made my

Dear All, Please see the short script at the end of the email, which I assembled looking for bits and pieces on the web. It essentially does what I need: it plots several countries as a color-coded map. I just would like to fine-tune a bit the final image, in particular (1) Select my own colors for "painting" the countries (i.e. associate manually a color to every level) (2) Be

Dear group, Here is my data frame: position100415 <- structure(list(DESCRIPTION = structure(1:9, .Label = c(" SUGAR NO.11 Jul/10 ", " SUGAR NO.11 May/10 ", "CORN May/10 ", "COTTON NO.2 Jul/10 ", "CRUDE OIL miNY May/10 ", "ROBUSTA COFFEE (10) Jul/10 ", "SILVER May/10 ", "SOYBEANS Jul/10 ", "WHEAT May/10

I have a form that I want to use to update multiple objects. In the controller, @grades = Grade.find(params[:grade].keys) @grades.each_with_index do |grade, i| grade.update_attribute(params[:grade][i]) end all_valid = @grades.inject(true) {|memo, c| c.valid? && memo } this doesn''t update the attributes as I would expect. (I would just use

Is there an efficient way to create a series of dummy codes from a single variable? For example, I have a variable, “grade” = {2, …, 12}. I want to create k-1 dummy codes for grade such that grade 2 is the base (i.e, grade 2 =0). I am hoping that the new variables can be labeled as grade.3, grade.4 etc. I'll then use grade <- paste("grade.", 3:12, sep="") in

In a previous post, I mentioned a loop being used to generate graphs. I have some sample code partially put together but have found one offending line of code that I cannot figure out what to do with. I have one data frame called grade4. If I do something like hist(grade4$math) I get the appropriate chart. Within the loop, however, I am doing this for multiple files and grades, so I use

I have grades data. I read them from a csv in letter-grade format. I then converted them to levels levels(grades$grade)=c('A+','A','A-','B+','B','B-','C+','C','C-','D+','D','D-') And then to numbers grades$gp=grades$grade levels(grades$gp)=c(4.3,4.0,3.7, 3.3,3.0,2.7, 2.3,2.0,1.7, 1.3,1.0,0.7)

Found this solution. It is maybe not the most elegant way, but it does the job. > a=as.data.frame(substr(lme$DESCRIPTION,1,14)) > colnames(a)=c("DESCRIPTION") > lme=as.data.frame(c(a,lme[,2:3])) > lme DESCRIPTION CLOSING.PRICE POSITION 1 PRIMARY NICKEL 25,755.7100 0 2 PRIMARY NICKEL 25,760.8600 0 3 PRM HGH GD ALU 2,415.9000 0

Env: R 2.8.1, Win Xp, Eclipse/StatET In a .Rd file, I have an example containing the lines: # calculate Y M, using polynomial contrasts trends <- as.matrix(VocabGrowth) %*% poly(8:11, degree=3) colnames(trends)<- c("Linear", "Quad", "Cubic") [At the risk of a long message, I'll append the complete .Rd file at the end of this message, in case this was

Dear R help gurus, I have the following problem and I would be delighted if you could help me. >From a large (1500) cohort of patients we have been taking some measurements (ECG measurements, but its not important). The measurements are ordinal in 4 grades (Grade I-IV, grade IV being the most severe form). Every patients has been measured several times (usually once per year). The

Hello I have a longitudinal dataframe organized in the long format and would like to make comparison between successive rows if certain conditions apply. Specifically, I have four variables of interest: grade, score, year, and schid, associated with each school with 3 measurements per school per grade, therefore the rows are temporally ordered and each school occupies multiple rows. For example,

dear expeRts, i would like to merge the data frame entries in a list. for example: > #input > myl <- list(q1=data.frame(id=c("Alice", "Bob"), grade=c(90, 49)), q2=data.frame(id=c("Alice", "Chuck"), grade=c(70, 93)), q3=data.frame(id=c("Bob", "Chuck"), grade=c(84, 40))) > #output > (mydf <-