Displaying 20 results from an estimated 200 matches similar to: "Anova's in R"
2004 Oct 17
3
ecdf with lots of ties is inefficient (PR#7292)
Full_Name: Martin Frith
Version: R-2.0.0
OS: linux-gnu
Submission from: (NULL) (134.160.83.73)
I have large vectors containing 100,000 to 20,000,000 numbers. However, they
only contain a few hundred *distinct* numbers (e.g. positive integers < 200).
When I do ecdf(v), it either runs out of memory, or it succeeds, but when I plot
the ecdf with postscript, the output is unnecessarily bloated
2008 Jul 16
2
belongs_to causing endless loop on first call to save!
Hi,
I have a situation I''m hoping someone out there may be able to shed some
light on. I have a Rails app (2.1.0 on Ruby 1.8.7) with a wizard-based sign
up process, that has recently been changed from storing incremental data in
the database to having a medium sized object graph living in the user
session until the user completes the entire sign up process (this is a
business
2010 Mar 08
3
Cannot create auth-master file
Hi all,
I'm trying to get postfix and dovecot working nicely together to process and store mail for both local (system) on one domain and virtual users and a few different domains.
I've got postfix up and running quite nicely, but am having a few problems with Dovecot. Every time postfix tried to delivery a message to a virtual user using dovecot I get an error like the following in
2008 Jan 15
1
Repeated Measures/Split-Plot Anova
Hi,
My name is Dan Ott and I recently learned R mainly for the purposing
of running ANOVA's and linear regression. I just started using a data
set where I want to run a repeated measures anova as well as a
split-plot anova. My question is: What is the syntax for repeated
measures and split-plot anova's?
I did a little searching online and it appears that aov might be used for
a
2010 May 12
1
DOS Attributes with mixed xattr filesystem support
Hi,
I'm running Samba as a glorified NAS at the moment - to begin with, I
have an ext3 storage partition, /storage. In this is a directory,
/storage/Personal, which has its own Samba share (also Personal). At
this point, dos attributes using filesystem xattrs work beautifully. The
problem comes when I start to fiddle further...
I have a Novell NetWare filesystem (ncpmount) mounted at
2007 Mar 15
2
how to...
I have to perform ANOVA's on many different data organized in a dataframe. I can run an ANOVA for each sample, but I've got hundreds of data and I would like to avoid manually carrying out each test. in addition, I would like to have the results organized in a simple way, for example in a table, wich could be easy to export. thank you for assistance
simone
2002 Jul 09
3
building formula objects
I want to write a function to take an argument as the response
variable of a linear model, e.g. to do anova's across a list of
variables, something like the following (except, of course, this
doesn't work):
function(x) { anova(lm(x ~ my.factor,data=my.data)) }
The x in lm() above is getting evaluated at the wrong level. How
can I make this work?
--
Russell Senior ``The two
2003 Jun 27
0
error terms in mixed ANOVA's
Hi,
Newbie here, just joined the list.
I discovered something interesting when performing a mixed between and
within (repeated measure) ANOVA in R. The error terms (SS actually I
guess) are inflated by the number of factors of the within measure.
This just seems wrong. I think I'm doing it right
e. g.
subj grp test x
1 1 1 ...
1 1 1
1 1 2
1 1 2
2 2 1
2 2 1
2 2 2
2 2 2
So, the anova
2011 Jun 08
1
ANOVA with many IV's
I'd like to conduct one-way ANOVA's on multiple IV's. Is there a function for
"aov (y~"all of my IV's")? Thank you!
--
View this message in context: http://r.789695.n4.nabble.com/ANOVA-with-many-IV-s-tp3583788p3583788.html
Sent from the R help mailing list archive at Nabble.com.
2011 Sep 27
1
ANOVA define as factor or not
Hi all
This is probably a simple problem but somehow I am having much trouble with
finding a solution, so I seek your help!
I have a data-set with continuous response variables. The explanatory
variably is 4xpH treatments (so 8.08, 7.94, 7.81 and 7.71) so also
continuous and not technically factorial.
However I have decided to do Anova's (as well as regression) to explore the
effect of
2006 Jun 21
1
eliminating a do loop
Using a "by() statement, I am preparing ANOVA's for multiple experiments,
and using simint() to generate confidence intervals.
This works fine.
simint.by.fit <- by(analytes.dfr, list(Assay = analytes.dfr$analyte ),
function(data) (simint(value ~ tx, data = data,type='Tukey' ) ) )
I can separately prepare plots of the confidence intervals, and I can
prepare separate plots
2008 Mar 02
2
difference between lrm's "Model L.R." and anova's "Chi-Square"
I am running lrm() with a single factor. I then run anova() on the fitted
model to obtain a p-value associated with having that factor in the model.
I am noticing that the "Model L.R." in the lrm results is almost the same
as the "Chi-Square" in the anova results, but not quite; the latter value
is always slightly smaller.
anova() calculates the p-value based on
2004 Jun 11
2
lme newbie question
Hi
I try to implement a simple 2-factorial repeated-measure anova in the
lme framework and would be grateful for a short feedback
-my dependent var is a reaction-time (rt),
-as dependent var I have
-the age-group (0/1) the subject belongs to (so this is a
between-subject factor), and
-two WITHIN experimental conditions, one (angle) having 5, the other
3 (hands) factor-levels;
2012 Feb 09
1
Tukey HSD
Hey Folks:
New to R and learning as I go, but really, I know just enough to get myself
into trouble. I've waded through everything up till now, and don't see
anything in the search that is directly helpful for the POS that I've
created.
The GOAL: All I want in the world is a program that performs 1-way ANOVA's
on every column in a data set (taking the first column as the
2012 May 04
1
ANOVA problem
Hi,
I need to create a data frame containing the results of a number of ANOVA's
but I'm having some trouble setting it up (some being enough for me to spend
3 days trying with no progress and be left staring in to the abyss which
some people call a weekend, and what I will call 2 quiet days in the
office...)
The response variable is *V*.
I need to do an ANOVA for each *G*.
The fixed
2007 Nov 04
4
Why can repeated measures anova with within & between subjects design not be done if group sizes are unbalanced?
Dear R people:
I wish to switch from SPSS to R, but there is one particular type of
ANOVA design that cannot be done in R. Or more likely, it can be
done, but it is nowhere documented.
The problem is typical for psychologists:
You have a repeated measures design with different groups of subjects.
Now, this can be done with the aov command, but the number of
subjects in both groups must be
2012 Aug 22
3
Question concerning anova()
Hi
I am comparing four different linear mixed effect models, derived from updating the original one. To
compare these, I want to use anova(). I therefore do the following (not reproducible - just to
illustration purpose!):
dat <- loadSPECIES(SPECIES)
subs <- expression(dead==FALSE & recTreat==FALSE)
feff <- noBefore~pHarv*year # fixed effect in the model
reff <-
2011 Feb 25
1
ANOVA and Pseudoreplication in R
Hi, As part of my dissertation, I'm going to be doing an Anova,
comparing the "dead zone" diameters on plates of microbial growth with
little paper disks "loaded" with antimicrobial, a clear zone appears
where death occurs, the size depending on the strength and
succeptibility. So it's basically 4 different treatments, and I'm
comparing the diameters (in mm) of
2011 Feb 26
2
[R-sig-ME] Fwd: Re: ANOVA and Pseudoreplication in R
On 25/02/2011 21:22, Ben Ward wrote:
>
> -------- Original Message --------
> Subject: Re: [R] ANOVA and Pseudoreplication in R
> Date: Fri, 25 Feb 2011 12:10:14 -0800
> From: Bert Gunter<gunter.berton at gene.com>
> To: Ben Ward<benjamin.ward at bathspa.org>
> CC: r-help<r-help at r-project.org>
>
>
>
> I can hopefully save bandwidth here by
2010 Mar 30
1
nlrq parameter bounds
Hi there,
Can anyone please tell me if it is possible to limit parameters in nlrq()
to 'upper' and 'lower' bounds as per nls()? If so how??
Many thanks in advance