similar to: shading in line plots

I am trying to use the angle option in polygon to create polygons filled with horizontal and vertical lines. The polygons I am crating are irregular and it the angle function appears to set the angle of the shading perpendicular to the polygon sides rather than perpendicular to the axes. Is there any way to set the angle relative to the axes rather than relative to the polygon sides?

Hi, I have a contour plot and I want to shade a polygon (the area below a line) but the polygon shading wipes out the contour lines. Does anybody know how to shade the polygon and still see the contour lines? Thanks. Jeff

Dear Listers, I am drawing a plot of two density curves, for male and female incomes. I would like to shade/hatch/color (whatever) the areas under the curves which are distinctive for each gender. This is the code I have tried so far: m <- density(topmal.d$y, bw = "sj") f <- density(topfem.d$y, bw = "sj") par(mfrow = c(1,1)) plot(x = c(0,400), y = c(0,0.02), type =

Thanks for the question. Here is a sample of the code for my plot: Top = c(34, 39, 42, 45, 46, 41, 41, 40, 43, 38, 33, 33) Bottom = c(24, 29, 32, 36, 32, 34, 32,41, 40, 39, 29, 24) plot(1,1, col = "white", xlim = c(1.3,11.7), ylim = c(0,80), axis = FALSE, xaxt = "n") axis(1, at = c(1:12)) polygon(c(c(1:12),c(12:1)), c(top, bottom), col =

The angle is not based on the polygon edges, but it can seem that way if you do not use the asp=1 argument in your plot. Try this example, > plot(1:10, 1:10, type='n') > x <- c(1, 3, 5, 3) > y <- c(3, 5, 3, 1) > polygon(x, y, angle=0, density=10) > polygon(x, y + 4.5, angle=45, density=10) > polygon(x + 4.5, y + 4.5, angle=90, density=10) > polygon(x + 4.5, y,

Hi, I have a graph with seven parallel horizontal lines. Is it possible to shade the area between two adjacent lines? Thank you in advance, Hannu

I have the following code for the minimum and maximum of my prediction interval > y.down=lines(x[x.order], set1.pred[,2][x.order], col=109) > y.up=lines(x[x.order], set1.pred[,3][x.order], col=109) domain=min(x):max(x) polygon(c(domain,rev(domain)),c(y.up,rev(y.down)),col=109) It doesnt seem to shade the right region, it gives me a trapezoid. Any help? Thanks!

Hi, I'm sure this should be fairly simple to do but I haven't found an example. I have 10 data points which are plotted as a line, I want to shade under this line with a colour. Other examples have shading under curves where there are two sets of data use polygons. mydata <- c(268,251,254,250,244,246,247,243,241,243) plot(mydata, type="o")

I want to get a lighter shade of a color...I have a lot of colored objects and want each one printed as a foreground against a slightly lighter background. I thought I could try something like changing the alpha channel by first converting it to rgb. But prior to trying that, I'm stuck with how to get the color after converting using col2rgb() to be interpreted again as a color, rather than

Dear R experts, I have plot the PDF of t distribution with df = 74. curve(dt(x,df=74),from=-4, to=4) how can I shade the area under curve (for example, col="red") from t=+- 1.996? Thank you. Regards, CH -- CH Chan Research Assistant - KWH http://www.macgrass.com

I have a set of 52 weekly values, one is the desired high lake stage for a week, and the other is the desired low lake stage for each week. It looks like this: week High Low 1 16 14.5 2 16 14.5 3 15.95 14.45 4 15.84 14.34 5 15.73 14.23 6 15.61 14.11 7 15.5 14 8 15.38 13.88 9 15.25 13.75 10 15.13 13.63 .... 52 15 13.5 I can plot out two nice curves

We had been using R1.2.3 "print tip lowess function" as described by Terry Speed's group to normalize microarray data and up until this week the commands we were using were working fine. First, we load our data using arrayname<-read.table("filename", header=T) and then check that the table is OK. We format the data list using setup1<-init.data() and usually get a

Filling polygons with lines is a throwback to the time when the height of quality graphics was the mechanical pen plotter (a device that used a pen in a mechanical arm to draw the plot on a piece of paper). Computing and printing technology has advanced quite a bit from that day, so you may want to reconsider why you want polygons filled with lines instead of just a solid color (and I consider

Hi, I cannot do the following: telnet 127.0.0.1 5038 I get connection refused and this is preventing AMP from installing. I had this working when I was using FC3 but I had to upgrade to FC4 for another application. So I am running PHP5, MYSQL 4 with FC4 and asterisk is running (I had this problem before with FC3 and it turned out asterisk was not running) I am using 1.2.0 beta1 Asterisk

Dear R users, I still feel new to R so please apologize if I am doing something stupid here. My use of the polygon() function produces a result that I cannot comprehend: In a plot, I would like to shade the area below a normal distribution. However, I do not want the entire area to be shaded, but just the area on the right side of a vertical line that I draw through the distribution (in

All, The code below produces a color 3D graph. I'd like to make it black and white shading. I tried setting col.regions to FALSE but this just made it completely white. I want the graph to look exactly as is, except black (or grey) and white shading. Is this possible? Cheers, David p.list = c(.01, .1, .25, .5, .75, .9) cov.list = c(.2, .1, .05) ### leave out .01 X = rep(p.list, 3)

Tena koe Simon plot(1:10, 1:10, type='n') polygon(c(2,3,6,8), c(2,5,5,3), density=20, angle=90) polygon(c(2,3,6,8), 5+c(2,5,5,3), density=20, angle=0) I don't understand your problem. Perhaps if you "provide[d] commented, minimal, self-contained, reproducible code" it would help. HTH .... Peter Alspach -----Original Message----- From: R-help [mailto:r-help-bounces at

This bug is not quite fixed - the example from my original report now = works using R-2.2.1, but plot(Uniform, 6) does not. The bug is due to if (show[6]) { ymx <- max(cook, na.rm =3D TRUE) * 1.025 g <- hatval/(1 - hatval) # Potential division by zero here # plot(g, cook, xlim =3D c(0, max(g)), ylim =3D c(0, ymx),=20 main =3D main, xlab =3D

Hello, I have a question regarding shading regions under curves to display 95% confidence intervals. I generated bootstrap results for the slope and intercept of a simple linear regression model using the following code (borrowed from JJ Faraway 2005): > attach(allposs.nine.d) > x<-model.matrix(~log(d.dist,10))[,-1] > bcoef<-matrix(0,1000,2) > for(i in 1:1000){ +

Am trying to produce a graph which prints out well in black and white using ggplot2. I have the following example set up nicely, but want to shade the red bars in one pattern and the blue in another so they print out clearly. I tried changing colours to 1 light, 1 dark, but then the overlapping colour looks virtually identical to the darker one. I noted the option density in barplot, but