similar to: question about about the drop1

Displaying 20 results from an estimated 400 matches similar to: "question about about the drop1"

2009 Mar 23
1
Iterative Proportional Fitting, use
Hi list, I would like to normalize a matrix (two actually for comparison) using iterative proportional fitting. Using ipf() would be the easiest way to do this, however I can't get my head around the use of the function. More specifically, the margins settings... for a matrix: mat <- matrix(c(65,4,22,24,6,81,5,8,0,11,85,19,4,7,3,90),4,4) using fit <-
2006 May 30
1
max / pmax
Hello R users, I am relatively new to R and cannot seem to crack a coding problem. I am working with substance abuse data, and I have a variable called "primary.drug" which is considered the drug of choice for each subject. I have just a few missing values on that variable. Instead of using a multiple imputation method like chained equations, I would prefer to derive these
2008 Nov 30
1
Rserve and creating a list of lists
Hello, I have some code which generates lattice objects. The function recieves serialized forms of the lattice objects which it then unserializes and then adds to an ArrayList<REXP>. REXPRaw rser = new REXPRaw( target ); //target contains the raw serialized forms of lattice objects rconn.assign("temp",rser); REXP ret =
2013 Apr 09
2
R crash
I have a generalized linear model to solve. I used package "geepack". When I use the correlation structure "unstructured", I get a messeage that- R GUI front-end has stopped working. Why this happens? What is the solution? The r codes are as follows: a<-read.table("d:/bmt.txt",header=T")
2012 Nov 08
2
Comparing nonlinear, non-nested models
Dear R users, Could somebody please help me to find a way of comparing nonlinear, non-nested models in R, where the number of parameters is not necessarily different? Here is a sample (growth rates, y, as a function of internal substrate concentration, x): x <- c(0.52, 1.21, 1.45, 1.64, 1.89, 2.14, 2.47, 3.20, 4.47, 5.31, 6.48) y <- c(0.00, 0.35, 0.41, 0.49, 0.58, 0.61, 0.71, 0.83, 0.98,
2012 Dec 31
3
cut ()
Hello List, My goal is to create a 5 category variable (p1_st_data$ob_mrj_cat), based on the p1_st_data$obt_mrj_p variable, using the following code for 50 States and District of Columbia (N=51). p1_st_data$ob_mrj_cat <- cut (p1_st_data$obt_mrj_p, quantile (p1_st_data$obt_mrj_p, (0:5/5), include.lowest=TRUE)) The issue is that, for Utah, I am getting an <NA> instead of (42,48.7] in
2009 Jul 28
2
A hiccup when using anova on gam() fits.
I stumbled across a mild glitch when trying to compare the result of gam() fitting with the result of lm() fitting. The following code demonstrates the problem: library(gam) x <- rep(1:10,10) set.seed(42) y <- rnorm(100) fit1 <- lm(y~x) fit2 <- gam(y~lo(x)) fit3 <- lm(y~factor(x)) print(anova(fit1,fit2)) # No worries. print(anova(fit1,fit3)) # Likewise. print(anova(fit2,fit3)) #
2011 Sep 12
1
coxreg vs coxph: time-dependent treatment
Dear List, After including cluster() option the coxreg (from eha package) produces results slightly different than that of coxph (from survival) in the following time-dependent treatment effect calculation (example is used just to make the point). Will appreciate any explaination / comment. cheers, Ehsan ############################ require(survival) require(eha) data(heart) # create weights
2009 May 12
1
questions on rpart (tree changes when rearrange the order of covariates?!)
Greetings, I am using rpart for classification with "class" method. The test data is the Indian diabetes data from package mlbench. I fitted a classification tree firstly using the original data, and then exchanged the order of Body mass and Plasma glucose which are the strongest/important variables in the growing phase. The second tree is a little different from the first one. The
2004 Dec 20
2
problems with limma
I try to send this message To Gordon Smyth at smyth at vehi,edu.au but it bounced back, so here it is to r-help I am trying to use limma, just downloaded it from CRAN. I use R 2.0.1 on Win XP see the following: > library(RODBC) > chan1 <- odbcConnectExcel("D:/Data/mgc/Chips/Chips4.xls") > dd <- sqlFetch(chan1,"Raw") # all data 12000 > # > nzw <-
2012 Oct 24
0
RoR Developer (Full Time, Salary)
We are an established and profitable technology company, making software in the fast-growing medical marijuana industry. Although it would help, you do not need to be involved in the medical marijuana industry to apply. We work out of an office near the Denver Tech Center (Hampden & Yosemite). Day to day, we use Rails 3.2, Ruby 1.9.3/1.9.2, JavaScript (CoffeeScript), MySQL, and Git (Github).
2009 May 22
1
bug in rpart?
Greetings, I checked the Indian diabetes data again and get one tree for the data with reordered columns and another tree for the original data. I compared these two trees, the split points for these two trees are exactly the same but the fitted classes are not the same for some cases. And the misclassification errors are different too. I know how CART deal with ties --- even we are using the
2018 Jan 17
1
Assessing calibration of Cox model with time-dependent coefficients
I am trying to find methods for testing and visualizing calibration to Cox models with time-depended coefficients. I have read this nice article <http://journals.sagepub.com/doi/10.1177/0962280213497434>. In this paper, we can fit three models: fit0 <- coxph(Surv(futime, status) ~ x1 + x2 + x3, data = data0) p <- log(predict(fit0, newdata = data1, type = "expected")) lp
2008 Aug 01
5
drop1() seems to give unexpected results compare to anova()
Dear all, I have been trying to investigate the behaviour of different weights in weighted regression for a dataset with lots of missing data. As a start I simulated some data using the following: library(MASS) N <- 200 sigma <- matrix(c(1, .5, .5, 1), nrow = 2) sim.set <- as.data.frame(mvrnorm(N, c(0, 0), sigma)) colnames(sim.set) <- c('x1', 'x2') # x1 & x2 are
2005 Jun 15
1
anova.lme error
Hi, I am working with R version 2.1.0, and I seem to have run into what looks like a bug. I get the same error message when I run R on Windows as well as when I run it on Linux. When I call anova to do a LR test from inside a function, I get an error. The same call works outside of a function. It appears to not find the right environment when called from inside a function. I have provided
2010 Jul 31
2
Is profile.mle flexible enough?
Hi the list, I am experiencing several issues with profile.mle (and consequently with confint.mle) (stat4 version 2.9.2), and I have to spend a lot of time to find workarounds to what looks like interface bugs. I would be glad to get feedback from experienced users to know if I am really asking too much or if there is room for improvement. * Problem #1 with fixed parameters. I can't
2010 Sep 09
5
Highlighting a few bars in a barplot
Hello, I have a bar plot where I am already using colour to distinguish one set of samples from another. I would also like to highlight a few of these bars as ones that should be looked at in detail. I was thinking of using hatching, but I can't work out how or if you can have a background colour and hatching which is different between bars. Any suggestions on how I should do this? Thanks
2009 Apr 24
2
prediction intervals (alpha and beta) for model average estimates from binomial glm and model.avg (library=dRedging)
Hi all, I was wondering if there is a function out there, or someone has written code for making confidence intervals around model averaged predictions (y~á+âx). The model average estimates are from the dRedging library? It seems a common thing but I can't seem to find one via the search engines Examples of the models are: fit1 <- glm(y~ dbh, family = binomial, data = data) fit2 <-
2010 Feb 26
2
Error in mvpart example
Dear all, I'm getting an error in one of the stock examples in the 'mvpart' package. I tried: require(mvpart) data(spider) fit3 <- rpart(gdist(spider[,1:12],meth="bray",full=TRUE,sq=TRUE)~water+twigs+reft+herbs+moss+sand,spider,method="dist") #directly from ?rpart summary(fit3) ...which returned the following: Error in apply(formatg(yval, digits - 3), 1,
2006 Jan 02
1
Use Of makeARIMA
Hi R-Experts, Currently I'm using an univariate time series in which I'm going to apply KalmanLike(),KalmanForecast (),KalmanSmooth(), KalmanRun(). For I use it before makeARIMA () but I don't understand and i don't know to include the seasonal coefficients. Can anyone help me citing a suitable example? Thanks in advance. ------------------------------------------