similar to: help with POSIX

For the following code below, the x-axis ticks are 1,2,3,4,5,6,7 when I was expection them to be 1,2,8,9,10,11,12. Please help me figure out where is the mistake. library(lattice) testdata <- as.data.frame(t(structure(c( 1,2005,9.24,6.18,634, 2,2005,8.65,6.05,96, 8,2004,6.81,6.51,16, 9,2004,9.0,7.29,8, 10,2004,8.84,6.18,524, 11,2004,8.54,6.35,579, 12,2004,9.97,6.3,614, 12,2005,8.75,5.84,32,

For the following code is there a way to make the jitter all line up horizontally, instead of them being just randomly spread around a value. So for ex if there are multiple values at 63 for genotype wt then all the values should be plotted on the same y value of 63 but spaced apart by a certain factor or noise.. library(lattice); dataFrame <- as.data.frame(t(structure(c( 64,'wt',

-----Original Message----- From: Ghosh, Sandeep Sent: Thursday, June 30, 2005 5:43 PM To: 'Berton Gunter' Subject: plot legend outside the grid Thanks for the pointers... I managed to get everything to look and feel the way I want except for the legend to plot outside the grid... Thanks for the note on the par, but I'm not able to it to plot outside the plot grid.. dataFrame <-

I am trying to download a bunch of files from a server, for which I am using download.file( ) within a for loop. The script is working fine except until download.file hits a URL which has no file, at which point it exits. I want to change this behavior to simple log the failure and maintain state within the for loop and iterate to next. I read about try / tryCatch but am having trouble

Gabor, Thanks much. Your solution is elegant. My overall scheme is to take present date, and check whether it is a weekend, if not, then create a string based on the date, to concatenate into a url link for download.file( ). The files I need to download have a part which is in the format: mmddyy. I am working to make myself a system to connect to exchanges, and download end of day files from

Thanks Bert for all the help. I got the legend figured out Friday but left early becoz of long weekend so didn't get a chance to reply.. I modified the plot margins a little bit and Here's what I finally had... par(mar=c(c(10, 6, 6, 10) + 0.1)); par(xpd=FALSE); with (dataFrame, stripchart(marbles_buried ~ genotype, method="jitter", vertical=TRUE, col = c('blue',

Hi All.. Have a question.. For the following r code testdata <- as.data.frame(t(structure(c( "1/1/04","LV1",3.8,2,87, "2/1/04","LV1",3.2,3,28, "3/1/04","LV1",3.4,3,88, "4/1/04","LV1",3,2,26, "5/1/04","LV1",3.8,2,87, "6/1/04","LV1",3.2,3,28,

Hello I am new to R and I need to convert some dates (numeric format by matlab) to actual dates in R. For instance, Matlab -> 730456 -> >> datestr(730456) ans = 02-Dec-1999 R - > library(zoo) > as.Date(730456) [1] "3969-12-03" I don't not mind the output format but it needs to be right. Many thanks Ed

Running R 1.9.1 under red hat 2.1 version When I try to generate an image, we get an error as in the following plot(rnorm(100)) Error in PS(file, old$paper, old$family, old$encoding, old$bg, old$fg, : unable to start device PostScript In addition: Warning message: cannot open `postscript' file argument `Rplots.ps' If anyone can throw some light or any pointers into why we are

Hi All, I have a quick question and any help is greatly appreciated. For the following data when I try to produce the image using xyplot function in lattice package, the key has 4 rows instead of 2. Can anyone tell me what I'm doing wrong and what is the way to fix the problem. Here the code that I'm running studyData <- as.data.frame(t(structure(c( "A",0,4.477,

Hello, I have a zoo time series object (say a) with the following time stamp/format [1] "1950-01-03 GMT" "1950-01-04 GMT" "1950-01-05 GMT" "1950-01-06 GMT" [5] "1950-01-09 GMT" "1950-01-10 GMT" and another (say b) with [1] "1950-01-05" "1950-01-06" "1950-01-09" "1950-01-10"

Hi All, For the following code, I'm not sure why the error bars are appearing horizontal. Can someone please tell me how to fix the problem. testdata <-

I want to change the way the plot is appearing in the barchart .. testdata <-

The problem with POSIXt is that you must consider timezones and daylight vs. standard time issues even if you don't want to. This violates modularity (viz. your routines becomes coupled to unrelated information) and leads to subtle errors where different routines are assuming different time zones. The problem is that the time, date, day of the week, month, etc. of a date depend on its

converting a POSIX class variable to a date class is easy. dates<-as.Date(x) #where X is of class POSIX How does one do that to all columns in a data frame that are of POSIX class and leave all the other columns (integers, factors) as is. Feel free to reply with just one or two buzzwords that I could then search for to find how to do it. Farrel Buchinsky

# pure replication code at end > # These work > > Sys.time() + NA [1] NA > as.POSIXlt(Sys.time(), "GMT") + NA [1] NA > > class(Sys.time() + NA) [1] "POSIXt" "POSIXct" > class(as.POSIXlt(Sys.time(), "GMT") + NA) [1] "POSIXt" "POSIXct" > > x <- Sys.time() + NA > y <- as.POSIXlt(Sys.time(),

Hi, I''m stuck. How do you parse a "dd/mm/yyyy" formatted date string??? I get a date format error. Thanks in advance Greg --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to

I am having a series of problems using date time data that has been converted into a POSIXt and POSIXlt classes. I have hourly time series data from 1900 that has been converted from text data. I assume most of my problems come from a mis-underdanding of the POSIX class. My matrix named (aa) for this year is approx 8700 by 4. When I try to calculate the length of posit column ( which is the

Thanks Rafael, wondering as of what is the level of support for ARM and is it close to production quality? Thanks On Mon, Feb 26, 2018 at 2:06 PM, Rafael Avila de Espindola < rafael.espindola at gmail.com> wrote: > Not sure there is an official POC, you are probably better off asking > whatever question you have directly on the list. > > Cheers, > Rafael > > Sumonto

Hi, One of the big decisions when writing code is how to handle dates and times. Gabor Grothendieck provided an excellent overview of the issue in his R News 4/1 (2004) article, and many users and developers are probably using it as a guide. The proposed guideline is to use the simplest class required; as Gabor put it "use Date if possible, otherwise use chron, and otherwise use