similar to: Storing vectors as vectors and iterating through them

Hi all, I've got a data frame that has an identical column to a chr vector. I would like to use the chr vector to order the rows of the data frame to be identical to the order in the chr vector (the contents of the chr vector are completely identical to one col of the data frame), but this is proving trickier than it sounds.. Any help would be much obliged, -Ken

I have a matrix of, say, M and N dimensions: my_matrix=matrix(c(1:60),nrow=6,ncol=10) I have two "id" vectors corresponding to the rows and columns, e.g.: id_m=seq(10,60,by=10) id_n=seq(100,1000,by=100) I would like to create a "proper" database (let's say a data.frame for this example -- i'm going to be loading these into an SQLite database, but we'll leave

Hi R-users I can not change the name of one column only of my matrix. my_matrix <- matrix (1:12,ncol=3) colnames(my_matrix)[1] <- 'myname' Error in dimnames(x) <- dn : length of 'dimnames' [2] not equal to array extent thank you for your help Lorenzo [[alternative HTML version deleted]]

Hi all, I've got a matrix of fractional data that is all positive and greater than zero that I would like to "loosely" classify, for lack of a better word. It looks something like this : 1.07 1.11 1.27 1.59 0.97 0.76 2.23 0.98 0.71 0.88 1.19 1.02 What I'm looking for is a way to round these numbers to the nearest 0.25, i.e. the above matrix would be

Hello, I saw this nice trick I want to replicate but I lost the source and I hope one of you can point me to the solution. My problem is that I don't know the correct words to query this. When I print to screen a matrix or data.frame the columns are split and printed below the previous ones; even though I have plenty of screen left. E.g., > my_matrix = matrix(runif(30),nrow=3,ncol=10)

Hello, I have 2 functions (a and b) a = function(n) { matrix (runif(n*2,0.0,1), n) } > > > b = function (m, matrix) { > n=nrow (matrix) > p=ceiling (n/m) > lapply (1:p, function (l,n,m) { > inf = ((l-1)*m)+1 > if (l<p) sup=((l-1)*m)+m > else sup=n >

On Wed, Feb 15, 2023 at 03:11:34PM +0100, Laszlo Ersek wrote: > The "name##_iter" function is used 11 times in libnbd; in all those cases, > "name" is "string_vector", and the "f" callback is "free": > > string_vector_iter (..., (void *) free); > > Casting "free" to (void*) is ugly. (Well-defined by POSIX, but

Hi all, I've got a package i've written that i am trying to check, build, and install. This is my 1st time doing this, so apologies in advance... ;) The package that I've written requires input from the user. It needs to know sample sizes and then runs some calcs, (sample sizes are just integers), and it gets this info from the user as num_reps <- readline("How many reps

Hello Everyone, I am using R for creating heatmap from a square matrix. Below is my script to do so my_map <- read.csv("Desktop/input.csv", sep=",") my_matrix <- data.matrix(my_map) my_heatmap <- heatmap(my_matrix, Rowv=NA, Colv=NA, col = cm.colors(256), scale="column", margins=c(5,10)) I get a beautiful plot as output, but I could not save this plot

Hi, I have a comma separated file with element names in first column like shown below : Name_1,0 Name_2,0.8878,0 Name_3,0.6777,0.7643,0 Name_4,0.9844,0.1234,0.1414,0 Original data is a 10000x10000 symmetric matrix (600 MB). To reduce file size, I have minimized matrix to only lower triangle. Is there a (memory) efficient way to 1) read file 2) compute first and second principal components and

Hi all, I've got a script that generates a few moderate-size data frames, and then puts them together into one big data frame at the end in order to write that data frame to disk, so that it may be re-opened later on... I'm trying to trim down memory requirements in this script, so I was wondering if there was any way to append to a data frame already saved on disk (just like

On Tue, Feb 21, 2023 at 05:23:52PM +0100, Laszlo Ersek wrote: > On 2/20/23 21:38, Eric Blake wrote: > > On Mon, Feb 20, 2023 at 06:03:13PM +0100, Laszlo Ersek wrote: > >> On 2/15/23 21:27, Eric Blake wrote: > >>> On Wed, Feb 15, 2023 at 03:11:34PM +0100, Laszlo Ersek wrote: > >>>> The "name##_iter" function is used 11 times in libnbd; in all

Hi all, What I'd like to do is to is to be able to extract a string corresponding to only the file name from a string containing the complete path, i.e. from the following path string: "/Users/ken/Desktop/test/runs/file1" I would like to end up with: "file1" This would be most ideally done in a platform-independent way. Thanks in advance, -Ken

Dear All, While inverting a matrix the following error appears on my console: Error in solve.default(my_matrix) : Lapack routine dgesv: system is exactly singular With this respect, I have been replacing the solve() function with ginv(): the Moore-Penrose generalized inverse of a matrix. These are the questions I would like to ask you: 1. Would you also replace solve() with ginv() in

Hello R-Users! I'm using a heatmap to visualize a matrix of values between -1 and 3. How can I set the colors so that white is zero, below zero is blue of increasing intensity towards -1 and above zero is red of increasing intensity towards red? I tried like this (using the marray and gplots packages from bioconductor): mcol <- maPalette(low="blue", mid="white",

Hi all, How can I decrease the number of ticks on the y-axis in a lattice levelplot()? I have as many ticks displayed on the y-axis as I have columns of data (1000 columns), how can I decrease this amount of ticks, while still properly displaying all the data? Note that I get my data from a matrix object, in which the z-values of the levelplot are the actual values in the matrix, whereas the

Hi all, As far as I can tell, the only canned way to do an intersect between two vectors of ints is the intersect(vec1, vec2) function -- is there another function I'm missing for intersecting more than two vectors?? TIA, Ken

Dear R gurus, I'm trying to solve what I assume is a fairly simple problem, but I'm having trouble finding the proper approach. I have a matrix where each column is some object (e.g. a car) and each row is a numeric measurement of a feature of said object (e.g. horse power, top speed, etc.). Let's also suppose that I know what make the car is (e.g. toyota, ford, etc.), stored in a

Hi all, I was hoping that someone could verify this for me- when I run princomp() on a matrix, it is my understanding that the scores slot of the output is a measure of how well each row correlates (for lack of a better word) with each principal component. i.e. say I have a 300x6 log2 scaled matrix, and I run princomp(). I would get back a $scores slot that is also 300x6, where each value

Hello, Since people have whisperred about Rcpp, I'd like to play too. > On 11/15/2010 07:45 AM, Patrick Leyshock wrote: >> Very helpful, thank you. >> >> A couple other questions, please: >> >> 1. I've got a function written in C, named "my_c_function". In my R >> code I call this function, passing to it an INTSXP and a STRSXP, >>