similar to: sorting a data.frame using a vector

Hi, I apologize for this often/old question. I found some hints but couldn't solve the problem so far. I have C functions (incl. the header files) as well as the R wrapper functions which I want to use for faster calculations. These functions are included in a R package. The installation process seems to be ok (no errors). I also can load the package without errors. But when I call the

Hi all, I'm very new to R. I have installed R 1.9.0 on Linux (Fedora). Now I got an self-made package comprising R functions as well as C-Code which are used in several R functions. I installed the package without any error (see install log below). Then, I checked in /usr/lib/R/library if the package izbi exists and it exists. But whenever I try to load the library on the command line I

If we capture transform feedback from n stream in (n-1) buffers we face a NULL buffer, use the buffer (n-1) to capture the output of stream n. This fixes one piglit test with nvc0: arb_gpu_shader5-xfb-streams-without-invocations Signed-off-by: Tobias Klausmann <tobias.johannes.klausmann at mni.thm.de> --- src/mesa/state_tracker/st_cb_xformfb.c | 5 +++++ 1 file changed, 5 insertions(+)

If a transform feedback buffer's size is 0, st_bufferobj_data doesn't end up creating a buffer for it. There's no point in trying to write to such a buffer, so just pretend as if it's not really there. This fixes arb_gpu_shader5-xfb-streams-without-invocations on nvc0. Signed-off-by: Ilia Mirkin <imirkin at alum.mit.edu> --- src/mesa/state_tracker/st_cb_xformfb.c | 2 +- 1

On 11.01.2015 06:05, Ilia Mirkin wrote: > Can you elaborate a bit as to why that's the right thing to do? > > On Wed, Jan 7, 2015 at 1:52 PM, Tobias Klausmann > <tobias.johannes.klausmann at mni.thm.de> wrote: >> If we capture transform feedback from n stream in (n-1) buffers we face a >> NULL buffer, use the buffer (n-1) to capture the output of stream n.

On 12.01.2015 01:57, Ilia Mirkin wrote: > On Sun, Jan 11, 2015 at 7:43 PM, Tobias Klausmann > <tobias.johannes.klausmann at mni.thm.de> wrote: >> >> On 11.01.2015 06:05, Ilia Mirkin wrote: >>> Can you elaborate a bit as to why that's the right thing to do? >>> >>> On Wed, Jan 7, 2015 at 1:52 PM, Tobias Klausmann >>>

Hi I have submitted a package (rioja) to CRAN. It checks OK for all R versions and OS's except r-release-macosx-ix86 where it fails when checking the examples. Specifically, it fails because R can't find the package vegan which is needed in a function. Here is the snippet from the check results: ### Begin snippet checking examples ... ERROR Running examples in 'rioja-Ex.R'

Hi, I am trying to use tune.svm in e1071 package. the command i use is tobj <- tune.svm(labels, data= data, cost = 10^(1:2)) Should the last column of the 'data' contain the labels as well? I want to use the linear kernel. But it gives me the error "Error in model.frame.default(formula, data) : 'data' must be a data.frame, not a matrix or an array" Do you know why

Can you elaborate a bit as to why that's the right thing to do? On Wed, Jan 7, 2015 at 1:52 PM, Tobias Klausmann <tobias.johannes.klausmann at mni.thm.de> wrote: > If we capture transform feedback from n stream in (n-1) buffers we face a > NULL buffer, use the buffer (n-1) to capture the output of stream n. > > This fixes one piglit test with nvc0: >

Dear R experts, I want to plot a line chart with another secondary axis placed right to the standard secondary axis which one can access with the axis command, so that the data lines are seen in the same plot. Is there any way to do this in R? Many thanks, Kirsten.

On Sun, Jan 11, 2015 at 7:43 PM, Tobias Klausmann <tobias.johannes.klausmann at mni.thm.de> wrote: > > > On 11.01.2015 06:05, Ilia Mirkin wrote: >> >> Can you elaborate a bit as to why that's the right thing to do? >> >> On Wed, Jan 7, 2015 at 1:52 PM, Tobias Klausmann >> <tobias.johannes.klausmann at mni.thm.de> wrote: >>>

Dear Rdevelopers The background for this email is that I was helping a PhD student to improve the speed of her R code. I suggested to replace calls like t(AA)%*% BB by crossprod(AA,BB) since I expected this to be faster. The surprising result to me was that this change actually made her code slower. > ## Examples : > > AA <- matrix(rnorm(3000*1000),3000,1000) > BB <-

Hello everyone, I have a .csv file with the following format: uniqueID SubjectID Distance_miles Tag 1 1001 5.5 3 2 1001 7 1 3 1001 6.5 1 4 1001 5 1 5 1002

Hello, The problem I'm working now requires to operate on big matrices. I've noticed that there are some packages that allows to run some commands in parallel. I've tried snow and NetWorkSpaces, without much success (they are far more slower that the normal functions) My problem is very simple, it doesn't require any communication between parallel tasks; only that it divides

Dear list, dear Frank, I try to fit a Weibull survival regression model with package Design: sclear <- psm(sobj~V1+V2,dist="weibull") sobj is a one-dimensional survival object (no event indicators), V1 and V2 are factors. I get the following result: Parametric Survival Model: Weibull Distribution psm(formula = sobj ~ V1 + V2, dist = "weibull") Obs Events

Hi, I have a 5x731 array A, and I want to compute the sums of the columns. Currently I do: apply(A, 2, sum) But it turns out, this is slow: 70% of my CPU time is spent here, even though there are many complicated steps in my computation. Is there a faster way? Thanks, Martin

Hi, Couldn't is.unsorted() bail out immediately here (after comparing the first 2 elements): > x <- 20000000:1 > system.time(is.unsorted(x), gcFirst=TRUE) user system elapsed 0.084 0.040 0.124 > x <- 200000000:1 > system.time(is.unsorted(x), gcFirst=TRUE) user system elapsed 0.772 0.440 1.214 Thanks! H.

I have a list of ICD9 (disease) codes with various formats - 3 digit, 4 digit, 5 digit. The first three digits of these codes are what I am most interested in. I would like to either add zeros to the 3 and 4 digit codes to make them 5 digit codes or add decimal points to put them all in the format ###.##. I did not see a function that allows me to do this in the formatting command. This seems

Dear all: I am comparing the PLS outputs of R and SAS for the following data set: Y x1 x2 x3 3 6 2 2 3 1 5 5 4 7 4 1 5 6 5 6 2 4 3 2 8 5 0 9 where Y is the dependent variable and x1, x2, x3 are the independent variables. I found several PLS algorithms in R (NIPALS,SIMPLS,KERNEL PLS). SAS has SIMPLS and NIPALS. The following are the NIPALS calculations of

Hello, I have a problem with using replace() to convert a vector of dates from yyyy-mm-dd to julian date. For example, I type replace(x,2004-05-14,134) and I receive an error: Error in `[<-.data.frame`(`*tmp*`, list, value = 134) : new columns would leave holes after existing columns If I can successfully convert, I have a script that will convert all of the dates in