similar to: plotting multiple series in one plot

Say you have a vector named x and a function which returns the character string "x" . How would I take "x" as an input and return the vector x? DISCLAIMER: This e-mail message and any attachments are inte...{{dropped}}

I know this is very basic--I'm wondering if there is a way to write data frames as outputs from a loop. In other words, take this simple example: > a <- data.frame(x = c(1,2,3,4), y = c(1,2,1,2)) Given a, how would you write a loop that creates two data frames, x and y, where the first column is a column of a and the second column is two times the first column, or: > x x.1

Hi: I need to plot two data sets and then I need to change labels of xaxis. I can manage to achieve something like it with this: x<-data.frame(a=c(1,2,3,4,5),b=c(2,4,6,8,10)) y<-data.frame(a=c(3,4,5),b=c(1.5,2,2.5)) xts <- ts(x$b,start=x$a[1]) yts <- ts(y$b,start=y$a[1]) ts.plot(xts,yts,col=c("red","blue")) But ts.plot does not allow to change x labels. Besides,

Hi: I need to plot two time series in the same plot and they cover the same time range and have the same frequency. With RSiteSearch("multiple series plot") i found this post by Gabor Grothendieck: http://finzi.psych.upenn.edu/R/Rhelp02a/archive/42281.html Exactly what i need except for one detail. I want one series to be made of points and the other by a line. When I simply try: xts

Hi, I am fairly new to R so this may be easy for some. I have one column that is the Type="A, B' T" and I have another column that lists Price='894, 895, 896' I wanted to plot three different series based upon the Type...If B than xts..If T yts... How exactly do I do this? Thanks in advance -- View this message in context:

Dear all, I found really difficult with the time series questions, please help me with this monthly airline series! I have run the following r code, and there is an error appeared at the end. The data files was enclosed in the email. I'm sorry the errors message appeared in chinese, but it says "plot.xy(xy.coords(x, y), type = type, ...) : errors in argument has more than 3

Greetings, I would like to estimate a spectral coherence between two timeseries. The stats : spectrum() returns a coh matrix which estimates coherence (squared). A basic test which from which i expect near-zero coherence: x = rnorm(500) y = rnorm(500) xts = ts(x, frequency = 10) yts = ts(y, frequency = 10) gxy = spectrum( cbind( xts, yts ) ) plot( gxy $ freq, gxy $

Hi, i have a problem in assigning 2 conditions to grep() , my data look like this: DA 24 N7 Rad= 3.4 20 Sac= 0.93 Acc= 4.76 DA 24 N7 Rad= 3.4 14 Sac= 0.65 Acc= 3.33 DA 24 N7 Rad= 3.4 3 Sac= 0.14 Acc= 0.71 DA 24 N7 Rad= 3.4 11 Sac= 0.51 Acc= 2.62 DG 23 N7 Rad= 3.4 8 Sac= 0.37 Acc= 1.91 DG 23 N7 Rad= 3.4 5 Sac= 0.23 Acc= 1.19 DG 23 N7 Rad= 3.4 0 Sac= 0.00 Acc= 0.00 DG 23 N7 Rad= 3.4 3 Sac=

Dear R-helpers, I am a beginner using R. This is the first question in this list. My question, Is there possible to make combinations with two part column? If I have a number 1,2,3,4,5,6,7,8. I need the result something like below: 1,2,3,4,5 6,7,8 1,2,3,4,7 5,6,8 2,3,4,5,6 1,7,8 1,2,3,6,7 4,5,8 1,2,3,4,8 5,6,7 3,4,6,7,8 1,2,5 .... I would be very happy if anyone could

I think this is another one of the same kind of bugs in ts: Version 0.64.1 (May 8, 1999) ... > z <- ts(matrix(1:20,10,2), start=c(1969,1), frequency=12) > (z > 5) | (z < 2) Error: invalid time series parameters specified > Paul -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-devel mailing list -- Read

Having read previous correspondance on this topic, am I right in using a gaussian distribution for a tobit model, one article suggests a normal distribution? Also, I want to censure at the upper bound, so, using the survival5 package I use: survreg(Surv(y,y<c,type="right")~x) for a censored regression. Could anybody who's had experience of this, confirm whether I'm in the

Hi, I would like to know if it's ok to use .Internal(inspect(x)) in order to detect vector copying. Take for example the following silly code: f <- function() { x = seq(10) print(.Internal(inspect(x))) for(i in seq(10)) { x[i] <- x[i] + 1 print(.Internal(inspect(x))) } } The output of f() was: @bd7acf0 13 INTSXP g0c4 [NAM(1)] (len=10, tl=0) 1,2,3,4,5,... [1] 1 2

Hello, I'm creating a loop to work with vegan, to get a species abundance curve. Here I send the script I've created and also an excel file to prove what it can do. Well, I have a database with 20 years, and each year we have sampled 19 stratum, and in each estratum we have carry out some sumpling. Then, with the script that I've sent I've got to calculate the species abundance

Full_Name: Bill Simpson Version: 65.1 OS: Linux Redhat 6.1 Submission from: (NULL) (193.62.250.209) Try this: #default plot symbols and lettering are too small, need to scale up par(cex=2,mex=.7) par(mar=c(5,5,1,1)) spdiff<-c(1,2,3,4,5) dpdet<-c(1,2,3,4,5)/10 dpsp<-c(2,3,4,5,6)/10 dpdir<-c(2,4,6,8,10)/10 plot(spdiff,dpdet,pch=15,ylim=c(0,max(dpdet,dpsp,dpdir)),xlab="Speed

On 23/11/2012, at 5:46 PM, Sean Silva wrote: > Adding LLVMdev, since this is intimately related to the optimization passes. > >> I think this is roughly because some function level optimisations are >> worse than O(N) in the number of instructions. > > Please profile this and mail llvmdev regarding passes with > significantly superlinear behavior (e.g. O(n^2)). My

Is there any way to control the spacing between bars in a histogram, or change the border width (I'm assuming the hist() function, though alternatives are welcome)? I'm interested in changing the visual spacing between columns in a plotted histogram. The general effect I'm looking for can be accomplished in barplots using the "width=" parameter, but I have not been able

Very New to R trying to get setup but when i try to install shiny i get trying URL 'http://cran.rstudio.com/src/contrib/shiny_1.0.4.tar.gz' Content type 'application/x-gzip' length 2329723 bytes (2.2 MB) downloaded 2.2 MB Warning in install.packages : running command '"C:/PROGRA~1/R/R-34~1.1/bin/x64/R" CMD INSTALL -l

Hi Rowland, The line 60 contains "{" in the script. The exit 1 statement is on line number 58. Am I missing something? Regards Sachin Kumar On Fri, Nov 29, 2019 at 5:21 PM Rowland penny via samba < samba at lists.samba.org> wrote: > On 29/11/2019 11:28, Sac Isilia wrote: > > Hi Rowland, > > > > I get below error while running the script again. > >

Yes windows How can i install from zip? Here is my command > install.packages("shiny") Installing package into ?C:/Users/Zack/Documents/R/win-library/3.4? (as ?lib? is unspecified) There is a binary version available but the source version is later: binary source needs_compilation shiny 1.0.3 1.0.4 FALSE installing the source package ?shiny? trying URL

Quick question: I am going to use the file_column plugin to manage uploading thumbnails. By default the images are stored in the public/ dir of the rails project. The problem I see is that when capistrano redeploys a new build and symlinks it in none of the images will be in the new public/ dir... Does anyone have a solution for this? Thanks, Zack -------------- next part -------------- An