similar to: How to extract data?

Hi all, Hope you people do not feel irritated for repeatedly sending mail on Time series. Here I got another problem on the same, and hope I would get some answer from you. I have following dataset: data[,1] [1] 4.96 4.95 4.96 4.96 4.97 4.97 4.97 4.97 4.97 4.98 4.98 4.98 4.98 4.98 4.99 4.99 5.00 5.01 [19] 5.01 5.00 5.01 5.01 5.01 5.01 5.02 5.01 5.02 5.02 5.03 5.03 5.03

Dear List I hope you can help me: I?ve got a dataframe (df) within which I am looking for Peak Over Threshold values as well as the length of the events. An event starts when walevel equals 5.8 and it should end when walevel equals the lower threshold value (5.35). I tried ?clusters (?)? from ?evd package?, and varied r (see example) but it did not work for all events (again

I'll appreciate if some one can help me with the following loop. This is the logic of the loop, if we have the following data; > x.df x.dif . . . . 102 0.00 103 0.42 104 0.08 105 0.00 106 0.00 107 0.00 108 -0.16 109 -0.34 110 0.00 111 -0.17 112 -0.33 113 0.00 114 0.00 115 0.00 116 0.33 117 0.17 118 0.00 . . . . I'm trying to find i's where for (i

R users; Does anyone have a recommendation for a faster plotting function rather than plot(x,y)? when I use plot(x,y) for a large number of variables, it take couple of moments to plot the graph? Sincerely, Sean

I have a binary vector and I want to find all "regions" of that vector that are runs of TRUE (or FALSE). > a <- rnorm(10) > b <- a<0.5 > b [1] TRUE TRUE TRUE FALSE TRUE FALSE TRUE TRUE TRUE TRUE My function would return something like a list: region[[1]] 1,3 region[[2]] 5,5 region[[3]] 7,10 Any ideas besides looping and setting start and ends directly?

R friends, I am using R 2.1.0 in a Win XP . I have a problem working with lists, probably I do not understand how to use them. Lets suppose that a set of patients visit a clinic once a year for 4 years on each visit a test, say 'eib' is performed with results 0 or 1 The patients do not all visit the clinic the 4 times but they missed a lot of visits. The test is considered positive if it

well! excuse me again but... your.string <- "aaacdf" nc1 <- nchar(your.string)-1 x <- unlist(strsplit(your.string, NULL)) ######## CORRECT x2 <- c() for (i in 1:nc1) x2 <- c(x2, paste(x[i], x[i+1], sep="")) ######## ERRATA 2 cat("ocurrences of <aa> in <your.string>: ", length(grep("aa", x2)), sep="", fill=TRUE) Fran

Dear R-Helpers, I have a large data matrix, which contains missing data. The matrix looks something like this: 1) X X X X X X NA NA NA 2) NA NA NA NA X X X X X 3) NA NA X X X X NA NA NA 4) X X X X X X X X X 5) X X NA NA X NA NA NA NA and so on. Notice that the first row starts with complete data but ends with missing. The second row starts with missing, but the rest is

Hello, just another problem in R, maybe it's simple to solve for you. I didn't find a solution up to now, but I'm convinced that I'm not the only one who has/had a similar problem. Maybe there's a ready-made function in R? The prob: I've imported a CSV-file into R with 1000 dates of an observed event (there's only information of the date. When there happend no

Dear R Users; Perl is the common language to write CGI scripts which handle Forms. My question is that can R be as fast as perl to do the same job(with using CGIwithR package). Is it an optimal solution to connect R directly to a commercial HTML webpages, Sincerely, Sean

Dear R users; I am using R for a project. I have some PHP forms that pass parameters to R for calculations, and publish the result in HTML format by CGIwithR. I'm using a Linux machine and every things work perfectly. However, it is too slow, it takes 5 to 10 seconds to run, and even if I start R from the Shell it takes the same amount of time, which is probably due to installing packages.

Hi all, I've got a matrix of fractional data that is all positive and greater than zero that I would like to "loosely" classify, for lack of a better word. It looks something like this : 1.07 1.11 1.27 1.59 0.97 0.76 2.23 0.98 0.71 0.88 1.19 1.02 What I'm looking for is a way to round these numbers to the nearest 0.25, i.e. the above matrix would be

I have a function that does some plotting. I then add lines to the plot. If executed one line at a time, there is not a problem. If I execute the function, though, I get: Error in ans[[1]] : subscript out of bounds This always occurs after the second lines command, and doesn't happen with all of my data points (some do not have errors). Any ideas? Thanks, Sean

Dear R users and Helpers I am beginner with using R and interested in carrying out certain task for my statistical research. I am reading data for a text file, which could contain data in following pattern x y 8 10 11 14 16 16 18 15 6 20 4 4 20 18 As per the example I have two columns and 7 rows of data in each. However is real life data situation I may not know how many columns are present

Dear List, Suppose we have a variable K.JUN defined as (with 1=wet, 0=dry): K.JUN1984 = c(1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1) K.JUN1985 = c(0, 1, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 1, 1, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1) K.JUN1986 = c(0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1)

I generated a PDF output file of 10 plots. When I try to view it with Adobe reader (R4 & R5), it will lockup the reader (it is consuming 100% of the CPU) after presenting the 4th plot. I can generate the plots just fine in Windows and as a postscript file reading it with GSview. Is there anyway to tell what might be wrong with the PDF output? The file is 890KB in size if anyone would like

Anyone have luck with pxechn32 and bootmgfw.efi? I'm getting the "Unable to retrieve first package" issue as reported by others. Really, any advice for UEFI booting into a winpe environment off of pxelinux 6.03 would be beneficial. Jason Jones Sr. Associate, Network Services | End User Computing 3947 N Oak St Ext | Valdosta, GA 31605 O +15137844955 E jason.s.jones at

why? > rle Run Length Encoding lengths: int [1:1650061] 2 2 8 2 4 5 6 3 26 46 ... values : chr [1:1650061] "4bbf9e94cbceb70c BG bg" "4fbbf2c67e0fb867 SK sk" ... > as.data.frame(rle) Error in as.data.frame.default(vertices.rle) : cannot coerce class '"rle"' into a data.frame it seems that rle.df <-

Thanks a lot, James!! The problem is fixed. On the version 1.4.0 Mac/darwin (the latest available version for this system) the function read.table (which is called from read.delim etc., too) has the bug you explained. Inserting the row nlines <- nlines+1 after lines <- c(lines, line) removes this bug. M. On Friday, February 22, 2002, at 02:33 PM, james.holtman at convergys.com

I want to make a histogram from the lengths vector which is part of the output of rle. But I don't know how to access that vector so that I use it as an argument of hist(). What argument must I use so that I use the lengths vector as an input to hist()? Example output is: Run Length Encoding lengths: int [1:4] 1 2 3 3 values : num [1:4] -1 1 -1 1 A printout of the function rle() may