Displaying 20 results from an estimated 10000 matches similar to: "(no subject)"
2012 Apr 24
2
Some Help Needed
Dear all,
I need to do some calculation where the code used are below. I get
error message when I choose k to be large, say greater than 25.
The error message is
"Error in integrate(temp, lower = 0, upper = 1, k, x, rho, m) :
the integral is probably divergent".
Can anyone give some help on resolving this. Thanks.
Hannah
m <- 100
alpha <- 0.05
rho <- 0.1
F0
2011 Sep 03
3
question with uniroot function
Dear all,
I have the following problem with the uniroot function. I want to find
roots for the fucntion "Fp2" which is defined as below.
Fz <- function(z){0.8*pnorm(z)+p1*pnorm(z-u1)+(0.2-p1)*pnorm(z-u2)}
Fp <- function(t){(1-Fz(abs(qnorm(1-(t/2)))))+(Fz(-abs(qnorm(1-(t/2)))))}
Fp2 <- function(t) {Fp(t)-0.8*t/alpha}
th <- uniroot(Fp2, lower =0, upper =1,
2011 Feb 21
1
question about solving equation using bisection method
Hi all,
I have the following two function f1 and f2.
f1 <- function(lambda,z,p1){
lambda*(p1*exp(-3*z-9/2)+(0.2-p1)*exp(4*z-8))-(1-lambda)*0.8}
f2 <- function(p1,cl, cu){
0.8*(pnorm(cl)+(1-pnorm(cu)))/(0.8*(pnorm(cl)+(1-pnorm(cu)))+p1*(pnorm(cl+3)+(1-pnorm(cu+3)))+(0.2-p1)*(pnorm(cl-4)+(1-pnorm(cu-4))))}-0.05
First fix p1 to be 0.15.
(i) choose a lambda value, say lamda=0.6,
(ii)
2009 Sep 23
1
Maximum Likelihood Est. regarding the degree of freedom of a multivariate skew-t copula
Hello,
I have a bigger problem in calculating the Maximum Likelihood Estimator regarding the degree of freedom of a multivariate skew-t copula.
First of all I would like to describe what this is all about, so that you can understand my problem:
I have 2 time series with more than 3000 entries each. I would like to calculate a multivariate skew-t Copula that fits this time series.
Notice:
2007 Sep 24
1
Root finding problem
Hello,
I have a problem finding a root of a function, which I define like this:
tuki <- function(u, x, a, lambda){
if((lambda%%1>0) & u<0) {u<-(u+0i)}
f <- Re(x-(a*(u)^lambda-(1-(u))^lambda)/lambda)
f
}
What I want to do is to find the root, but without specifying the
interval within which to search for it. I can do it easily in MATLAB
with fsolve() or fzero() functions.
I
2003 Apr 25
4
Kinderman-Ramage (PR#2846)
Hi,
Our department has detected a bug in the implementation of the
Kinderman-Ramage generator for normal random variates in version
1.7.0, which can be seen from the below R session.
(Consecutive calls for chisq.test(...) always gives p-values very
close to 0.)
We have already encountered this bug in version 1.6.2
The error is in file
R-1.7.0/src/nmath/snorm.c
Here is a patch for this file to
2011 Mar 29
5
Integration with variable bounds
If this is posted elsewhere I cannot find it. I need to perform multiple
integration where some of the variables are in the bounds of the other
variables. I was trying to use R2Cuba function but cannot set the upper and
lower bounds. My code so far is :
int <- function(y){
u2 = y[1]
z2 = y[2]
u1 =y[3]
z1 = y[4]
ff <- u1*(z1-u1)*u2*(z2-u2)*exp(-0.027*(12-z2))
return(ff)
}
2007 Mar 27
3
Use of 'defineVar' and 'install' in .Call
Dear all,
[system and version information below]
I am trying to modify a C function for finding the root of an
expression. The function is to be called from R as .Call with input
parameters:
f: expression for which we will find the root
guesses: interval for the solution
stol: tolerance
rho: environment
The original functions I use are:
SEXP mkans(double x) {
SEXP ans;
PROTECT(ans =
2007 Mar 27
3
Use of 'defineVar' and 'install' in .Call
Dear all,
[system and version information below]
I am trying to modify a C function for finding the root of an
expression. The function is to be called from R as .Call with input
parameters:
f: expression for which we will find the root
guesses: interval for the solution
stol: tolerance
rho: environment
The original functions I use are:
SEXP mkans(double x) {
SEXP ans;
PROTECT(ans =
2009 Feb 05
1
optimal control, maximization with several variables?
Dear all,
I would like to solve the following problem, which can be done with optimal control theory or dynamic programming:
max(x,y) a*u1+b*u2+c*f1(u2) s.t. 0<u1<x, 0<u2<f2(x,u2), x'=f3(u1,u2,x)
which can be rewritten if optimal control theory should be applied as
H=a*u1+b*u2+c*f1(u2)+lambda*(x') s.t. 0<u1<x, 0<u2<f2(x,u2)
The maximum principle
2000 Jan 12
1
Usage of p/d/qnorm
Hello,
could You please help: I am looking for a way to formulate test accuracy
measures such as test sensitivity, specificity, predictive values, and
correct classification rate using p/d/qnorm. The tests' primary values
follow a bimodal distribution, which is modelled by a mixture of two normal
distributions:
p * dnorm ((x - u1) / s1) / s1 +
(1 - p) * dnorm ((x - u2) / s2) / s2)
2010 Jun 13
2
help with R
Hi all,
I want to solve the following equation for x with rho <- 0.5
pnorm(-x)*pnorm((rho*dnorm(x)/pnorm(x)-x)/sqrt(1-rho^2))==0.05
Is there a function in R to do this?
Thank you very much!
Hannah
[[alternative HTML version deleted]]
2005 Mar 09
3
problem using uniroot with integrate
Hi,
I'm trying to calculate the value of the variable, dp, below, in the
argument to the integral of dnorm(x-dp) * pnorm(x)^(m-1). This
corresponds to the estimate of the sensitivity of an observer in an
m-alternative forced choice experiment, given the probability of
a correct response, Pc, a Gaussian assumption for the noise and
no bias. The function that I wrote below gives me an error:
2013 Feb 18
2
error: Error in if (is.na(f0$objective)) { : argument is of length zero
Dear all,
I tried running the following syntax but it keeps running for about 4 hours
and then i got the following errors:
Error in if (is.na(f0$objective)) { : argument is of length zero
In addition: Warning message:
In is.na(f0$objective) :
is.na() applied to non-(list or vector) of type 'NULL'
Here is the syntax itself:
library('nloptr')
library('pracma')
#
2007 Sep 10
2
Are the error messages of ConstrOptim() consisten with each other?
Dear Friends.
I found something very puzzling with constOptim(). When I change the
parameters for ConstrOptim, the error messages do not seem to be
consistent with each other:
> constrOptim(c(0.5,0.3,0.5), f=fit.error, gr=fit.error.grr, ui=ui,ci=ci)
Error in constrOptim(c(0.5, 0.3, 0.5), f = fit.error, gr = fit.error.grr, :
initial value not feasible
> constrOptim(c(0.5,0.9,0.5),
2004 Jul 08
1
(PR#7070)
> version
_
platform i686-pc-linux-gnu
arch i686
os linux-gnu
system i686, linux-gnu
status
major 1
minor 7.1
year 2003
month 06
day 16
language R
Bug:
integrate(f,lower,upper,extra_args)
where
f <- function(x,extra_args)
{
body
}
integrate doesn't pass the extra arguments when calling f.
As a first check of this finding I integrated dnorm from
2004 Jan 15
1
Exactness of ppois
Hello,
by checking the precision of a convolution algorithm, we found the
following "inexactness":
We work with R Version 1.8.1 (2003-11-21) on Windows systems (NT, 2000,
XP).
Try the code:
## Kolmogorov distance between two methods to
## determine P(Poisson(lambda)<=x)
Kolm.dist <- function(lam, eps){
x <- seq(0,qpois(1-eps, lambda=lam), by=1)
max(abs(ppois(x,
2007 Aug 14
2
State Space Modelling
Hey all,
I am trying to work under a State Space form, but I didn't get the help
exactly.
Have anyone eles used this functions?
I was used to work with S-PLUS, but I have some codes I need to adpt.
Thanks alot,
Bernardo
[[alternative HTML version deleted]]
2012 Apr 07
1
Uniroot error
Dear All
I am trying to find a uniroot of a function within another function (see
example) but I am getting an error message (f()values at end points not of
opposite sign). I was wondering if you would be able to advise how redefine
my function so that I can find the solution. In short my first function
calculates the intergrale which is function of "t" , I need to find the
uniroot of
2000 Sep 20
1
integration in R?
I have the following problem.
inf
p= Int [dnorm(x-d) * pnorm(x) ^ (m-1)] dx
-inf
Given p and m, I want to find d. For example,
p m d
.9 2 1.81
Is there a way to solve this problem in R? Ideally I would have a
function with arguments p and m, and output d.
Thanks very much for any help.
Bill
-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
r-help mailing