similar to: Very slow assignments

Hi everybody! I'm creating an object of a S4 class that has two slots: ListExamples, which is a list, and idx, which is an integer (as the code below). Then, I read a data.frame file with 10000 (ten thousands) of lines and 10 columns, do some pre-processing and, basically, I store each line as an element of a list in the slot ListExamples of the S4 object. However, many operations after this

Hi User's, This might be a simple question but it is giving me a hard time as I am a new user. I installed R version 2.9.2 (2009-08-24) 1. I just copied a short script from Fox (2002) as a practice and wanted to save it as Rossi.R. The system saved it without complain but when I looked at using a windows explorer it is not *.R file but only Rossi. Why this is happening? 2. the script

Dear Germano, Thank you for your fast reply, In the above code, *MYData *is the actual data set. Do not we need to convert *MYData to *the dissimilarity matrix using *pam(as.dist(**MYData**), k = 10, diss = TRUE*)* code line?* *Regards.* On Thu, Aug 17, 2017 at 2:58 PM, Germano Rossi <germano.rossi at gmail.com> wrote: > try this > > MYdata <-

Dear Mr. Therneau, Mr. Fox, or to whoever, who has some time... I don't find a solution to use the "survfit" function (package: survival) for a defined pattern of covariates with a Cox-Model including a time dependent interaction term. Somehow the definition of my "newdata" argument seems to be erroneous. I already googled the problem, found many persons having the

hello I make a subroutine that give-me a (mathematical) function in string format. I would like transform this string into function ( R function ). thanks for any tips. cleber #e.g. fun_String = "-100*x1 + 0*x2 + 100*x3" fun <- function(x1,x2,x3){ return( ############ evaluation( fun_String ) ############ ) True String mathematical function :-( :-( > nomes [1]

Hi, R users, I'm trying to transform a matrix A into B (see below). Anyone knows how to do it in R? Thanks. Matrix A (zone to zone travel time) zone z1 z2 z3 z1 0 2.9 4.3 z2 2.9 0 2.5 z3 4.3 2.5 0 B: from to time z1 z1 0 z1 z2 2.9 z1 z3 4.3 z2 z1 2.9 z2 z2 0 z2 z3 2.5 z3 z1 4.3 z3 z2 2.5 z3 z3 0 The real matrix I have is much larger, with more than 2000 zones. But I think it should

Sorry, I never use pam. In the help, you can see that pam require a dataframe OR a dissimilarity matrix. If diss=FALSE then "euclidean" was use.So, I interpret that a matrix of dissimilarity is generated automatically. Problems may be in your data. Indeed pam(ruspini, 4)$diss write a dissimilaty matrix while pam(MYdata,10)$diss wite NULL 2017-08-17 16:03 GMT+02:00 Sema Atasever

I _think_ there is a problem with the license as well: Z3 is MIT, so clang would have to be released with Z3's license. On Tue, 12 Feb 2019, 09:24 Roman Lebedev via cfe-dev <cfe-dev at lists.llvm.org wrote: > On Tue, Feb 12, 2019 at 4:13 PM Paulo Matos via cfe-dev > <cfe-dev at lists.llvm.org> wrote: > > > > Hello, > > > > I am trying to run scan-build

Folks- I have developed a package which I am planning on posting to CRAN. I include examples for each of the 40 or so functions in the package. However, since the examples are non-trivial and the package is using MCMC simulation methods, it takes about 20 minutes to run the complete set of examples on a 2.8 Ghz windows PC. The R process reaches a high water mark of about 100 MB of memory as

I am currently attempting to split a long list of strings (let's call it "string.list") that is of the format: "1234567.z3.abcdef-gh.12" I have gotten it to: "1234567" "z3" "abcdef-gh" "12" by use of the strsplit function. This leaves me with each element of "string.list" having a split string of the above format. What

Dear R user, I want to estimate the parameter of ZETA or/and ZIPF distributions using R, given a series of integer values. Do you know a package (similar to MASS) or a function (similar to fitdistr) I can use to estimate the parameter of these distributions using MLE method? Otherwise do you know a function (which use MLE method to estimate distribution parameters) that allow me to specify a

Dear all, I tried to use "step" function to do model selection, but I got an error massage. What I don't understand is that data as data.frame worked well for my other programs, how come I cannot make it run this time. Could you please tell me how I can fix it? ***************************************************************************************************

I have the joint distribution of three discrete random variables z1, z2 and z3 which is captured by "z" and "prob" as described below. For example, the probability for z1=0.46667, z2=-1 and z3=-1 is 2.752e-13. Also, the probability adds up to 1. > head(z) z1 z2 z3 [1,] -0.46667 -1.0000 -1.0000 [2,] -0.33333 -0.9333 -0.9333 [3,] -0.20000 -0.8667 -0.8667

Hi, # TL;DR I've been building an application with and without the address sanitizer (with gcc 5.3 and clang 3.7.1) and I've observed that the application's behaviour changes (assertion hit/ not hit). I'm wondering if this could be a bug in address sanitizer or if the application I'm running is just buggy (e.g. doing bad things like relying on memory layout, etc.). I'm

Hello all R-users! In Jun-2005, I find the follow discussion about using of LME function ( in NLME library ) for fitting non-replicate data The thread: ANOVA vs REML approach to variance component estimation http://tolstoy.newcastle.edu.au/R/help/05/06/6498.html Someone expose the follow problem: # non-replicate data y <- c(2.2, -1.4, -0.5, -0.3, -2.1, 1.5, 1.3, -0.3, 0.5, -1.4,

I created a loadable optimization following the tutorial at http://llvm.org/docs/WritingAnLLVMPass.html. I want to use the Z3 library, installed in my system, in my optimization. When I include z3++.h (the name of the library) in the code and use its classes, it compiles well, but when I try to run it it says: > opt: symbol lookup error: /home/giacomo/llvm/Debug+Asserts/lib/Acsl.so: >

On Tue, 12 Feb 2019, 14:32 Paulo Matos <pmatos at linki.tools wrote: > > > On 12 February 2019 18:59:21 CET, Mikhail Ramalho < > mikhail.ramalho at gmail.com> wrote: > >I _think_ there is a problem with the license as well: Z3 is MIT, so > >clang > >would have to be released with Z3's license. > > I don't think that's a problem. You are not

Thank you Jim, I read the data as you suggested but I could not find K1 in col1. rbind(preval,mydat) Col1 Col2 col3 1 <NA> <NA> <NA> 2 X1 <NA> <NA> 3 Y1 <NA> <NA> 4 K2 <NA> <NA> 5 W1 <NA> <NA> 6 Z1 K1 K2 7 Z2 <NA> <NA> 8 Z3 X1 <NA> 9 Z4 Y1 W1 On Sat, Feb 24, 2018 at 6:18 PM, Jim

Hi, If I have an R object UUU, where the second element is U2, based on "g" column of my.table my.table of UUU is: mmm ggg gindex map Info aaa123 U1 1 1 1 aaa124 U1 1 2 1 bbb1378 U2 2 1 1 bbb8888 U2 2 2 0 bbb1389 U2 2 3

Hello all R-users _question 1_ I need to make a statistical model and respective ANOVA table but I get distinct results for the T-test (in summary(lm.object) function) and the F-test (in anova(lm.object) ) shouldn't this two approach give me the same result, i.e to indicate the same significants terms in both tests??????? obs. The system has two restrictions: 1) sum( x_i ) = 1 2) sum(