similar to: reshaping data

My box plot below is drawing its upper whisker all the way to the last point, instead of showing the point as an outlier. Am I misunderstanding, or is it a bug? Help(boxplot) states for the parameter ?range? that ?this determines how far the plot whiskers extend out from the box. If range is positive, the whiskers extend to the most extreme data point which is no more than range times the

Dear R-users, I recently began using the ggplot2 package and I am still in the process of getting used to it. My goal would be to plot on the same grid a number of curves derived from two distinct datasets. The first dataset (called molten.data) looks like this : Column names : Perc, Week, Weight P10 21 333.3554 P90 21 486.0480 P10 22 452.6347 P90 22 563.8263 P10 23 575.0960 P90

Hi all: I'm struggling with getting my data re-formatted using functions in reshape/reshape2 to get from: 1957 0.862500000 1958 0.750000000 1959 0.300000000 1960 0.287500000 1963 0.675000000 1964 0.937500000 1965 0.025000000 1966 0.387500000 1969 0.087500000 1970 0.275000000 1973 0.500000000 1974 0.362500000 1976 0.925000000 1978 0.712500000 1979 0.337500000 1980 0.700000000 1981 0.425000000

Any of you guys ever seen an issue with Xen 4.4 were xm cannot create a guest because of what looks like an issue allocating memory even though xm info shows like 5x the amount of free memory needed? We are still unfortunately still using xm... it's on my list, i know.. We've had this happen on a couple hosts now. Only way to resolve seams to be rebooting the host. I'm going to

Dear R users, [in case the format of email is changed or you dont finf it easy to understand, i have attached a text file of my question] i have the data in the following format and i want to convert it in the format given at the end. Ta ans Sa are the names of certain cities. there are 69 cities in my data. column 1 is representing station name (i am writing the data of only two cities for

Assume that I have the dataframe "data1", which is listed at the end of this message. I want count the number of lines that each person has for each year. For example, the person with ID=213 has 15 entries (NinYear) for 1953. The following bit of code calculates NinYear: for (i in 1:length(data1$ID)) { data1$NinYear[i] <- length(data1[data1$Year==data1$Year[i] &

The reason it doesn't work easily with reshape/reshape2 is that the order of the rows is not determined. Your answer could be 1957 1958 ... 1985 1986 0.8625000 0.7500000 ... 0.7307692 0.23750000 0.0733945 0.6435644 ... NA 0.05769231 0.5096154 NA ... NA 0.65137615 or 1957 1958 ... 1985 1986 0.0733945 0.6435644 ... NA

Hi Tom, Or perhaps: #assume the data frame is named "tadf" library(prettyR) stretch_df(tadf,1,2) Jim On Thu, Jul 6, 2017 at 6:50 AM, Ista Zahn <istazahn at gmail.com> wrote: > The reason it doesn't work easily with reshape/reshape2 is that the > order of the rows is not determined. Your answer could be > > 1957 1958 ... 1985 1986 >

We're using the stock configuration, the dom0 is limited to 1024MB via grub. ------ Original Message ------ From: "Pasi K?rkk?inen" <pasik at iki.fi> To: "Shaun Reitan" <shaun.reitan at ndchost.com>; "Discussion about the virtualization on CentOS" <centos-virt at centos.org> Sent: 6/26/2016 9:30:57 AM Subject: Re: [CentOS-virt] Cannot

Part 1: I want to plot the CO2 concentration vs. year, but extending the x-axis using the xlim parameter to include the year 2006 (x axis range of values are from -41210 to 0), and adjusting the ylim parameter to go up to 400 when the range of y axis values are from 150 to 300. How do I do this? Using axis function? I am confused about the syntax here. Part 2: I also want to use the points()

I have two collections of dates and I want to figure out what dates they have in common. This is not giving me what I want (I don't know what it is giving me). What is the best way to do this? Tom > data1 [1] "1948-02-24 EST" "1949-04-12 EST" "1950-05-29 EDT" "1951-05-21 EDT" [5] "1951-12-20 EST" "1953-01-22 EST"

Hi all, I need your insight. I've been testing Dovecot on an AIX 5.2 system. Compiled and running fine. We have some users on an AIX 5.1 system, so I'm working on installing it there, so we can do further testing. I'm using Dovecot 1.0 RC15 with OpenSSL 9.0.7e, configured to use port 10143 (imap) and 10993 (imaps). The error I'm seeing in the log is: dovecot: Nov 28

Hello everyone, Merging two dataframes should be easy. However when I try to merge, R doesn't recognize identical values, even if I am doing it by values that have no decimals. willclayong: vs30 LON LAT Net X wills.cat wills.vs30 clahan.cat clahanvs30 PolyID.wills PolyID.clahan tif.cat STA ELEVATION tif.vs30 1 338.539 -3849590 4319319 <NA> 2 D 301

Good Afternoon, I am relatively new to R and have been trying to figure out how to estimate regression coefficients using the MLE method. Some background: I am trying to examine scenarios in which certain estimators might be preferred to others, starting with MLE. I understand that MLE will (should) produce the same results as Ordinary Least Squares if the assumption of normality holds. That

This does not use reshape/reshape2, but it is pretty straightforward. Assuming X is your example data: > Y <- split(X[, 2], X[, 1]) > vals <- sapply(Y, length) > pad <- max(vals) - vals > Y2 <- lapply(seq_along(Y), function(x) c(Y[[x]], rep(NA, pad[x]))) > names(Y2) <- names(Y) > X2 <- do.call(cbind, Y2) > X2[, 1:6] 1957 1958 1959

Dear Rui and UseRs,[a text file has also been attached, in case the format of my email is difficult to get]I am extremely sorry that I am bothering you once again, but I?ll have to get to the bottom of it. The following command sp <- lapply(split(agg, agg$st), function(x) x[order(x$year, x$month), ]) gave me an output with monthly mean of population(as under). i am not able to apply

Hi everybody, If I've a data frame like this: dataframe a X0 X2 X4 X6 X8 X10 X12 X14 X16 1957 0 0 0 0 0 0 0 0 0 1958 0 0 0 0 0 0 0 0 0 1959 831 0 0 0 0 0 0 0 0 1960 544 282 0 0 0 0 0 0 0 1961 446 365 0 0 0 0 0 0 0 1962 442 473 0 0 0 0 0 0 0 1963 595 468 0 0 0 0 0 0 0 1964

Dear R-users, I have a complex line by xy-values (ordered by z). And I would like to get interpolated y-values on the positions of x = 0:600. How do I get the correct points? x=c(790,790,790,790,790,786,783,778,778,766,763,761,761,761,715,628,521,350,160,134,134,129,108,101,93,111,161,249,288,243,139,45,7)

I have some data whose date column consists of two types of date entries: (a) year-only entries (eg "1983") and (b) full date info (eg September 12, 1962). Here's what the non-standard date info looks like: > mode(non.standard.dates) [1] "numeric" > head(non.standard.dates) [1] July 15, 1925 February 13, 1923 July 10, 1988 February 24, 1931 [5] 1952

Hi, again i am stuck in my presentation, and i have never learn R before in my life but need this to be done, so please help me out for a favour: http://www.nabble.com/file/p20333155/kew.dat kew.dat run this in R and these comes up: Month Year Rain 1 Jan 1900 74.400000 2 Feb 1900 80.500000 3 Mar 1900 23.600000 4 Apr 1900 23.600000 5 May 1900 25.100000 6