similar to: previous monday date

Hello, There has to be a more R'ish way to do this. I have two matrices, one has the values I want, but I want to NA some of them. The other matrix has binary values that tell me if I want to NA the values in the other matrix. I produce a third matrix based on this. I've also tried apply() passing in c(1,2) for rows and columns with no success yet. Example (this works, but I'm

Hello all, I'm hoping to convert a decimal value for week of the year back to a date object. Eg: strptime(paste(2010,1:52,sep=" "),format="%Y %W") I expected (hoped?) this would give me the date for Monday of each week. Instead, it's giving me 52 values of today's date. Where am I erring? Thanks Michael _______________________________________________________

Hello, First time posting to this mail list. I'd like to use R in the most efficient way. I'm accomplishing what I want, but feel there is a more R'ish way to do it. Just learning R. *My goal: get ranks of value across rows with row names and column names intact.* I'm guessing one of the [?]apply functions will do what I need, but I couldn't sort out which one (after a lot

Hello, What is the best way to turn a matrix into a list removing NaN's? I'm new to R... Start: > mt = matrix(c(1,4,NaN,5,3,6),2,3) > mt [,1] [,2] [,3] [1,] 1 NaN 3 [2,] 4 5 6 Desired result: > lst [[1]] [1] 1 3 [[2]] [1] 4 5 6 Thanks! Ben [[alternative HTML version deleted]]

Hello, Does anyone know how to change the Tinn-R editor background color? White is rough on the eyes... Thanks, Ben [[alternative HTML version deleted]]

Can someone show me how to modify one (R.oo) class's object inside another (R.oo) class's method? Is that possible with the R.oo package? A quick example or reference to an example would be outstanding... Thanks, Ben [[alternative HTML version deleted]]

Hello, Does anyone know how to convert this: > msg [1] "a" [2] "b" [3] "c" To: > msg "a b c" In other words, I need to convert a character vector to a single string with carriage returns for each row. Functionally, I'm attempting to send an email of a character vector in a way that is readable in the email body. I can only input one

Hello, I have a bunch of data files all with "dbs" file extensions. They are generated via a SQL query from another program and source. Does anyone know (or have ideas) how to get the data from a dbs file type into R (or into some other format that can imported to R)? I've searched online for 4 hours now... Thanks! Ben [[alternative HTML version deleted]]

Hello, I'm trying to get the count of values in each row that are above and below quantile thresholds. Thanks! Example: > x = matrix(1:30,5,6) > x [,1] [,2] [,3] [,4] [,5] [,6] [1,] 1 6 11 16 21 26 [2,] 2 7 12 17 22 27 [3,] 3 8 13 18 23 28 [4,] 4 9 14 19 24 29 [5,] 5 10 15 20 25 30 > qtl = t(apply(x, 1,

Hello, I'm looking to get the values, row names and column names of the largest and smallest values in a matrix. Example (except is does not include the names): > x <- swiss$Education[1:25] > dat = matrix(x,5,5) > colnames(dat) = c('a','b','c','d','c') > rownames(dat) = c('z','y','x','w','v') >

Hello, I'd like to 'do work' on data members upon construction (i.e. without implementing it in a get method). Is this the best way to create data member 'z' upon construction? I'm thinking if .z=paste(x,y) below gets more complex I'll run into issues. setConstructorS3("MyClass", function(x=NA,y=NA,...) { this <- extend(Object(), "MyClass",

Hello, Using the R.oo package, how do I throw an error if a field is not present when the user of the class creates the object? Using the example in the R.oo package: setConstructorS3("Person", function(name, age) { if (missing(name)) name <- NA; if (missing(age)) age <- NA; extend(Object(), "Person", .name=name, .age=age ) }) [rest of class methods

Hello, which.max() only returns one index value, the one for the maximum value. If I want the two index values for the two largest values, is this a decent solution, or is there a nicer/better R'ish way? max2 <-function(v) { m=which.max(v) v[m] = -v[m] m2=which.max(v) result=c(m, m2) result } Seems to work ok. Thanks, Esmail

Hello, I have two date strings, say "1972-06-30" and "2012-01-31", and I'd like to get every quarter period end date between those dates? Does anyone know how to do this? Speed is important... Here is a small sample: Two dates: "2007-01-31" "2012-01-31" And I'd like to get this: [1] "2007-03-31" "2007-06-30"

Hello, I've posted something similar under a different subject and never received a solution. Trying again with (hopefully) a better description. Objective: Send a matrix of string data in an email message. The message must have authentication and be sent via an R script. I'm almost there! Here is where I am at: I collect long error message lines in 'errs', which is a matrix.

Hello, I'm pretty new to R. Basically, how do I speed up the for loop below. Or better yet, get rid of the for loop all together. objective: plot two data sets column against column by index. These data sets have alot NA's. Some columns are all NA's. I need the plots to overlay. I don't like the plots in matplot(). Needs to be much faster than the code below... #simple sample

If someone is able, can you tell me if there is a better way to do this? More specifically, do I have to rewrite all of the data members stuff and extend stuff of parent class in the child class? See below. Thanks in advance! Example 1: setConstructorS3("ClassA", function(A,x) { if(missing(A))A=15; if(missing(x))x=NA; extend(Object(), "ClassA", .size = A, .x=x

Hello I am new to R and I need to convert some dates (numeric format by matlab) to actual dates in R. For instance, Matlab -> 730456 -> >> datestr(730456) ans = 02-Dec-1999 R - > library(zoo) > as.Date(730456) [1] "3969-12-03" I don't not mind the output format but it needs to be right. Many thanks Ed

Hello, I have some "stupid" problems managing "date" data. I have a colomn "date", which I converted from a character representation: for example: a="26/02/06" date=strptime(a,format="%d/%m/%y") For one part of the analysis, I'm interested only in the month and the year, so I did: m.y=strftime(date,format="%m/%y") This returns me

When I use the code as.Date(0) the I get : "1970-01-01". My question is why it is like that? help file on as.Date seems to give no light on that. Can anyone clarify me?   Regards, Send instant messages to your online friends http://uk.messenger.yahoo.com [[alternative HTML version deleted]]