similar to: Obtaining variable's names from a list of variables

Hello, It might be an easy question but if you have many variables to fit in the lm function, how do you take all without specifying var1+var2+...+var2100 in the terms parameter in response ~ terms? Cheers, Carol

Hi Can someone help me with this? How can I apply a function to a list of variables. something like this listvar=list("Monday","Tuesday","Wednesday") func=function(x){x[which(x<=10)]=NA} lapply(listvar, func) were Monday=[213,56,345,33,34,678,444] Tuesday=[213,56,345,33,34,678,444] ... in my case I have a neverending list of vectors. Thanks!

Dear list   I have 5 markers that can be used to detect an infection in combination. Could you please advise me how to use functions in ROCR/ other package to produce the ROC curve for a combination of markers?   I have used the following to get ROC statistics for each marker. pred <- prediction(y$marker1, y$infectn) perf <-performance(pred,"tpr","fpr")

Hi all, I have two vectors (columns) called "efinal" and "efinal 2". I want to plot them on the same plot and "draw" a shaded area beween the two lines using function polygon I have tried all but I don ?t understand the polygon area, can you help me with examples? plot(efinal,type="l",ylim=range(min(efinal2),

I noticed that the text() command adds text to a plot. Is there a way to either make the plot blank or add text to a "blank sheet". I would like to "plot" a page that contains just text, no plot lines, labels, etc. Suggestions? Kevin [[alternative HTML version deleted]]

Hey all, In order to test if a marker is a risk factor, I built two models (using cox proportional hazard model). One model included this marker, and the other is not. Then, I use R package risksetROC to test how much predictive value did the marker add to this model. I get two C statistics by analyzing the linear predictors of the two models into this package. The qustion is How to test if two

Is there a way to convince R to create a character vector without using the quotes? This works ex1 <- c("first","second") but when I try this it doesn't ext <- as.character(c(first,second)) it complains. I have many variables to put into character vectors so dispensing with the quotes would be useful. Thanks Jim =============================== Dr. Jim Maas

Hi All, I am trying to lable the y-axis on my scatterplot with the following: "Soil moisture content (m3m-3)" I am using the following coding for plotting the graph: plot(soilmoisture~gradientlevel, xlab="Levels of droughting gradient", ylab="Soil moisture content (m3m-3)", bty="l", font.main="2", pch=16, las=1, cex.lab="1.13") I have

Hi, i want to construct a data set similar to "AirPassengers". Its attributes are following. > attributes(AirPassengers) $tsp [1] 1949.000 1960.917 12.000 $class [1] "ts" How Can I construct a data set similar to it having same class and attributes. Thanks -- Amar Kumar Nandan ?:nandan.amar at gmail.com http://aknandan.co.nr

Hi All, I am writing a function to predict values based on a model. It works fine as long as the formula just uses regular variable names. I am having a problem when the variables are wrapped with a function call. For example: m <- lm(mpg ~ factor(cyl), data = mtcars) ## I get the column names using as.character(attr(terms(m), "variables"))[-1L] ## which gives the same column

Dear List members, I really, like the feature that one can call R functions with mathematical expressions, e.g. curve(x^2, 0, 1) I wonder, how I can construct in a simple way a function like mycurve = function (expr) {...} such that that a call mycurve(x^2) has the same effect as the call curve(x^2, -100,100) Below is some code that works, but it seems much to complicated: it first

Hello Everyone I have the data long format and I want to draw the contour plot with it x1 x2 x3 0 1 2 0 2 1 0 3 5 1 1 4 1 2 2 1 3 3 when I am using contour(x1,x2,x3,col=heat.colors) or fill.contour its giving me an error that increasing x and y expected So please tell me what is the right function to draw contour when the data is not ordered and you cant order

I wish place the following axis label in such a manner that some of the text is plain and the scientific name is in italics (i.e. a mixture of two font types) Using plot: mtext("Total Landings of Pecten maximus (tonnes)",font,=3, side=2, line=3) makes everything italic, but how do I apply the font change to only "Pecten maximus"? Rgds Phil

I've seen a number of issues with the loading of workspaces discussed previously, but here's another one... I simply can't load any saved workspace at all... Here's an example, starting with an empty workspace and creating a single variable "a". > a<-1:5 > save.image("a.Rdata") > rm(a) > load("a.Rdata") Error in function ()  : unused

Hi all, I would like to replace the for loop in the code below with a function to improve the speed and to make the script more efficient. The loop creates a vector of integers (x) with the probability of f for each integer. The length of f is variable, but sums to 1. I tried to use a function with optional arguments which did not work. Here is the code: f <- data.matrix(c(0.5,0.15,0.35))

Hello! I would like to do some tables for several variables and I would like to write a loop that does the table for each variable. I should also point out that my data set has several missing observations and sometimes the observations that are missing are not the same for all my variables. What I would like to do: table(StoreData$CompanyID, !is.na(StoreData$P2))

Dear users, 1. Is there a way to create a movie file to play a sequence of single frames (e.g. plots) at a specified time delay between frames? 2. If making a movie file is not possible, then how can I incorporate in a loop some delay between the frames to be plotted so I can change the playing speed? Sorry if this questions was already in the forum, but I couldn?t find it. Thanks in advance

Hello Eik: Thanks. I do not need to sample. Essentially, I have a do loop which produces 24 vectors of length of some length (say k=300) and 24 matrices of 300x300. Then, I simply need to? take the averages of these 24 vectors and matrices: x=(x1+x2+...+x24)/k y=(y1+y2+...+y24)/k I am just looking for ways to do this in a do loop, which requires initialization (to 0's) of x and y. My

Hi, I have a silly question regarding the usage of two commands: read.table and gregexpr： For read.table, if I read a matrix and set header = T, I found that all the dash ("-") becomes dots (".") A = read.table("Matrix.txt", sep = "\t", header = F) A[1,1] # "A-B-C-D". A = read.table("Matrix.txt", sep = "\t", header = T)

I have a dataset and a list of labels. I simply want to apply the labels to the variables, all at once. The only way I was able to do it was using a loop:     for (i in 1:length(data))  label(data[,i]) <- data.labels[i] I'd like to find the non-loop way to do it, using apply or the like... Any help appreciated. [[alternative HTML version deleted]]