similar to: Missing datasets (2.13.1)

Thank you for your guys reply for my previous question. But I got one more question about the boxplot. With the code in the R-help: boxplot(len ~ dose, data = ToothGrowth, boxwex = 0.25, at = 1:3 - 0.2, subset = supp == "VC", col = "yellow", main = "Guinea Pigs' Tooth Growth", xlab = "Vitamin C dose mg", ylab =

Hi all, I I need to manipulate the x axis in a stripchart. I will use one of the data sets included in R to explain what I need to do. attach(ToothGrowth) stripchart(len[supp=='VC']~dose[supp=='VC'], vertical=TRUE, group.names=c('A','A','A')) stripchart(len[supp=='OJ']~dose[supp=='OJ'], add=TRUE, vertical=TRUE, at=c(1:3)+.1,

Dear List, ? I am creating a boxplot with two subsets, very similar to the example by Roger Bivand at ?boxplot (reproduced below).? I am trying to change the labels on the x-axis to have one number to cover both subsets.? I can do this in other plots by using axis=FALSE followed by a separate axis() command.? I have also tried variations in the names= argument but can't get it to work.?

hi List and Manuel, I have encounter the following problem with the function "lineplot.CI".? I'm running R 2.10.1, sciplot 1.0-7 on Win XP.? It seems like it's a scoping issue, but I couldn't figure it out. Thanks! ...Tao > lineplot.CI(x.factor = dose, response = len, data = ToothGrowth)??? ## fine > lineplot.CI(x.factor = dose, response = len, data = ToothGrowth,

Hi folks, Win7 64bit R 1.12.0 I run following command on R:- > ToothGrowth > attach(ToothGrowth) > plot(dose,len) > matrics=lm(len~dose) > abline(metrics) Error in int_abline(a = a, b = b, h = h, v = v, untf = untf, ...) : plot.new has not been called yet Only a grey diagram is displayed without content > plot(abline(metrics)) Error in int_abline(a = a, b = b, h = h, v

I'm trying to plot a scatterplot of two variables using pch to plot different characters based on a third factor. Here is my example > data("ToothGrowth") > attach(ToothGrowth) > levels(supp) [1] "OJ" "VC" > plot(len ~ dose,pch=as.numeric(supp)) > legend(locator(1),pch=as.numeric(supp),legend=levels(supp)) The command as.numeric(supp) returns 2 2

Hi folks Run; > ToothGrowth > attach(ToothGrowth) > toothgrowth=lm(len~dose) adding abline: > abline(toothgrowth) I got it done adding single abline. How to add more ablines on the same diagram? I found following thread, applying "mapply" command; Plotting multiple ablines http://www.mail-archive.com/r-help@r-project.org/msg51543.html mapply(abline, (converge$kY +

Dear list, How can I add the mean and standard deviation to each of the boxplots using the example provided in the boxplot function? boxplot(len ~ dose, data = ToothGrowth, boxwex = 0.25, at = 1:3 - 0.2, subset = supp == "VC", col = "yellow", main = "Guinea Pigs' Tooth Growth", xlab = "Vitamin C dose mg",

Hi to all, Does anybody knows why this is giving an error? data(ToothGrowth) # Two-way design with options bargraph.CI(dose, len, group = supp, data = ToothGrowth, xlab = "Dose", ylab = "Growth", cex.lab = 1.5, x.leg = 1, col = "black", angle = 45, cex.names = 1.25, density = c(0,20), legend = TRUE) Error in dn.call[[1]] :

Hi, I followed the following sequence of commands after installing 'XGobi': >library(xgobi); >data(ToothGrowth); >xgobi(ToothGrowth); I got the following warning message: C:/R13 1.0/rw1030/library/xgobi/scripts/xgobi.bat -vtitle 'ToothGrowth' -std mmx C:/DOCUME~1/h1452992/LOCALS 1/Temp/xgobi-TthGr5705 Warning message: argument `pkg' is deprecated. Use

Dear all I have written a function to perform a very simple but useful task which I do regularly. It is designed to show how many values are missing from each variable in a data.frame. In its current form it works but is slow because I have used several loops to achieve this simple task. Can anyone see a more efficient way to get the same results? Or is there existing function which does

Hi, sorry for bothering your guys. I will trying to make some nice graph using boxplot. when I check the help file of boxplot, there is a sample code as: boxplot(len ~ dose, data = ToothGrowth, add = TRUE, boxwex = 0.25, at = 1:3 + 0.2, subset = supp == "OJ", col = "orange") legend(2, 9, c("Ascorbic acid", "Orange juice"),

Hello, When using bargraph.CI in package sciplot can the bars for each group be different colors? How do I select the color for each group? When I use this instead of the default (SD vs SE): bargraph.CI(x.factor = dose, response = len, data = ToothGrowth, ci.fun= function(x) c(mean(x)-sd(x), mean(x) + sd(x)) ) Am I getting 95% CI bars? Thank you kindly, Michael Just

Is it possible to add standard error bars to the means on interaction plots? Thanks Murray -- Murray Pung Statistician, Datapharm Australia Pty Ltd 0404 273 283 [[alternative HTML version deleted]]

This relates to a message from Christophe Pallier to r-help some time ago. Like myself, he finds aggregate very useful, but the interface a little cumbersome. I've implemented a more compact formula interface, found at the bottom of this message: data(ToothGrowth) # I used to aggregate like this: aggregate(list(len=ToothGrowth$len),

termplot() does not carry subsetting over to carriers that are in the environment but not in the data frame. This generates a "subscript out of bounds" error. > data(ToothGrowth) > logdose <- log(ToothGrowth$dose) > tooth.lm <- lm(len ~ logdose, data=ToothGrowth) > termplot(tooth.lm) ## Works fine > toothVC2.lm <- lm(len ~ poly(dose,2),

Here's the latest batch of words to get shipped out to Allison Smith. Please submit reasonably small changes to me by tomorrow 10:00 AM Eastern time, and I'll add them. As usual, donations to what will be a ~$110 USD expense would be appreciated, as I am paying for this round out of my pocket. Please send to paypal address "jtodd@loligo.com". I did not include all

Hi there, I am a beginner. I would like to change the error bars in the bargraph.CI function from the default (se) to (sd). The help file says ci.fun= function(x) c(fun(x)-se(x), fun(x)+se(x)) Is there a simple way of telling the function what (x) precisely is - I already define in in the of the bargraph.CI function and assume that is should be able to use that information. cheers, Herwig --

Hi All, As a follow-on from the mail below, it is possible to have boxplots based on means and variance for more than one input, i.e., bxp(input1,input2,....) Thanks in Advance, Dermot ******** Previous Mail on this subject *********** >I have a couple more questions about boxplots. In the books I've read on >statistics (I'm not a statistics expert but just a poor engineer

Hello, applying a function to a list of variables I face the following problem: Let's say I want to compute tables for several variables. I could write a command for every single table, like bravo<-c(1,1,2,3,5,5,5,);charly<-c(7,7,4,4,2,1) table(bravo); table(charly) > table(bravo); table(charly) bravo 1 2 3 5 2 1 1 3 charly 1 2 4 7 1 1 2 2 The results are two tables with the